data_source
stringclasses 1
value | prompt
stringlengths 271
305
| ability
stringclasses 1
value | reward_model
dict | extra_info
dict |
|---|---|---|---|---|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1fd4 >> 0x0) * (0x6e35 * 0xa1ec))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8aaa2a29e30",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1fd4 >> 0x0) * (0x6e35 * 0xa1ec))",
"source_dataset": "bitwise_arithmetic",
"source_index": 700
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x716 + 0x65e0) * (0x3f7f * 0xcb8f))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x157d533edb96",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x716 + 0x65e0) * (0x3f7f * 0xcb8f))",
"source_dataset": "bitwise_arithmetic",
"source_index": 701
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1ac1 >> 0x0) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd60",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1ac1 >> 0x0) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 702
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x875 - 0x6abc) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3124",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x875 - 0x6abc) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 703
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9195 << 0x1) - (0xe935 - 0x2c16))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x660b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9195 << 0x1) - (0xe935 - 0x2c16))",
"source_dataset": "bitwise_arithmetic",
"source_index": 704
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4adf * 0x828c) + (0xadec - 0x240))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x262edba0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4adf * 0x828c) + (0xadec - 0x240))",
"source_dataset": "bitwise_arithmetic",
"source_index": 705
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc9c << 0x3) * (0xcae1 << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4ff168e0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc9c << 0x3) * (0xcae1 << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 706
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6f67 - 0x51d5) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xec90",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6f67 - 0x51d5) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 707
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x952d << 0x0) - (0xa0a6 * 0x5c17))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x39c981bd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x952d << 0x0) - (0xa0a6 * 0x5c17))",
"source_dataset": "bitwise_arithmetic",
"source_index": 708
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfe8b * 0x6f50) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6eadd070",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfe8b * 0x6f50) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 709
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x65c0 * 0x17a3) + (0xe6ee * 0x274e))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2cd9a7c4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x65c0 * 0x17a3) + (0xe6ee * 0x274e))",
"source_dataset": "bitwise_arithmetic",
"source_index": 710
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xaaa9 * 0xf4c0) + (0xac99 >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa329bf59",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xaaa9 * 0xf4c0) + (0xac99 >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 711
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1f28 - 0xac67) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x8d3f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1f28 - 0xac67) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 712
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4d09 + 0x9a27) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe730",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4d09 + 0x9a27) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 713
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x60e2 >> 0x0) * (0x96f6 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1c90c296",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x60e2 >> 0x0) * (0x96f6 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 714
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd150 << 0x3) - (0xfa5c - 0x43a1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5d3c5",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd150 << 0x3) - (0xfa5c - 0x43a1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 715
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x83d8 * 0xc141) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc70ea3b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x83d8 * 0xc141) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 716
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc975 * 0xc73e) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x9ccabd56",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc975 * 0xc73e) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 717
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6313 + 0xa5fa) * (0xe5ca >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1dbcf665",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6313 + 0xa5fa) * (0xe5ca >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 718
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xda7e >> 0x0) - (0xf770 - 0x2a9))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1a49",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xda7e >> 0x0) - (0xf770 - 0x2a9))",
"source_dataset": "bitwise_arithmetic",
"source_index": 719
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x40cc << 0x0) * (0x86d - 0xd3ac))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3371b634",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x40cc << 0x0) * (0x86d - 0xd3ac))",
"source_dataset": "bitwise_arithmetic",
"source_index": 720
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd285 + 0x84ce) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2aea6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd285 + 0x84ce) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 721
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa420 << 0x3) - (0xc5e7 - 0x4517))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4a030",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa420 << 0x3) - (0xc5e7 - 0x4517))",
"source_dataset": "bitwise_arithmetic",
"source_index": 722
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xec46 - 0x2f6c) - (0x87a2 + 0x9b81))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x6649",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xec46 - 0x2f6c) - (0x87a2 + 0x9b81))",
"source_dataset": "bitwise_arithmetic",
"source_index": 723
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb2be * 0xb5e0) - (0xcf30 >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7efbed10",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb2be * 0xb5e0) - (0xcf30 >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 724
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x36bb << 0x3) + (0xdcf8 - 0x59a5))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2392b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x36bb << 0x3) + (0xdcf8 - 0x59a5))",
"source_dataset": "bitwise_arithmetic",
"source_index": 725
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf668 - 0x809a) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x75ce",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf668 - 0x809a) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 726
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5aba >> 0x1) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5ab",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5aba >> 0x1) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 727
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbe3f - 0x9f6) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x16892",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbe3f - 0x9f6) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 728
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1426 << 0x2) - (0x5bfe >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xb66",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1426 << 0x2) - (0x5bfe >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 729
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3266 + 0x2676) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x58dc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3266 + 0x2676) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 730
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8043 >> 0x3) * (0x1573 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x55eae0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8043 >> 0x3) * (0x1573 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 731
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf677 << 0x1) + (0xa5d5 * 0x71c1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x49b1f783",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf677 << 0x1) + (0xa5d5 * 0x71c1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 732
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xce8c << 0x3) + (0xb2b7 - 0x5295))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6d482",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xce8c << 0x3) + (0xb2b7 - 0x5295))",
"source_dataset": "bitwise_arithmetic",
"source_index": 733
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1e06 << 0x0) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf03",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1e06 << 0x0) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 734
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4613 >> 0x2) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8c20",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4613 >> 0x2) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 735
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd577 * 0xaaf7) - (0xa127 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8e89f299",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd577 * 0xaaf7) - (0xa127 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 736
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3280 >> 0x2) - (0x47d2 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x8304",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3280 >> 0x2) - (0x47d2 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 737
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7886 - 0xd9af) * (0x6a9e << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x2876f14e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7886 - 0xd9af) * (0x6a9e << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 738
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7c24 * 0x119f) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x445bf2e0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7c24 * 0x119f) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 739
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7586 * 0x543d) * (0x4bce * 0x5641))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3dbb56e7784c284",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7586 * 0x543d) * (0x4bce * 0x5641))",
"source_dataset": "bitwise_arithmetic",
"source_index": 740
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x450f << 0x1) - (0xcd25 >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x4307",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x450f << 0x1) - (0xcd25 >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 741
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf050 - 0x4f52) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x141f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf050 - 0x4f52) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 742
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2513 + 0xd6aa) - (0x9a5a >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xae90",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2513 + 0xd6aa) - (0x9a5a >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 743
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x29bb - 0x9595) + (0xf397 + 0x1ce3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa4a0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x29bb - 0x9595) + (0xf397 + 0x1ce3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 744
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x18a9 >> 0x3) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x315",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x18a9 >> 0x3) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 745
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa7fd - 0xe34e) + (0x344b >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x212c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa7fd - 0xe34e) + (0x344b >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 746
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8973 << 0x2) + (0x9c3f - 0x5686))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x26b85",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8973 << 0x2) + (0x9c3f - 0x5686))",
"source_dataset": "bitwise_arithmetic",
"source_index": 747
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7dcd + 0x9035) * (0x949e * 0xaf7))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6b6bb135ce4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7dcd + 0x9035) * (0x949e * 0xaf7))",
"source_dataset": "bitwise_arithmetic",
"source_index": 748
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2cdd - 0x69e0) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1e82",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2cdd - 0x69e0) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 749
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8369 << 0x0) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8369",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8369 << 0x0) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 750
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb341 + 0x73b6) * (0xcecd << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1dc8deb96",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb341 + 0x73b6) * (0xcecd << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 751
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf9ad << 0x0) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf9ad",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf9ad << 0x0) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 752
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4f3f * 0xc734) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3daa11cc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4f3f * 0xc734) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 753
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x70c1 << 0x3) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1c3040",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x70c1 << 0x3) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 754
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x967b << 0x0) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4b3d8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x967b << 0x0) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 755
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xec80 - 0x47ff) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x14902",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xec80 - 0x47ff) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 756
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x659a - 0x6c2) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x17b60",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x659a - 0x6c2) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 757
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc7c5 << 0x2) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x31f14",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc7c5 << 0x2) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 758
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1917 << 0x0) * (0x87dc * 0x3684))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2d5e2e47d10",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1917 << 0x0) * (0x87dc * 0x3684))",
"source_dataset": "bitwise_arithmetic",
"source_index": 759
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf8c9 * 0x3057) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5df4789",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf8c9 * 0x3057) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 760
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3ffd + 0xc0f3) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x201e0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3ffd + 0xc0f3) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 761
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd6d1 * 0x62f) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x530565f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd6d1 * 0x62f) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 762
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe7e1 + 0x785c) + (0xe1e3 >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x17c79",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe7e1 + 0x785c) + (0xe1e3 >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 763
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x524a >> 0x2) + (0xe5a0 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x74192",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x524a >> 0x2) + (0xe5a0 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 764
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xceb9 - 0x4e9b) + (0xb181 - 0xe271))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4f2e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xceb9 - 0x4e9b) + (0xb181 - 0xe271))",
"source_dataset": "bitwise_arithmetic",
"source_index": 765
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc394 << 0x1) * (0x7da9 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1800182d0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc394 << 0x1) * (0x7da9 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 766
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4f3f >> 0x3) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x279c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4f3f >> 0x3) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 767
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2b79 + 0xd1f4) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1fad",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2b79 + 0xd1f4) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 768
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x969 << 0x1) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x12d2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x969 << 0x1) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 769
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5b0e * 0xf2da) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2b3062f6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5b0e * 0xf2da) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 770
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdd27 >> 0x3) + (0xe813 + 0x89f1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x18da8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdd27 >> 0x3) + (0xe813 + 0x89f1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 771
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x56a7 + 0xe26e) - (0x88fd - 0x72b9))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x122d1",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x56a7 + 0xe26e) - (0x88fd - 0x72b9))",
"source_dataset": "bitwise_arithmetic",
"source_index": 772
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x58af * 0x7a7a) * (0x168e >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1de7ab15d4a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x58af * 0x7a7a) * (0x168e >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 773
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1807 << 0x2) + (0xf7c4 - 0x4857))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x10f89",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1807 << 0x2) + (0xf7c4 - 0x4857))",
"source_dataset": "bitwise_arithmetic",
"source_index": 774
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x412b - 0xaa2c) * (0x44c3 * 0xaf57))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x13514d57f845",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x412b - 0xaa2c) * (0x44c3 * 0xaf57))",
"source_dataset": "bitwise_arithmetic",
"source_index": 775
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd192 << 0x0) * (0xd50c << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5734266c0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd192 << 0x0) * (0xd50c << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 776
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x21ed * 0xb486) - (0x464a >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x17ec547c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x21ed * 0xb486) - (0x464a >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 777
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfdca - 0x3a50) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x61bd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfdca - 0x3a50) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 778
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf1dd * 0x3c0d) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe2f050e4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf1dd * 0x3c0d) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 779
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4cd1 << 0x0) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x13344",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4cd1 << 0x0) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 780
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc1e2 + 0xc5ee) - (0x335d * 0x361f))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xada4e73",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc1e2 + 0xc5ee) - (0x335d * 0x361f))",
"source_dataset": "bitwise_arithmetic",
"source_index": 781
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x25fc + 0xe6f7) - (0x11eb + 0x3844))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc2c4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x25fc + 0xe6f7) - (0x11eb + 0x3844))",
"source_dataset": "bitwise_arithmetic",
"source_index": 782
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa352 + 0xe010) * (0x32be >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4cc8a6bc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa352 + 0xe010) * (0x32be >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 783
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3146 - 0x9f25) * (0xff64 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x36ce060e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3146 - 0x9f25) * (0xff64 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 784
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x87ad + 0x7ec8) * (0xce7f << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd3b45a0b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x87ad + 0x7ec8) * (0xce7f << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 785
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb5aa - 0x5e76) + (0x6b53 * 0x7119))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2f6a754f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb5aa - 0x5e76) + (0x6b53 * 0x7119))",
"source_dataset": "bitwise_arithmetic",
"source_index": 786
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf03b >> 0x0) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf03b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf03b >> 0x0) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 787
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x723f * 0xd847) - (0xa4ae + 0xa96d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6083895e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x723f * 0xd847) - (0xa4ae + 0xa96d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 788
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xff70 + 0xed25) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1ec95",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xff70 + 0xed25) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 789
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe821 >> 0x3) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x741",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe821 >> 0x3) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 790
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1cc1 - 0xba5f) * (0xacf1 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x353d44df0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1cc1 - 0xba5f) * (0xacf1 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 791
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfff8 - 0x8f25) - (0xd324 * 0xcaca))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xa7409195",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfff8 - 0x8f25) - (0xd324 * 0xcaca))",
"source_dataset": "bitwise_arithmetic",
"source_index": 792
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1f30 * 0xae7d) - (0xcaad >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1541a7c5",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1f30 * 0xae7d) - (0xcaad >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 793
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf11f + 0x48b) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1eb5",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf11f + 0x48b) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 794
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x41ce >> 0x1) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x20e7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x41ce >> 0x1) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 795
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfaae * 0xfb22) * (0xe993 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x702f8b6a858a0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfaae * 0xfb22) * (0xe993 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 796
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3b2a - 0xacde) + (0xa0d8 - 0x369))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2bbb",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3b2a - 0xacde) + (0xa0d8 - 0x369))",
"source_dataset": "bitwise_arithmetic",
"source_index": 797
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x76d6 << 0x1) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3b6b0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x76d6 << 0x1) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 798
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf8dd >> 0x1) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf8d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf8dd >> 0x1) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 799
}
|
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