data_source
stringclasses 1
value | prompt
stringlengths 271
305
| ability
stringclasses 1
value | reward_model
dict | extra_info
dict |
|---|---|---|---|---|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe29f >> 0x3) * (0x563a + 0x6ccd))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1593ff45",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe29f >> 0x3) * (0x563a + 0x6ccd))",
"source_dataset": "bitwise_arithmetic",
"source_index": 600
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8720 * 0x33d0) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1b592a00",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8720 * 0x33d0) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 601
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x74ca >> 0x1) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1d328",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x74ca >> 0x1) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 602
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4966 + 0x7e2) - (0xc72e - 0x4ffc))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x25ea",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4966 + 0x7e2) - (0xc72e - 0x4ffc))",
"source_dataset": "bitwise_arithmetic",
"source_index": 603
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9e85 >> 0x3) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4f4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9e85 >> 0x3) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 604
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe2b4 + 0x62df) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x28b2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe2b4 + 0x62df) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 605
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1dce - 0x6a96) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x999",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1dce - 0x6a96) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 606
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9acb >> 0x0) - (0x953 * 0x5813))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3349e5e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9acb >> 0x0) - (0x953 * 0x5813))",
"source_dataset": "bitwise_arithmetic",
"source_index": 607
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7187 << 0x3) - (0xdd07 * 0x8f52))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x7bba2906",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7187 << 0x3) - (0xdd07 * 0x8f52))",
"source_dataset": "bitwise_arithmetic",
"source_index": 608
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1d69 + 0xb224) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x33e3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1d69 + 0xb224) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 609
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xda3c << 0x2) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6d1e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xda3c << 0x2) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 610
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2c9c >> 0x2) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x164e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2c9c >> 0x2) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 611
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9c12 + 0x728c) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x874f0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9c12 + 0x728c) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 612
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe403 + 0x3488) - (0x97c7 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xcca8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe403 + 0x3488) - (0x97c7 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 613
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8b3b + 0x795d) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x20930",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8b3b + 0x795d) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 614
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7059 * 0x19f) * (0x7c04 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2c1d3d728e0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7059 * 0x19f) * (0x7c04 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 615
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb087 << 0x0) + (0x2b29 + 0x3c4f))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x117ff",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb087 << 0x0) + (0x2b29 + 0x3c4f))",
"source_dataset": "bitwise_arithmetic",
"source_index": 616
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x27ca - 0xed52) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x31620",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x27ca - 0xed52) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 617
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2959 + 0xd435) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7ec70",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2959 + 0xd435) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 618
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xcd4c + 0x8bc7) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x15913",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xcd4c + 0x8bc7) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 619
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc89a * 0x48cf) + (0xd703 >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x390e5b89",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc89a * 0x48cf) + (0xd703 >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 620
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc6d2 + 0xa87c) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2de9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc6d2 + 0xa87c) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 621
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x23fb >> 0x3) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x23fb >> 0x3) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 622
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3afb * 0x7f2e) - (0xd3d2 + 0x6f70))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1d4bdad8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3afb * 0x7f2e) - (0xd3d2 + 0x6f70))",
"source_dataset": "bitwise_arithmetic",
"source_index": 623
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4a4 >> 0x2) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x948",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4a4 >> 0x2) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 624
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5064 * 0x5e37) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3b2bfaf8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5064 * 0x5e37) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 625
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfe6c + 0x30d5) + (0x233d >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x133a8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfe6c + 0x30d5) + (0x233d >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 626
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4e67 - 0x4f34) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4e67 - 0x4f34) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 627
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6749 << 0x2) - (0x1d8f + 0x253a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x15a5b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6749 << 0x2) - (0x1d8f + 0x253a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 628
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6153 << 0x0) - (0x58c + 0x420a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x19bd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6153 << 0x0) - (0x58c + 0x420a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 629
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf3d3 >> 0x2) - (0xdd1b + 0xe169))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x18190",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf3d3 >> 0x2) - (0xdd1b + 0xe169))",
"source_dataset": "bitwise_arithmetic",
"source_index": 630
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xca96 + 0x5fff) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2552a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xca96 + 0x5fff) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 631
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa3a2 - 0xdc96) + (0xdc8a * 0x12b7))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x101f21b2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa3a2 - 0xdc96) + (0xdc8a * 0x12b7))",
"source_dataset": "bitwise_arithmetic",
"source_index": 632
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbcbc * 0xa25d) * (0x787c * 0xdc3a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3076c976eef21720",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbcbc * 0xa25d) * (0x787c * 0xdc3a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 633
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8d66 >> 0x3) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x46b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8d66 >> 0x3) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 634
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9531 << 0x0) + (0xc37b - 0x17ab))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x14101",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9531 << 0x0) + (0xc37b - 0x17ab))",
"source_dataset": "bitwise_arithmetic",
"source_index": 635
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(0xd2a3 * 0x7a82)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x64cca4c6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "(0xd2a3 * 0x7a82)",
"source_dataset": "bitwise_arithmetic",
"source_index": 636
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd147 << 0x0) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3451",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd147 << 0x0) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 637
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd85b >> 0x2) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6c2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd85b >> 0x2) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 638
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc850 << 0x0) * (0xfd4d * 0x52c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x401116212c0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc850 << 0x0) * (0xfd4d * 0x52c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 639
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xaa5b << 0x3) - (0x33c4 - 0x6b69))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x58a7d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xaa5b << 0x3) - (0x33c4 - 0x6b69))",
"source_dataset": "bitwise_arithmetic",
"source_index": 640
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1948 - 0x900a) + (0x2d02 >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x7122",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1948 - 0x900a) + (0x2d02 >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 641
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8b23 >> 0x3) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8b2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8b23 >> 0x3) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 642
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9b70 * 0x4d0) + (0x9dc1 - 0x5007))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2ec58ba",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9b70 * 0x4d0) + (0x9dc1 - 0x5007))",
"source_dataset": "bitwise_arithmetic",
"source_index": 643
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xaf07 * 0xd7e2) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x24e6594b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xaf07 * 0xd7e2) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 644
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa1c9 << 0x0) - (0x84a8 + 0x39d8))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1cb7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa1c9 << 0x0) - (0x84a8 + 0x39d8))",
"source_dataset": "bitwise_arithmetic",
"source_index": 645
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x40d9 << 0x1) * (0x8e7 + 0x754b))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3feef0c4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x40d9 << 0x1) * (0x8e7 + 0x754b))",
"source_dataset": "bitwise_arithmetic",
"source_index": 646
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(0x7b6a * (0x8da5 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x222438f4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "(0x7b6a * (0x8da5 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 647
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb94e << 0x0) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5ca70",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb94e << 0x0) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 648
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd560 * 0xf8b7) - (0xa2ff - 0x4fb8))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xcf4d3459",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd560 * 0xf8b7) - (0xa2ff - 0x4fb8))",
"source_dataset": "bitwise_arithmetic",
"source_index": 649
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3053 >> 0x0) - (0x3c71 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x121b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3053 >> 0x0) - (0x3c71 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 650
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x28be * 0xee63) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x25f0657a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x28be * 0xee63) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 651
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7478 + 0xd3fe) * (0xcfcc * 0x103b))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x10e744b8b9d8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7478 + 0xd3fe) * (0xcfcc * 0x103b))",
"source_dataset": "bitwise_arithmetic",
"source_index": 652
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8d61 * 0x6d0f) - (0x282d * 0xed20))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1703e70f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8d61 * 0x6d0f) - (0x282d * 0xed20))",
"source_dataset": "bitwise_arithmetic",
"source_index": 653
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7feb >> 0x2) - (0xdb2f << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x34cc2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7feb >> 0x2) - (0xdb2f << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 654
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x546c + 0x7595) + (0x12db - 0xca98))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1244",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x546c + 0x7595) + (0x12db - 0xca98))",
"source_dataset": "bitwise_arithmetic",
"source_index": 655
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7190 << 0x2) * (0xcbb9 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb4bd9f00",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7190 << 0x2) * (0xcbb9 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 656
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x87f - 0xdf39) + (0x2954 + 0xb339))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5d3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x87f - 0xdf39) + (0x2954 + 0xb339))",
"source_dataset": "bitwise_arithmetic",
"source_index": 657
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd6a8 - 0x88e7) - (0xdaba * 0x25f))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x2065145",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd6a8 - 0x88e7) - (0xdaba * 0x25f))",
"source_dataset": "bitwise_arithmetic",
"source_index": 658
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x968f >> 0x1) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x968e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x968f >> 0x1) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 659
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd509 * 0x3322) + (0xd22d * 0x78c9))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8db73387",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd509 * 0x3322) + (0xd22d * 0x78c9))",
"source_dataset": "bitwise_arithmetic",
"source_index": 660
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6be0 - 0x14e8) - (0x87d1 + 0xf467))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x12540",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6be0 - 0x14e8) - (0x87d1 + 0xf467))",
"source_dataset": "bitwise_arithmetic",
"source_index": 661
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4f17 >> 0x3) * (0x53f1 - 0x7103))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x11f4be4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4f17 >> 0x3) * (0x53f1 - 0x7103))",
"source_dataset": "bitwise_arithmetic",
"source_index": 662
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7bad << 0x1) + (0x6979 + 0xae4a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x20f1d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7bad << 0x1) + (0x6979 + 0xae4a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 663
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x92b9 >> 0x3) * (0x99d5 >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb054163",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x92b9 >> 0x3) * (0x99d5 >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 664
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x77b3 >> 0x0) * (0x8fa4 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x10ca6aeb",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x77b3 >> 0x0) * (0x8fa4 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 665
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc595 * 0xecd0) * (0x6249 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x118af8079c640",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc595 * 0xecd0) * (0x6249 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 666
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2d15 + 0x20d1) * (0x34f + 0x6c46))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x21f410de",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2d15 + 0x20d1) * (0x34f + 0x6c46))",
"source_dataset": "bitwise_arithmetic",
"source_index": 667
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x718c - 0x4ce2) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x495",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x718c - 0x4ce2) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 668
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3b04 * 0x6f10) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xccd36200",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3b04 * 0x6f10) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 669
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x33ee << 0x2) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xcfb8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x33ee << 0x2) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 670
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa917 << 0x2) * (0x5ece << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xfa7a0a08",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa917 << 0x2) * (0x5ece << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 671
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4ef6 + 0x6c97) + (0x8f60 + 0xde65))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x22952",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4ef6 + 0x6c97) + (0x8f60 + 0xde65))",
"source_dataset": "bitwise_arithmetic",
"source_index": 672
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1836 - 0xeea) - (0xb881 * 0xce09))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x947e413d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1836 - 0xeea) - (0xb881 * 0xce09))",
"source_dataset": "bitwise_arithmetic",
"source_index": 673
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xea9c + 0xad4b) - (0x719b >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x189b4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xea9c + 0xad4b) - (0x719b >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 674
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3b7c >> 0x3) - (0x580 + 0x998a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x979b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3b7c >> 0x3) - (0x580 + 0x998a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 675
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x22a7 << 0x3) - (0x49dd >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x102c1",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x22a7 << 0x3) - (0x49dd >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 676
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x48ea >> 0x3) + (0xb2b1 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2d3e1",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x48ea >> 0x3) + (0xb2b1 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 677
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xddbb - 0xc5ae) - (0x79ef + 0x957))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x6b39",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xddbb - 0xc5ae) - (0x79ef + 0x957))",
"source_dataset": "bitwise_arithmetic",
"source_index": 678
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7c98 * 0xf76f) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf0d95bd0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7c98 * 0xf76f) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 679
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x70ce >> 0x1) - (0xa513 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf23",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x70ce >> 0x1) - (0xa513 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 680
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4662 * 0xc467) - (0x783c - 0xfef))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x35fef121",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4662 * 0xc467) - (0x783c - 0xfef))",
"source_dataset": "bitwise_arithmetic",
"source_index": 681
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xad34 + 0x4955) * (0x1dd6 * 0xcd52))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x170b6fa21eec",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xad34 + 0x4955) * (0x1dd6 * 0xcd52))",
"source_dataset": "bitwise_arithmetic",
"source_index": 682
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(0x8c9b + (0x2155 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x9d45",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "(0x8c9b + (0x2155 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 683
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x144e << 0x3) * (0x16e3 - 0x7c4d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x40597260",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x144e << 0x3) * (0x16e3 - 0x7c4d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 684
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2988 << 0x0) - (0xe43d * 0x2671))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x2245a365",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2988 << 0x0) - (0xe43d * 0x2671))",
"source_dataset": "bitwise_arithmetic",
"source_index": 685
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa34d >> 0x0) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x28d34",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa34d >> 0x0) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 686
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xaedd >> 0x1) * (0x76ad + 0xc471))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6b9e98e4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xaedd >> 0x1) * (0x76ad + 0xc471))",
"source_dataset": "bitwise_arithmetic",
"source_index": 687
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8a42 >> 0x3) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8a4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8a42 >> 0x3) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 688
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf797 + 0x232) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1f39",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf797 + 0x232) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 689
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x139e - 0xeeab) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1b61a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x139e - 0xeeab) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 690
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x284e >> 0x3) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa12",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x284e >> 0x3) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 691
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8dad * 0xa741) * (0x8319 + 0x5cc3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x50f0d53592ac",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8dad * 0xa741) * (0x8319 + 0x5cc3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 692
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x110b << 0x0) - (0x18cb >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x7c0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x110b << 0x0) - (0x18cb >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 693
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1a01 << 0x0) + (0x25f1 * 0xfc8b))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x256defdc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1a01 << 0x0) + (0x25f1 * 0xfc8b))",
"source_dataset": "bitwise_arithmetic",
"source_index": 694
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
0x3173
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3173",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "0x3173",
"source_dataset": "bitwise_arithmetic",
"source_index": 695
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2489 - 0xe064) + (0x9350 * 0x12d6))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xad60905",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2489 - 0xe064) + (0x9350 * 0x12d6))",
"source_dataset": "bitwise_arithmetic",
"source_index": 696
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xab34 - 0x242f) * (0x6829 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6ddf4f9a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xab34 - 0x242f) * (0x6829 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 697
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3d23 * 0x2bab) + (0xf391 + 0xc7f8))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa6f72ea",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3d23 * 0x2bab) + (0xf391 + 0xc7f8))",
"source_dataset": "bitwise_arithmetic",
"source_index": 698
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf316 + 0x6c9e) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xafda",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf316 + 0x6c9e) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 699
}
|
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