data_source
stringclasses 1
value | prompt
stringlengths 271
305
| ability
stringclasses 1
value | reward_model
dict | extra_info
dict |
|---|---|---|---|---|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x30da - 0x4b91) * (0x4cc1 * 0x6ab1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3568f6137c7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x30da - 0x4b91) * (0x4cc1 * 0x6ab1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4900
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd244 + 0xb582) - (0x485 >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x18341",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd244 + 0xb582) - (0x485 >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4901
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x55b6 >> 0x0) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2adb0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x55b6 >> 0x0) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4902
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf983 - 0xf36e) - (0x6ff4 + 0xb622))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x12001",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf983 - 0xf36e) - (0x6ff4 + 0xb622))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4903
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa6ee * 0xc13e) + (0xf1ce - 0x212c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7e02ac46",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa6ee * 0xc13e) + (0xf1ce - 0x212c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4904
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(0xef8d << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3be34",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "(0xef8d << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4905
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd06a * 0x4d62) * (0x5924 * 0x7ebb))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xadc05c42f53c7f0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd06a * 0x4d62) * (0x5924 * 0x7ebb))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4906
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x31ff - 0xa898) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x7699",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x31ff - 0xa898) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4907
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa0ed - 0x1114) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8fd9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa0ed - 0x1114) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4908
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf1dd * 0x1f27) + (0x2d1c >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1d6ea6f2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf1dd * 0x1f27) + (0x2d1c >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4909
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x87b7 * 0x2c5b) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xbc1d906",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x87b7 * 0x2c5b) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4910
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x164 * 0xadb) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x78c46",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x164 * 0xadb) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4911
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x715a - 0xef64) * (0x7f57 * 0xe1ef))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3754cbc18a3a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x715a - 0xef64) * (0x7f57 * 0xe1ef))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4912
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbce3 << 0x0) - (0x7e06 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7de0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbce3 << 0x0) - (0x7e06 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4913
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x54d4 >> 0x0) + (0xfe87 - 0x705c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe2ff",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x54d4 >> 0x0) + (0xfe87 - 0x705c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4914
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6602 + 0x82ac) * (0xea49 >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1a9e0f9e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6602 + 0x82ac) * (0xea49 >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4915
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb6db - 0xfa18) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x10cf4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb6db - 0xfa18) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4916
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x10e0 << 0x0) - (0xb70 + 0x14bd))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xf4d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x10e0 << 0x0) - (0xb70 + 0x14bd))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4917
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb643 * 0x9a05) - (0x94d1 - 0xdd22))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6da825a0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb643 * 0x9a05) - (0x94d1 - 0xdd22))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4918
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf866 + 0x3aa0) + (0x9aae * 0x73ea))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x460ac012",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf866 + 0x3aa0) + (0x9aae * 0x73ea))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4919
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2d3e >> 0x1) - (0x14e1 * 0xa668))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xd924ac9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2d3e >> 0x1) - (0x14e1 * 0xa668))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4920
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe00a >> 0x0) + (0xdf9c << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7dcea",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe00a >> 0x0) + (0xdf9c << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4921
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6e4c << 0x0) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xdc98",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6e4c << 0x0) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4922
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xce8 << 0x2) + (0xf33f << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x21a1e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xce8 << 0x2) + (0xf33f << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4923
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xecb6 << 0x0) + (0x1383 * 0xb31))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xdb49c9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xecb6 << 0x0) + (0x1383 * 0xb31))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4924
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8e67 >> 0x2) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2399",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8e67 >> 0x2) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4925
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3dc9 << 0x3) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3dc9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3dc9 << 0x3) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4926
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbd26 + 0x3b92) - (0x3cc2 + 0x4e6f))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6d87",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbd26 + 0x3b92) - (0x3cc2 + 0x4e6f))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4927
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x28b >> 0x1) - (0x79f3 + 0x69a6))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xe254",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x28b >> 0x1) - (0x79f3 + 0x69a6))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4928
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb8be + 0xcc0a) + (0xb798 * 0xff7d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb73b9200",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb8be + 0xcc0a) + (0xb798 * 0xff7d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4929
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5b4c >> 0x2) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x16d3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5b4c >> 0x2) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4930
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x457d - 0x3018) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5594",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x457d - 0x3018) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4931
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3d5b - 0x4356) * (0x6256 + 0xf9f3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x822e893",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3d5b - 0x4356) * (0x6256 + 0xf9f3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4932
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7bbd * 0x5284) + (0x1862 + 0xe167))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x27e3513d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7bbd * 0x5284) + (0x1862 + 0xe167))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4933
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4206 - 0xbad2) * (0xce28 - 0xab60))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x10697760",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4206 - 0xbad2) * (0xce28 - 0xab60))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4934
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x181c - 0xc755) + (0xcaee - 0x9c71))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x80bc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x181c - 0xc755) + (0xcaee - 0x9c71))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4935
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xda8b >> 0x1) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xda8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xda8b >> 0x1) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4936
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa20d << 0x1) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2883",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa20d << 0x1) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4937
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2cb3 + 0x42fd) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xdf60",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2cb3 + 0x42fd) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4938
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf445 << 0x1) * (0x85cc >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xff54fff8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf445 << 0x1) * (0x85cc >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4939
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe073 * 0xaa51) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2554d898c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe073 * 0xaa51) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4940
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdb33 - 0xedae) + (0xeee1 + 0x6238))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x13e9e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdb33 - 0xedae) + (0xeee1 + 0x6238))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4941
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9f1b * 0x4199) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x146279118",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9f1b * 0x4199) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4942
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7fa7 + 0x4295) - (0x8e2a << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1766c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7fa7 + 0x4295) - (0x8e2a << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4943
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x70ab >> 0x3) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3854",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x70ab >> 0x3) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4944
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe59c * 0xf035) * (0x1b35 * 0x1a4e))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x25a4bada566f148",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe59c * 0xf035) * (0x1b35 * 0x1a4e))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4945
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xac60 << 0x2) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x158c0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xac60 << 0x2) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4946
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7767 + 0x94da) * (0x8f67 - 0x19ab))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7b5eb4bc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7767 + 0x94da) * (0x8f67 - 0x19ab))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4947
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa08 - 0x70b3) * (0x8aeb >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x37b66cf9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa08 - 0x70b3) * (0x8aeb >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4948
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd476 << 0x0) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1a8e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd476 << 0x0) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4949
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1089 >> 0x3) - (0x9cac << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x9a9b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1089 >> 0x3) - (0x9cac << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4950
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8f71 - 0x2e5f) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x30890",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8f71 - 0x2e5f) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4951
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3fd8 >> 0x0) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3fd8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3fd8 >> 0x0) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4952
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5f7a * 0xbd77) - (0xb5f0 * 0xfbc1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x6c42063a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5f7a * 0xbd77) - (0xb5f0 * 0xfbc1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4953
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2939 >> 0x0) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa4e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2939 >> 0x0) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4954
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf000 << 0x3) - (0x6da8 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5c960",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf000 << 0x3) - (0x6da8 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4955
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x30c7 >> 0x3) + (0xe4e << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3f50",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x30c7 >> 0x3) + (0xe4e << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4956
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xcc17 + 0x693) - (0x436c + 0x5854))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x36ea",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xcc17 + 0x693) - (0x436c + 0x5854))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4957
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x679f >> 0x0) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x19e7c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x679f >> 0x0) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4958
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8de7 >> 0x0) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x46f38",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8de7 >> 0x0) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4959
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x212 + 0xc3fa) * (0x741b << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x167494d10",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x212 + 0xc3fa) * (0x741b << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4960
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9451 << 0x3) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x128a20",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9451 << 0x3) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4961
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x22ce >> 0x2) * (0x2f91 + 0x166e))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x260e94d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x22ce >> 0x2) * (0x2f91 + 0x166e))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4962
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x57ca << 0x1) + (0xb93f + 0xbb3b))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2240e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x57ca << 0x1) + (0xb93f + 0xbb3b))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4963
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf101 >> 0x1) - (0xf180 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x40",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf101 >> 0x1) - (0xf180 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4964
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5e4d >> 0x0) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1793",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5e4d >> 0x0) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4965
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc316 - 0xe17f) - (0x666b >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x519e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc316 - 0xe17f) - (0x666b >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4966
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x89ee >> 0x1) * (0xba02 * 0x1947))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4f2a1c23902",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x89ee >> 0x1) * (0xba02 * 0x1947))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4967
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa69b - 0xedac) + (0xd279 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x222b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa69b - 0xedac) + (0xd279 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4968
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1c46 + 0x7e46) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x9a8c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1c46 + 0x7e46) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4969
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfccd >> 0x0) + (0x8fa5 - 0x2e78))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x15dfa",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfccd >> 0x0) + (0x8fa5 - 0x2e78))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4970
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8a25 << 0x3) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x45128",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8a25 << 0x3) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4971
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf853 >> 0x1) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3e148",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf853 >> 0x1) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4972
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x465 + 0xab09) + (0x7fd4 + 0xd552))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x20494",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x465 + 0xab09) + (0x7fd4 + 0xd552))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4973
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf7e3 * 0xf2eb) - (0x129b + 0xc238))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xeb374e8e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf7e3 * 0xf2eb) - (0x129b + 0xc238))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4974
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x594b << 0x0) * (0xd9da * 0xc40f))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3a31dbe72902",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x594b << 0x0) * (0xd9da * 0xc40f))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4975
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe4e3 + 0xb156) - (0x2621 + 0xf2e7))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7d31",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe4e3 + 0xb156) - (0x2621 + 0xf2e7))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4976
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9e6a << 0x0) + (0xef11 - 0x9f0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1838b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9e6a << 0x0) + (0xef11 - 0x9f0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4977
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xeeda * 0x93ee) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x45029e56",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xeeda * 0x93ee) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4978
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8eda + 0x334a) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6112",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8eda + 0x334a) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4979
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6b3 * 0xb6ba) * (0x3680 * 0xddb6))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe1b2ee34ad7200",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6b3 * 0xb6ba) * (0x3680 * 0xddb6))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4980
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe2bd >> 0x2) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1c578",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe2bd >> 0x2) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4981
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8b7b * 0x2d40) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x629df700",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8b7b * 0x2d40) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4982
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf9e9 * 0x5c9f) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x169abcedc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf9e9 * 0x5c9f) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4983
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe04a >> 0x3) - (0x6f7b + 0xfc0b))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x14f7d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe04a >> 0x3) - (0x6f7b + 0xfc0b))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4984
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x662c - 0xc75b) * (0xf814 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xbc5a3f58",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x662c - 0xc75b) * (0xf814 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4985
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfb34 - 0x2df0) * (0xc41f >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x13a769cc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfb34 - 0x2df0) * (0xc41f >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4986
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xffbb - 0xe91a) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5a84",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xffbb - 0xe91a) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4987
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2043 << 0x0) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x810",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2043 << 0x0) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4988
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x401e * 0xd572) + (0x963a + 0x9eec))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3576b882",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x401e * 0xd572) + (0x963a + 0x9eec))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4989
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa0cc * 0xcec3) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x81dea364",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa0cc * 0xcec3) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4990
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x965c >> 0x1) * (0x4f6 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xba7b1a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x965c >> 0x1) * (0x4f6 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4991
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x49bf * 0xd8e1) + (0xee46 - 0xee4))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3e7ad841",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x49bf * 0xd8e1) + (0xee46 - 0xee4))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4992
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5bee - 0xbb85) + (0x8518 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1b4c9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5bee - 0xbb85) + (0x8518 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4993
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9039 + 0xd1e6) - (0xf291 - 0xbb1a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x12aa8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9039 + 0xd1e6) - (0xf291 - 0xbb1a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4994
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xcc88 >> 0x3) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3322",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xcc88 >> 0x3) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4995
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf479 << 0x2) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf479",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf479 << 0x2) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4996
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x259e * 0x970e) + (0x3f89 >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x16324895",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x259e * 0x970e) + (0x3f89 >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4997
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5c97 + 0x8290) + (0x95ff >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x17526",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5c97 + 0x8290) + (0x95ff >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 4998
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8ef8 << 0x2) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x477c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8ef8 << 0x2) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 4999
}
|
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