data_source
stringclasses 1
value | prompt
stringlengths 271
305
| ability
stringclasses 1
value | reward_model
dict | extra_info
dict |
|---|---|---|---|---|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x37ab << 0x1) - (0xe96a >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x7a14",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x37ab << 0x1) - (0xe96a >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1100
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5904 << 0x1) - (0x260d + 0x847a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x781",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5904 << 0x1) - (0x260d + 0x847a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1101
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2de4 << 0x1) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb790",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2de4 << 0x1) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1102
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xba94 - 0x58d4) * (0x8d29 - 0x10ba))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2f836240",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xba94 - 0x58d4) * (0x8d29 - 0x10ba))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1103
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x695b * 0xce84) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2a7ec6760",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x695b * 0xce84) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1104
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5915 >> 0x0) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5915",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5915 >> 0x0) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1105
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x81f3 >> 0x2) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x103e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x81f3 >> 0x2) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1106
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfbce << 0x2) * (0xa69f + 0xe7d5))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x61fb17560",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfbce << 0x2) * (0xa69f + 0xe7d5))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1107
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3f54 + 0xf517) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x9a35",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3f54 + 0xf517) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1108
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2e78 >> 0x2) - (0xa872 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x537f2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2e78 >> 0x2) - (0xa872 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1109
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x804b * 0x10a1) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x10aabe5",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x804b * 0x10a1) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1110
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7ccb - 0x8a26) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xd5b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7ccb - 0x8a26) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1111
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd787 + 0xef42) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x71b2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd787 + 0xef42) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1112
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3869 * 0x3d3a) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6bee665",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3869 * 0x3d3a) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1113
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7615 << 0x0) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7615",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7615 << 0x0) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1114
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x188e - 0xdbe1) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x61a98",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x188e - 0xdbe1) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1115
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5bbb * 0xe391) + (0x8f3e * 0x55e6))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x819b0d9f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5bbb * 0xe391) + (0x8f3e * 0x55e6))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1116
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdb1c * 0x9d30) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x86894140",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdb1c * 0x9d30) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1117
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xea87 << 0x2) - (0xd4b1 + 0x3734))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x29e37",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xea87 << 0x2) - (0xd4b1 + 0x3734))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1118
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf9ad + 0xf419) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1edc6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf9ad + 0xf419) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1119
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdc99 * 0x1507) + (0xf7b7 * 0xd6c6))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe1f126b9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdc99 * 0x1507) + (0xf7b7 * 0xd6c6))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1120
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4d7d + 0x1001) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2ebf0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4d7d + 0x1001) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1121
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x49c * 0x3106) - (0x9bcb - 0xd164))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe22d41",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x49c * 0x3106) - (0x9bcb - 0xd164))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1122
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x277f * 0xabcc) - (0x3c2e * 0xccbe))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x15a003f0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x277f * 0xabcc) - (0x3c2e * 0xccbe))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1123
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x57ad << 0x2) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xaf5a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x57ad << 0x2) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1124
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xcc07 + 0x364f) - (0x1fce >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe288",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xcc07 + 0x364f) - (0x1fce >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1125
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb9e4 >> 0x1) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x173c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb9e4 >> 0x1) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1126
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd689 * 0xb490) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x97510110",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd689 * 0xb490) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1127
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x62a5 + 0xa577) - (0x3184 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x420c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x62a5 + 0xa577) - (0x3184 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1128
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x65b >> 0x1) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1968",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x65b >> 0x1) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1129
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4856 >> 0x0) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4856",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4856 >> 0x0) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1130
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5975 - 0x8864) - 0xfece)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x12dbd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5975 - 0x8864) - 0xfece)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1131
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4d7f >> 0x0) * (0x6a2 * 0x5658))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xad5e291450",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4d7f >> 0x0) * (0x6a2 * 0x5658))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1132
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4c1 << 0x1) * (0x5d7b - 0x5745))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3b0d6c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4c1 << 0x1) * (0x5d7b - 0x5745))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1133
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x16c4 + 0xc989) - (0x37e4 * 0x4d43))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x10dd545f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x16c4 + 0xc989) - (0x37e4 * 0x4d43))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1134
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe75b + 0x3fe1) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1273c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe75b + 0x3fe1) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1135
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7447 * 0xafe1) * (0x7cd0 - 0x6e69))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x47e8a790871",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7447 * 0xafe1) * (0x7cd0 - 0x6e69))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1136
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe0d6 >> 0x1) + (0x2449 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb8fd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe0d6 >> 0x1) + (0x2449 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1137
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x718b * 0x847e) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x75871cd4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x718b * 0x847e) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1138
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9e68 * 0xc59) * (0xab02 + 0xe108))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xbd1e6fd5590",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9e68 * 0xc59) * (0xab02 + 0xe108))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1139
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf04b + 0x441e) - (0xae3a >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x108db",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf04b + 0x441e) - (0xae3a >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1140
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5dbf << 0x0) + (0x1e48 + 0x2ffb))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xac02",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5dbf << 0x0) + (0x1e48 + 0x2ffb))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1141
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7800 * 0x8644) * (0x22a << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x11066358000",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7800 * 0x8644) * (0x22a << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1142
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa8c4 >> 0x1) + (0xc237 - 0x403d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd65c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa8c4 >> 0x1) + (0xc237 - 0x403d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1143
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8593 + 0x701e) + (0xfc85 - 0xdba0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x11696",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8593 + 0x701e) + (0xfc85 - 0xdba0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1144
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4242 >> 0x0) - (0xe965 * 0xc784))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xb5e598d2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4242 >> 0x0) - (0xe965 * 0xc784))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1145
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x16cf << 0x3) + (0xa733 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x204de",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x16cf << 0x3) + (0xa733 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1146
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x886e >> 0x3) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x443",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x886e >> 0x3) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1147
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xebb4 + 0xfde) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1f72",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xebb4 + 0xfde) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1148
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xde6e >> 0x0) * (0x628e - 0x73aa))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xedda208",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xde6e >> 0x0) * (0x628e - 0x73aa))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1149
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2510 - 0x7901) * (0xe2f3 * 0x828a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x25f22a21451e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2510 - 0x7901) * (0xe2f3 * 0x828a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1150
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x812b << 0x2) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x812b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x812b << 0x2) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1151
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x55e - 0x21fb) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x728",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x55e - 0x21fb) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1152
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x28e8 + 0xd4a3) * (0x786b >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x77432119",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x28e8 + 0xd4a3) * (0x786b >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1153
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3ce9 * 0xc15) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2dfeb1d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3ce9 * 0xc15) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1154
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x317c + 0x6bc9) - (0xcfd5 * 0x6056))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x4e351449",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x317c + 0x6bc9) - (0xcfd5 * 0x6056))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1155
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf03d >> 0x3) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x781c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf03d >> 0x3) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1156
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6eeb - 0x18c1) + (0xdd89 - 0x1fd1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x113e2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6eeb - 0x18c1) + (0xdd89 - 0x1fd1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1157
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3378 + 0xba4e) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x76e3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3378 + 0xba4e) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1158
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbc2 << 0x0) * (0x32f8 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x95d1fc0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbc2 << 0x0) * (0x32f8 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1159
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xeb66 - 0xf0f8) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1648",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xeb66 - 0xf0f8) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1160
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x597e * 0x7cf2) - (0xb7d3 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2bad7328",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x597e * 0x7cf2) - (0xb7d3 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1161
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x70bc - 0x1d7c) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x29a00",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x70bc - 0x1d7c) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1162
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5e09 << 0x3) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2f048",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5e09 << 0x3) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1163
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8249 + 0x883) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x11598",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8249 + 0x883) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1164
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdd7a * 0x3ce7) + (0x88b0 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x34b0b56e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdd7a * 0x3ce7) + (0x88b0 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1165
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x486a << 0x3) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x90d40",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x486a << 0x3) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1166
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x535f << 0x0) + (0x3373 * 0xc339))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x273c60fa",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x535f << 0x0) + (0x3373 * 0xc339))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1167
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6eef + 0xd175) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x50190",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6eef + 0xd175) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1168
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5447 * 0xb46b) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xed9496b4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5447 * 0xb46b) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1169
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6832 >> 0x1) * (0x4916 << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xedf9b26",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6832 >> 0x1) * (0x4916 << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1170
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9d38 * 0x9398) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5aa48140",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9d38 * 0x9398) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1171
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x636b << 0x3) + (0xbd4d >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x33301",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x636b << 0x3) + (0xbd4d >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1172
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc759 * 0xb677) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x11c2be0b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc759 * 0xb677) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1173
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9066 << 0x0) + (0xe873 + 0x318c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1aa65",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9066 << 0x0) + (0xe873 + 0x318c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1174
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd8bf >> 0x1) + (0x8005 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8c60",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd8bf >> 0x1) + (0x8005 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1175
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x125a * 0x8339) + (0x28e6 - 0x643c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x967e8b4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x125a * 0x8339) + (0x28e6 - 0x643c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1176
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd0af - 0x5e3e) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7271",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd0af - 0x5e3e) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1177
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xacaf - 0xdea3) * (0x5eb7 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x49ed35b0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xacaf - 0xdea3) * (0x5eb7 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1178
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9ee7 >> 0x2) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x9ee4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9ee7 >> 0x2) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1179
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5199 + 0xc55b) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8b7a0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5199 + 0xc55b) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1180
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3362 << 0x2) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x33620",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3362 << 0x2) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1181
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6edc << 0x2) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6edc0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6edc << 0x2) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1182
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7e35 >> 0x0) * 0x2183)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x10856a1f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7e35 >> 0x0) * 0x2183)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1183
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x846e << 0x3) - (0x4436 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x40155",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x846e << 0x3) - (0x4436 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1184
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5282 - 0x8909) + (0x93a2 * 0x72cd))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x42342633",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5282 - 0x8909) + (0x93a2 * 0x72cd))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1185
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb9f1 * 0x7136) - (0x1555 + 0xf37a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x52399107",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb9f1 * 0x7136) - (0x1555 + 0xf37a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1186
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x41a7 + 0x561d) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x12f8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x41a7 + 0x561d) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1187
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4552 >> 0x1) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x11548",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4552 >> 0x1) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1188
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3a9e << 0x1) * (0x3303 * 0xb974))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x10ec4e530190",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3a9e << 0x1) * (0x3303 * 0xb974))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1189
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xce79 - 0x980) * (0x82b8 * 0x8e0a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x37ce0889c1b0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xce79 - 0x980) * (0x82b8 * 0x8e0a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1190
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa959 * 0xac83) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1c879d22",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa959 * 0xac83) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1191
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xea35 + 0xf249) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1dc7e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xea35 + 0xf249) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1192
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7952 >> 0x1) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1e548",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7952 >> 0x1) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1193
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x89fd * 0x1c6c) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1ea3c578",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x89fd * 0x1c6c) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1194
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5aef - 0x8103) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x4c28",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5aef - 0x8103) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1195
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1a7a * 0xb8d3) - (0x4e67 * 0x9ff9))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1de0b8a1",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1a7a * 0xb8d3) - (0x4e67 * 0x9ff9))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1196
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1b20 + 0x7b24) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x12c88",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1b20 + 0x7b24) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1197
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc8e >> 0x3) * (0x46c8 + 0x963f))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x15a37f7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc8e >> 0x3) * (0x46c8 + 0x963f))",
"source_dataset": "bitwise_arithmetic",
"source_index": 1198
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x41ca * 0xef89) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf63b2c68",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x41ca * 0xef89) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 1199
}
|
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