data_source
stringclasses 1
value | prompt
stringlengths 271
305
| ability
stringclasses 1
value | reward_model
dict | extra_info
dict |
|---|---|---|---|---|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9c35 - 0xf790) - (0xe857 * 0x7de4))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x7241c3d7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9c35 - 0xf790) - (0xe857 * 0x7de4))",
"source_dataset": "bitwise_arithmetic",
"source_index": 900
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xee45 - 0x728f) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf76",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xee45 - 0x728f) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 901
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd905 + 0xf699) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe7cf",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd905 + 0xf699) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 902
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3425 - 0xea44) - (0x93a1 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x304a3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3425 - 0xea44) - (0x93a1 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 903
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2fe5 * 0xf732) * (0x2fcc + 0xa2cd))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x260b9198082a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2fe5 * 0xf732) * (0x2fcc + 0xa2cd))",
"source_dataset": "bitwise_arithmetic",
"source_index": 904
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1c67 >> 0x3) * (0xc255 * 0xe37))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2645e2b5a4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1c67 >> 0x3) * (0xc255 * 0xe37))",
"source_dataset": "bitwise_arithmetic",
"source_index": 905
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1762 + 0xd2b6) + (0x5848 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x19aa8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1762 + 0xd2b6) + (0x5848 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 906
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4562 * 0xa035) * (0x8ef5 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x60fcfcf24f48",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4562 * 0xa035) * (0x8ef5 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 907
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x732f - 0xd52) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xcbba",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x732f - 0xd52) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 908
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4e5b * 0xceb2) - (0x3366 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3f421a16",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4e5b * 0xceb2) - (0x3366 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 909
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2b65 + 0xb82) + (0x194 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4387",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2b65 + 0xb82) + (0x194 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 910
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
0x63db
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x63db",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "0x63db",
"source_dataset": "bitwise_arithmetic",
"source_index": 911
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8b95 - 0xe715) + (0x4af0 * 0x9b72))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2d805360",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8b95 - 0xe715) + (0x4af0 * 0x9b72))",
"source_dataset": "bitwise_arithmetic",
"source_index": 912
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2719 << 0x3) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x9c640",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2719 << 0x3) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 913
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe272 << 0x0) - (0x4191 * 0x416e))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x10c11adc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe272 << 0x0) - (0x4191 * 0x416e))",
"source_dataset": "bitwise_arithmetic",
"source_index": 914
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe552 << 0x0) - (0x9767 - 0x9269))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe054",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe552 << 0x0) - (0x9767 - 0x9269))",
"source_dataset": "bitwise_arithmetic",
"source_index": 915
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3cf3 << 0x3) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3cf3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3cf3 << 0x3) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 916
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3b32 << 0x0) + (0x488 >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3bc3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3b32 << 0x0) + (0x488 >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 917
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4bad + 0xeb99) - (0xb831 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1093a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4bad + 0xeb99) - (0xb831 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 918
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe6f1 << 0x2) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe6f1",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe6f1 << 0x2) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 919
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x34d5 << 0x2) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd354",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x34d5 << 0x2) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 920
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5c1a + 0xa8b6) * (0x26a4 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x9d77d50",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5c1a + 0xa8b6) * (0x26a4 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 921
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf056 >> 0x1) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf05",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf056 >> 0x1) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 922
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbb6e * 0x43c6) * (0x3308 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2790b5b41280",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbb6e * 0x43c6) * (0x3308 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 923
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6243 << 0x2) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc486",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6243 << 0x2) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 924
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdb90 << 0x0) + (0x66b8 + 0x1af8))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x15d40",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdb90 << 0x0) + (0x66b8 + 0x1af8))",
"source_dataset": "bitwise_arithmetic",
"source_index": 925
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdd42 >> 0x0) * (0x4af7 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x81951d5c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdd42 >> 0x0) * (0x4af7 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 926
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x172b * 0xafbb) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1fcea2d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x172b * 0xafbb) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 927
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdb9c >> 0x1) + (0x941 * 0xf065))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8b10473",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdb9c >> 0x1) + (0x941 * 0xf065))",
"source_dataset": "bitwise_arithmetic",
"source_index": 928
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2ce9 + 0x3b2f) * (0xac23 - 0x3127))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3201e7a0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2ce9 + 0x3b2f) * (0xac23 - 0x3127))",
"source_dataset": "bitwise_arithmetic",
"source_index": 929
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd65c << 0x3) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd65c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd65c << 0x3) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 930
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdd5a * 0xc847) + (0x93e1 * 0x1c3d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xbd7b8c93",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdd5a * 0xc847) + (0x93e1 * 0x1c3d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 931
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9535 >> 0x0) * (0x3f6c << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x93dbf570",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9535 >> 0x0) * (0x3f6c << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 932
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xcb51 >> 0x0) + (0x418c + 0xa71e))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1b3fb",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xcb51 >> 0x0) + (0x418c + 0xa71e))",
"source_dataset": "bitwise_arithmetic",
"source_index": 933
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4b8c + 0x8d63) - (0x3f4d * 0xe7e2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3955840b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4b8c + 0x8d63) - (0x3f4d * 0xe7e2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 934
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5515 * 0xab6c) + (0xbe0d + 0x3d25))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x38f9e70e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5515 * 0xab6c) + (0xbe0d + 0x3d25))",
"source_dataset": "bitwise_arithmetic",
"source_index": 935
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xce60 << 0x3) - (0xd4c9 - 0x58d1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5f708",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xce60 << 0x3) - (0xd4c9 - 0x58d1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 936
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x292c * 0xa90f) - (0xceb1 - 0xb51f))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1b305c02",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x292c * 0xa90f) - (0xceb1 - 0xb51f))",
"source_dataset": "bitwise_arithmetic",
"source_index": 937
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4a77 * 0xacb5) - (0x1f48 * 0x99c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x31100243",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4a77 * 0xacb5) - (0x1f48 * 0x99c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 938
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb74b * 0x7f4f) + (0x7729 * 0x7784))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x92c84549",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb74b * 0x7f4f) + (0x7729 * 0x7784))",
"source_dataset": "bitwise_arithmetic",
"source_index": 939
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xcfc9 * 0x16dd) * (0x87b5 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x27591874e21",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xcfc9 * 0x16dd) * (0x87b5 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 940
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9819 >> 0x3) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4c0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9819 >> 0x3) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 941
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf492 + 0x9dfc) + (0x8724 + 0xfbdf))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x31591",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf492 + 0x9dfc) + (0x8724 + 0xfbdf))",
"source_dataset": "bitwise_arithmetic",
"source_index": 942
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6957 << 0x1) - (0x481e - 0x4e1c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd8ac",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6957 << 0x1) - (0x481e - 0x4e1c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 943
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x94a7 + 0xcf01) + (0x3e7e << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x35798",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x94a7 + 0xcf01) + (0x3e7e << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 944
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfc1b >> 0x0) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xfc1b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfc1b >> 0x0) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 945
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3f3e + 0x1662) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xab4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3f3e + 0x1662) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 946
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6d75 * 0xb585) - (0xdf92 + 0x2a0c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4d9b8d2b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6d75 * 0xb585) - (0xdf92 + 0x2a0c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 947
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc4f2 * 0x43e5) + (0x84d0 >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x343c074a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc4f2 * 0x43e5) + (0x84d0 >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 948
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd0dd - 0xd366) - (0x94d8 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x12c39",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd0dd - 0xd366) - (0x94d8 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 949
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xec04 + 0xbdc3) * (0xd4ca >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x58795bde",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xec04 + 0xbdc3) * (0xd4ca >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 950
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9dfa * 0x986f) + (0x444b << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5e1311be",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9dfa * 0x986f) + (0x444b << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 951
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfaf8 << 0x2) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xfaf8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfaf8 << 0x2) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 952
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf83a - 0x70be) * (0xca45 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1ac2f53c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf83a - 0x70be) * (0xca45 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 953
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1bb2 - 0x1a93) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8f8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1bb2 - 0x1a93) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 954
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe48b * 0x3323) * (0xf891 + 0x190c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x30cb0552419d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe48b * 0x3323) * (0xf891 + 0x190c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 955
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2ff5 << 0x1) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5fea",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2ff5 << 0x1) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 956
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x93e1 >> 0x3) + (0xa5ca * 0xcc64))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x845dcd64",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x93e1 >> 0x3) + (0xa5ca * 0xcc64))",
"source_dataset": "bitwise_arithmetic",
"source_index": 957
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x78c8 + 0x2b6f) + (0x225c << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe8ef",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x78c8 + 0x2b6f) + (0x225c << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 958
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xddda - 0xf2d5) + (0xca30 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x63c85",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xddda - 0xf2d5) + (0xca30 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 959
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x225d - 0x4806) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x25a9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x225d - 0x4806) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 960
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x735c << 0x3) * (0x11e8 * 0x7abd))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1ef2f6628f00",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x735c << 0x3) * (0x11e8 * 0x7abd))",
"source_dataset": "bitwise_arithmetic",
"source_index": 961
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa432 >> 0x1) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x290c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa432 >> 0x1) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 962
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa441 >> 0x2) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa440",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa441 >> 0x2) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 963
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xef4a - 0x94df) - (0xc521 + 0x36b0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xa166",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xef4a - 0x94df) - (0xc521 + 0x36b0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 964
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbed6 * 0xb8c7) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x89be285a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbed6 * 0xb8c7) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 965
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xde2 + 0xf44d) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1022f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xde2 + 0xf44d) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 966
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7b7c >> 0x1) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3dbe",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7b7c >> 0x1) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 967
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x702a << 0x1) - (0x1c5c - 0xd67e))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x19a76",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x702a << 0x1) - (0x1c5c - 0xd67e))",
"source_dataset": "bitwise_arithmetic",
"source_index": 968
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x670a << 0x3) + (0x2eac * 0x1f64))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5bc4780",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x670a << 0x3) + (0x2eac * 0x1f64))",
"source_dataset": "bitwise_arithmetic",
"source_index": 969
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x89f >> 0x2) - (0x897f << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x110d7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x89f >> 0x2) - (0x897f << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 970
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9269 - 0x9168) * (0x637a + 0x3ff5))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa4126f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9269 - 0x9168) * (0x637a + 0x3ff5))",
"source_dataset": "bitwise_arithmetic",
"source_index": 971
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6ef1 << 0x1) - (0x7e62 >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xce16",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6ef1 << 0x1) - (0x7e62 >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 972
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8704 << 0x3) * (0xaaae >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb406bd60",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8704 << 0x3) * (0xaaae >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 973
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2cc2 >> 0x0) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x16610",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2cc2 >> 0x0) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 974
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5b69 + 0x50fa) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xac63",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5b69 + 0x50fa) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 975
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xca50 - 0x9808) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x19240",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xca50 - 0x9808) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 976
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7351 - 0x9d23) - (0xdb33 - 0xcbad))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3958",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7351 - 0x9d23) - (0xdb33 - 0xcbad))",
"source_dataset": "bitwise_arithmetic",
"source_index": 977
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2efd >> 0x1) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5df8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2efd >> 0x1) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 978
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x89e3 * 0x6998) - (0x569d << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x38dfa32b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x89e3 * 0x6998) - (0x569d << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 979
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8c56 << 0x0) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8c56",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8c56 << 0x0) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 980
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6d09 - 0x50cd) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe1e0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6d09 - 0x50cd) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 981
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd554 * 0xcbe9) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2a7af15d0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd554 * 0xcbe9) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 982
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa360 - 0xae46) + (0x7ba3 * 0xe741))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6faf6e7d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa360 - 0xae46) + (0x7ba3 * 0xe741))",
"source_dataset": "bitwise_arithmetic",
"source_index": 983
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3988 * 0x9482) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x215fd710",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3988 * 0x9482) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 984
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3917 << 0x3) + (0xc6db >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x28f93",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3917 << 0x3) + (0xc6db >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 985
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc799 * 0xe6af) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x167b7cf2e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc799 * 0xe6af) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 986
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9050 >> 0x3) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x482",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9050 >> 0x3) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 987
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa8bb - 0xd77c) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x2ec1",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa8bb - 0xd77c) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 988
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xda09 + 0x5163) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4adb",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xda09 + 0x5163) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 989
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x577d - 0x379e) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7f7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x577d - 0x379e) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 990
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe7e2 << 0x0) - (0x35e - 0x61e9))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1466d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe7e2 << 0x0) - (0x35e - 0x61e9))",
"source_dataset": "bitwise_arithmetic",
"source_index": 991
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1453 << 0x3) + (0x307b - 0x5dca))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7549",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1453 << 0x3) + (0x307b - 0x5dca))",
"source_dataset": "bitwise_arithmetic",
"source_index": 992
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1372 - 0xdc1) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb62",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1372 - 0xdc1) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 993
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x141f + 0x5ef7) + (0x5c17 + 0x560b))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x12538",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x141f + 0x5ef7) + (0x5c17 + 0x560b))",
"source_dataset": "bitwise_arithmetic",
"source_index": 994
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5b9 + 0x5b3c) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x60f5",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5b9 + 0x5b3c) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 995
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7e53 * 0xd0b) * (0xc35a << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4e94d9a4dfa",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7e53 * 0xd0b) * (0xc35a << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 996
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf13 + 0x3c9b) - (0xed2d << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x18eac",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf13 + 0x3c9b) - (0xed2d << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 997
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfbdf * 0xdb44) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x35eeab0f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfbdf * 0xdb44) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 998
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc6a8 - 0x1745) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x15ec6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc6a8 - 0x1745) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 999
}
|
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