data_source
stringclasses 1
value | prompt
stringlengths 271
305
| ability
stringclasses 1
value | reward_model
dict | extra_info
dict |
|---|---|---|---|---|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7437 - 0x9e69) - (0x32db * 0xd4a2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x2a3db4c8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7437 - 0x9e69) - (0x32db * 0xd4a2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 500
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf970 >> 0x1) - (0x928c + 0x1322))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x28f6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf970 >> 0x1) - (0x928c + 0x1322))",
"source_dataset": "bitwise_arithmetic",
"source_index": 501
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x90a8 >> 0x0) * (0xfb79 + 0x6609))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc7c11d50",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x90a8 >> 0x0) * (0xfb79 + 0x6609))",
"source_dataset": "bitwise_arithmetic",
"source_index": 502
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x632f + 0x5c44) + (0x8991 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1043b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x632f + 0x5c44) + (0x8991 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 503
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbf89 + 0x5f69) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x23de4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbf89 + 0x5f69) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 504
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x350f << 0x2) * (0xe464 << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xbd585770",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x350f << 0x2) * (0xe464 << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 505
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc23d - 0x1527) + (0xf7f7 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x12911",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc23d - 0x1527) + (0xf7f7 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 506
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7d83 >> 0x2) - (0xdd74 + 0xd354))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x19168",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7d83 >> 0x2) - (0xdd74 + 0xd354))",
"source_dataset": "bitwise_arithmetic",
"source_index": 507
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xafe * 0x3f4f) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2b7e662",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xafe * 0x3f4f) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 508
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5fad - 0x6907) - (0xfe7e >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x107d8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5fad - 0x6907) - (0xfe7e >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 509
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb23e << 0x1) + (0x8f6c >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1f3e8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb23e << 0x1) + (0x8f6c >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 510
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x69ef + 0x639d) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x19b18",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x69ef + 0x639d) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 511
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x611a - 0xe2fd) - (0x43d2 + 0xb712))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x17cc7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x611a - 0xe2fd) - (0x43d2 + 0xb712))",
"source_dataset": "bitwise_arithmetic",
"source_index": 512
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2845 + 0x4263) - (0xb810 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3ca4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2845 + 0x4263) - (0xb810 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 513
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb676 >> 0x3) - (0xa82 * 0xdbc0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x90500b2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb676 >> 0x3) - (0xa82 * 0xdbc0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 514
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd93c >> 0x2) + (0x991d - 0xabdc))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2390",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd93c >> 0x2) + (0x991d - 0xabdc))",
"source_dataset": "bitwise_arithmetic",
"source_index": 515
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb301 >> 0x1) * (0x981d + 0xf2a6))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8a032c80",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb301 >> 0x1) * (0x981d + 0xf2a6))",
"source_dataset": "bitwise_arithmetic",
"source_index": 516
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5de1 * 0x8365) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x605e598a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5de1 * 0x8365) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 517
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1f8 << 0x3) + (0xe4b5 - 0xee4d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x628",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1f8 << 0x3) + (0xe4b5 - 0xee4d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 518
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3400 * 0x34e0) - (0xc22a * 0x894b))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x5d63dc4e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3400 * 0x34e0) - (0xc22a * 0x894b))",
"source_dataset": "bitwise_arithmetic",
"source_index": 519
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb814 + 0x628e) + (0x5ccb - 0x6d2c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x10a41",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb814 + 0x628e) + (0x5ccb - 0x6d2c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 520
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf30f - 0xd265) * (0x5ea7 * 0x3e53))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2f0b1a94c92",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf30f - 0xd265) * (0x5ea7 * 0x3e53))",
"source_dataset": "bitwise_arithmetic",
"source_index": 521
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4fc8 + 0x6fde) - (0x2450 * 0x2e12))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x6882dfa",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4fc8 + 0x6fde) - (0x2450 * 0x2e12))",
"source_dataset": "bitwise_arithmetic",
"source_index": 522
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc316 << 0x3) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1862c0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc316 << 0x3) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 523
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe9a7 * 0xfdea) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x73dfced30",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe9a7 * 0xfdea) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 524
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4976 >> 0x3) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x24b8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4976 >> 0x3) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 525
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xff24 << 0x2) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7f92",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xff24 << 0x2) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 526
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x55e3 + 0x4487) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x134d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x55e3 + 0x4487) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 527
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xff37 + 0xd061) + (0x98f2 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x21c11",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xff37 + 0xd061) + (0x98f2 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 528
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe2e << 0x1) + (0x88de - 0xfb3f))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x5605",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe2e << 0x1) + (0x88de - 0xfb3f))",
"source_dataset": "bitwise_arithmetic",
"source_index": 529
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9d61 * 0xd770) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x108e2a2e0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9d61 * 0xd770) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 530
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6519 + 0x8d6d) * (0xf342 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1cce77118",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6519 + 0x8d6d) * (0xf342 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 531
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3c5f * 0x6e9f) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd0b2880",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3c5f * 0x6e9f) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 532
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6ac2 + 0x8000) + (0xabdd >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x115b9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6ac2 + 0x8000) + (0xabdd >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 533
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x182 - 0x98cb) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x4ba5",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x182 - 0x98cb) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 534
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe218 << 0x3) + (0xb250 - 0xd1d6))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6f13a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe218 << 0x3) + (0xb250 - 0xd1d6))",
"source_dataset": "bitwise_arithmetic",
"source_index": 535
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5c62 << 0x2) - (0xa508 + 0x2b33))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa14d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5c62 << 0x2) - (0xa508 + 0x2b33))",
"source_dataset": "bitwise_arithmetic",
"source_index": 536
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa76b - 0x564a) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x28908",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa76b - 0x564a) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 537
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf8c4 + 0xb00f) * (0x704a - 0xee53))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xd126c96b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf8c4 + 0xb00f) * (0x704a - 0xee53))",
"source_dataset": "bitwise_arithmetic",
"source_index": 538
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb939 << 0x3) - (0x8988 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5a766",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb939 << 0x3) - (0x8988 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 539
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf19c << 0x1) + (0x871c >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x226c6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf19c << 0x1) + (0x871c >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 540
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x91ef - 0xa4f9) + (0xc66c - 0xa686))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xcdc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x91ef - 0xa4f9) + (0xc66c - 0xa686))",
"source_dataset": "bitwise_arithmetic",
"source_index": 541
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4cdc << 0x0) * (0x963c - 0xa061))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x30bb3cc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4cdc << 0x0) * (0x963c - 0xa061))",
"source_dataset": "bitwise_arithmetic",
"source_index": 542
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5fd3 * 0x8830) - (0x3893 << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x32f9d6fd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5fd3 * 0x8830) - (0x3893 << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 543
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5f4c >> 0x3) + (0x65f7 + 0x83ce))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf5ae",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5f4c >> 0x3) + (0x65f7 + 0x83ce))",
"source_dataset": "bitwise_arithmetic",
"source_index": 544
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x820f >> 0x3) * (0xe184 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1ca30508",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x820f >> 0x3) * (0xe184 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 545
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe926 + 0xf055) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1d97b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe926 + 0xf055) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 546
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3bdb << 0x3) - (0xae2c + 0xdf40))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x516c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3bdb << 0x3) - (0xae2c + 0xdf40))",
"source_dataset": "bitwise_arithmetic",
"source_index": 547
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6d78 << 0x2) + (0xead3 >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1d33a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6d78 << 0x2) + (0xead3 >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 548
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x157c - 0x2e5c) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x638",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x157c - 0x2e5c) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 549
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe846 - 0xb783) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x30c3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe846 - 0xb783) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 550
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xacfe + 0xf8bf) * (0xb8e9 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x984fd8828",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xacfe + 0xf8bf) * (0xb8e9 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 551
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xcc6 + 0xbefc) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xcbc2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xcc6 + 0xbefc) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 552
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbc39 >> 0x0) * (0x7cad >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb74e42d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbc39 >> 0x0) * (0x7cad >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 553
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xad21 - 0x3804) - (0x3bc0 << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x395d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xad21 - 0x3804) - (0x3bc0 << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 554
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8a6a + 0x65d7) - (0x6807 * 0x7930))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x313de00f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8a6a + 0x65d7) - (0x6807 * 0x7930))",
"source_dataset": "bitwise_arithmetic",
"source_index": 555
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8575 << 0x0) + (0x5db8 * 0xd196))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4cbaa745",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8575 << 0x0) + (0x5db8 * 0xd196))",
"source_dataset": "bitwise_arithmetic",
"source_index": 556
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe2dd << 0x2) * (0xe991 * 0x1ad6))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x56ca541f3e78",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe2dd << 0x2) * (0xe991 * 0x1ad6))",
"source_dataset": "bitwise_arithmetic",
"source_index": 557
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf603 - 0x9b69) * (0x682b << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x126ee3ef0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf603 - 0x9b69) * (0x682b << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 558
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1ce8 + 0x7878) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2558",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1ce8 + 0x7878) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 559
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7759 * 0xb9c5) * (0xff7e << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x566f2db27086",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7759 * 0xb9c5) * (0xff7e << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 560
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x94f6 + 0xa972) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x27cd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x94f6 + 0xa972) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 561
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd0b6 * 0xb0da) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x48176d7e0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd0b6 * 0xb0da) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 562
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7fb5 >> 0x0) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7fb5",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7fb5 >> 0x0) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 563
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa9ee << 0x1) + (0x2ae1 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1a99e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa9ee << 0x1) + (0x2ae1 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 564
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe783 + 0xd159) + (0x3f73 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1d895",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe783 + 0xd159) + (0x3f73 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 565
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb005 << 0x3) - (0x544d - 0xd7c1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6039c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb005 << 0x3) - (0x544d - 0xd7c1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 566
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3cc0 - 0xf141) * (0xc02c * 0x421))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x22f76913bac",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3cc0 - 0xf141) * (0xc02c * 0x421))",
"source_dataset": "bitwise_arithmetic",
"source_index": 567
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5d1d * 0x5180) * (0xdc49 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xcc0f3bb5e00",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5d1d * 0x5180) * (0xdc49 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 568
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8fbc * 0xb27) * (0x7e20 - 0x9069))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x727ea6b7c4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8fbc * 0xb27) * (0x7e20 - 0x9069))",
"source_dataset": "bitwise_arithmetic",
"source_index": 569
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9b90 >> 0x1) - (0xcfd6 * 0x5090))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x41677a98",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9b90 >> 0x1) - (0xcfd6 * 0x5090))",
"source_dataset": "bitwise_arithmetic",
"source_index": 570
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf7f4 << 0x3) + (0x93e5 + 0xc059))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x913de",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf7f4 << 0x3) + (0x93e5 + 0xc059))",
"source_dataset": "bitwise_arithmetic",
"source_index": 571
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9663 + 0x1e42) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5a52",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9663 + 0x1e42) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 572
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x25ec - 0xce41) + (0x6398 * 0x830))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x32ec42b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x25ec - 0xce41) + (0x6398 * 0x830))",
"source_dataset": "bitwise_arithmetic",
"source_index": 573
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2eaa >> 0x1) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1755",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2eaa >> 0x1) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 574
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd267 * 0x15fc) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x242320c8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd267 * 0x15fc) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 575
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb24e * 0x2d59) - (0x2933 + 0xc0dc))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1f94c90f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb24e * 0x2d59) - (0x2933 + 0xc0dc))",
"source_dataset": "bitwise_arithmetic",
"source_index": 576
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa62e << 0x0) + (0xe3bc - 0x1da9))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x16c41",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa62e << 0x0) + (0xe3bc - 0x1da9))",
"source_dataset": "bitwise_arithmetic",
"source_index": 577
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xca8b >> 0x0) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6545",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xca8b >> 0x0) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 578
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6579 * 0xdcd1) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2bc369e4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6579 * 0xdcd1) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 579
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xff8e + 0x9c04) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x66e48",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xff8e + 0x9c04) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 580
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9665 << 0x0) - (0xaa06 + 0x441e))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x57bf",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9665 << 0x0) - (0xaa06 + 0x441e))",
"source_dataset": "bitwise_arithmetic",
"source_index": 581
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x93cf * 0xcd4a) + (0x86f3 * 0x9835))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc6c3b525",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x93cf * 0xcd4a) + (0x86f3 * 0x9835))",
"source_dataset": "bitwise_arithmetic",
"source_index": 582
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4230 + 0x68dc) * (0x1c56 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4bb5bfc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4230 + 0x68dc) * (0x1c56 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 583
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa32e - 0xc553) + (0xf773 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1ccc1",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa32e - 0xc553) + (0xf773 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 584
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5b1 - 0x40a5) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x75f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5b1 - 0x40a5) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 585
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x78e0 + 0xf073) + (0xfe41 - 0xed35))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x17a5f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x78e0 + 0xf073) + (0xfe41 - 0xed35))",
"source_dataset": "bitwise_arithmetic",
"source_index": 586
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3f5 >> 0x2) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3f4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3f5 >> 0x2) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 587
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9c74 + 0x5e9f) - (0xf255 - 0xe82c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf0ea",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9c74 + 0x5e9f) - (0xf255 - 0xe82c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 588
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9ac4 - 0x2323) * (0x37a4 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6800e89",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9ac4 - 0x2323) * (0x37a4 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 589
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4e4f + 0x9fc8) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1dc2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4e4f + 0x9fc8) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 590
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x347 + 0x5e51) + (0xd745 - 0xc3e3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x74fa",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x347 + 0x5e51) + (0xd745 - 0xc3e3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 591
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x84b2 >> 0x1) + (0x5bf7 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xfa47",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x84b2 >> 0x1) + (0x5bf7 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 592
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb396 << 0x1) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb396",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb396 << 0x1) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 593
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8762 >> 0x3) + (0x683e * 0x8dc2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x39b935e8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8762 >> 0x3) + (0x683e * 0x8dc2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 594
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x74fb + 0x67b6) * (0xad4a - 0xb824))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x95ad8ba",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x74fb + 0x67b6) * (0xad4a - 0xb824))",
"source_dataset": "bitwise_arithmetic",
"source_index": 595
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbad8 * 0x6242) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x47b6dbb0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbad8 * 0x6242) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 596
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5d01 - 0xf8e5) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x4df2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5d01 - 0xf8e5) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 597
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc382 * 0x3120) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x96114900",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc382 * 0x3120) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 598
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc7cf << 0x2) + (0xd06c << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3efa8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc7cf << 0x2) + (0xd06c << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 599
}
|
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