data_source
stringclasses 1
value | prompt
stringlengths 271
305
| ability
stringclasses 1
value | reward_model
dict | extra_info
dict |
|---|---|---|---|---|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6a86 << 0x3) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd50c0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6a86 << 0x3) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 400
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x56d3 * 0x4ae6) + (0x44c - 0x5b0c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1966a8d2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x56d3 * 0x4ae6) + (0x44c - 0x5b0c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 401
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdd89 * 0x4e44) + (0x8ca9 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x43befbac",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdd89 * 0x4e44) + (0x8ca9 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 402
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x68a0 * 0x965f) - (0x2818 * 0xd779))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1bb57808",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x68a0 * 0x965f) - (0x2818 * 0xd779))",
"source_dataset": "bitwise_arithmetic",
"source_index": 403
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa8b8 >> 0x1) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x545c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa8b8 >> 0x1) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 404
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6a5c << 0x1) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd4b8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6a5c << 0x1) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 405
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x17c - 0xcf2c) + (0x6e73 * 0xe8f3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x64804179",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x17c - 0xcf2c) + (0x6e73 * 0xe8f3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 406
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xad5d + 0x9af3) - (0x7dd4 - 0x1ac2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe53e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xad5d + 0x9af3) - (0x7dd4 - 0x1ac2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 407
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfcaa + 0x1df6) - (0xb4c3 + 0x8ca))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5d13",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfcaa + 0x1df6) - (0xb4c3 + 0x8ca))",
"source_dataset": "bitwise_arithmetic",
"source_index": 408
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc22 * 0xf924) - (0xb7b8 + 0x588d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xbcdb683",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc22 * 0xf924) - (0xb7b8 + 0x588d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 409
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x176b * 0xeb79) * (0x8614 >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x168f775b366",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x176b * 0xeb79) * (0x8614 >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 410
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb37a << 0x3) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x166f4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb37a << 0x3) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 411
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb290 * 0x4450) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xbe98340",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb290 * 0x4450) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 412
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd4b1 >> 0x1) + (0xfdfd - 0xe46c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x83e9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd4b1 >> 0x1) + (0xfdfd - 0xe46c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 413
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9f0e + 0xbc1b) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xad948",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9f0e + 0xbc1b) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 414
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbdab << 0x2) * (0xbc9f - 0xd39f))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x44297400",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbdab << 0x2) * (0xbc9f - 0xd39f))",
"source_dataset": "bitwise_arithmetic",
"source_index": 415
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfcfc + 0x4a38) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x28e6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfcfc + 0x4a38) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 416
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2d0b + 0xe94b) - (0x4fd1 * 0x1633))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x6eac64d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2d0b + 0xe94b) - (0x4fd1 * 0x1633))",
"source_dataset": "bitwise_arithmetic",
"source_index": 417
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa022 << 0x2) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x140440",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa022 << 0x2) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 418
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x973a >> 0x3) + (0x2d4f >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1890",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x973a >> 0x3) + (0x2d4f >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 419
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbd40 << 0x1) + (0xabbd + 0x98c1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2befe",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbd40 << 0x1) + (0xabbd + 0x98c1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 420
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd6cd + 0xd9b6) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x36106",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd6cd + 0xd9b6) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 421
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3bf3 - 0xca33) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x8e40",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3bf3 - 0xca33) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 422
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2f1a + 0x3b22) - (0x65b7 - 0x171c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1ba1",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2f1a + 0x3b22) - (0x65b7 - 0x171c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 423
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xebd2 - 0x2327) + (0xc7a6 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3e743",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xebd2 - 0x2327) + (0xc7a6 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 424
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe12f << 0x2) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x384bc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe12f << 0x2) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 425
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x30e0 + 0xb314) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x71fa0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x30e0 + 0xb314) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 426
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa64a << 0x0) * (0xbaf * 0x38c3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1aec7b95042",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa64a << 0x0) * (0xbaf * 0x38c3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 427
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe731 >> 0x3) * (0xd1e1 << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x17b12c26",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe731 >> 0x3) * (0xd1e1 << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 428
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc935 << 0x2) + (0xb8ea * 0x143c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xea0c3ac",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc935 << 0x2) + (0xb8ea * 0x143c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 429
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfe4 << 0x1) - (0xda0f * 0x2500))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1f840b38",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfe4 << 0x1) - (0xda0f * 0x2500))",
"source_dataset": "bitwise_arithmetic",
"source_index": 430
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(0xb765 + (0x49bf * 0xfb1f))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4857ea86",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "(0xb765 + (0x49bf * 0xfb1f))",
"source_dataset": "bitwise_arithmetic",
"source_index": 431
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4d5b - 0xed9f) + (0xf617 * 0x3629))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x340fa36b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4d5b - 0xed9f) + (0xf617 * 0x3629))",
"source_dataset": "bitwise_arithmetic",
"source_index": 432
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(0xa463 + (0xc71c << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3c0d3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "(0xa463 + (0xc71c << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 433
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9963 * 0x5c48) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6e956fb",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9963 * 0x5c48) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 434
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x90e9 - 0x95a3) + (0x763 - 0xa91d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xa674",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x90e9 - 0x95a3) + (0x763 - 0xa91d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 435
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4b84 + 0x6511) - (0x8f9f >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8cae",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4b84 + 0x6511) - (0x8f9f >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 436
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8839 >> 0x1) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x441c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8839 >> 0x1) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 437
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x36f2 << 0x2) * (0xd842 - 0xd2bb))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4bece78",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x36f2 << 0x2) * (0xd842 - 0xd2bb))",
"source_dataset": "bitwise_arithmetic",
"source_index": 438
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7714 - 0xa539) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xb894",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7714 - 0xa539) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 439
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8924 >> 0x2) * (0x3b0a >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3f414ed",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8924 >> 0x2) * (0x3b0a >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 440
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2f5 + 0xc33) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x794",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2f5 + 0xc33) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 441
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x763d + 0x3fbd) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x16bf4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x763d + 0x3fbd) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 442
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5be5 * 0x6466) - (0xd514 >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2409f69c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5be5 * 0x6466) - (0xd514 >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 443
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf0a5 - 0x8082) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x38118",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf0a5 - 0x8082) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 444
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x30b6 + 0x4564) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1d86",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x30b6 + 0x4564) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 445
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x674c >> 0x3) * (0x7c33 - 0x1394))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x546acb7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x674c >> 0x3) * (0x7c33 - 0x1394))",
"source_dataset": "bitwise_arithmetic",
"source_index": 446
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe249 >> 0x3) - (0xe6e + 0x8bf3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x7e18",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe249 >> 0x3) - (0xe6e + 0x8bf3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 447
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb12b >> 0x0) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x58958",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb12b >> 0x0) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 448
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa6cc >> 0x2) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5366",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa6cc >> 0x2) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 449
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8f8 * 0x959) + (0x37f1 - 0x2ccf))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x53e15a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8f8 * 0x959) + (0x37f1 - 0x2ccf))",
"source_dataset": "bitwise_arithmetic",
"source_index": 450
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8275 * 0xebc0) * (0xdf41 * 0x7fec))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x345a6ae5fb2c5900",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8275 * 0xebc0) * (0xdf41 * 0x7fec))",
"source_dataset": "bitwise_arithmetic",
"source_index": 451
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4739 << 0x2) - (0xdcae << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x9c78",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4739 << 0x2) - (0xdcae << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 452
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf7da + 0x93ec) - (0x99f3 * 0x5188))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x31062052",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf7da + 0x93ec) - (0x99f3 * 0x5188))",
"source_dataset": "bitwise_arithmetic",
"source_index": 453
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa3d4 * 0x3e93) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5016d578",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa3d4 * 0x3e93) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 454
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3ded * 0xa6ef) - (0x4dc9 + 0x8162))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2860af18",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3ded * 0xa6ef) - (0x4dc9 + 0x8162))",
"source_dataset": "bitwise_arithmetic",
"source_index": 455
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5f8e - 0xd7e2) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3c2a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5f8e - 0xd7e2) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 456
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4669 << 0x0) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x23348",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4669 << 0x0) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 457
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa3b0 * 0xc286) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1f184388",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa3b0 * 0xc286) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 458
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5721 * 0x88c6) * (0x5b0d * 0x746a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x78767f229c8334c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5721 * 0x88c6) * (0x5b0d * 0x746a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 459
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf67a - 0xe3e9) - (0xdce3 + 0xa5fe))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x17050",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf67a - 0xe3e9) - (0xdce3 + 0xa5fe))",
"source_dataset": "bitwise_arithmetic",
"source_index": 460
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5099 << 0x0) * (0xb41f << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x38b55687",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5099 << 0x0) * (0xb41f << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 461
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc1a8 + 0xd7fb) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6668",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc1a8 + 0xd7fb) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 462
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4c3c << 0x2) * (0x6887 >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7c824e90",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4c3c << 0x2) * (0x6887 >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 463
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6b24 >> 0x2) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd648",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6b24 >> 0x2) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 464
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7d3f - 0xa8ca) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x2b8b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7d3f - 0xa8ca) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 465
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x43f8 + 0x5ecc) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x28b10",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x43f8 + 0x5ecc) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 466
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb4dc - 0x2358) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x24610",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb4dc - 0x2358) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 467
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6949 << 0x0) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x34a4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6949 << 0x0) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 468
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbf51 << 0x1) + (0xd948 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1eb46",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbf51 << 0x1) + (0xd948 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 469
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5da1 << 0x3) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2ed08",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5da1 << 0x3) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 470
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xab36 - 0x70b2) - (0x5379 * 0xf62e))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x50450b3a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xab36 - 0x70b2) - (0x5379 * 0xf62e))",
"source_dataset": "bitwise_arithmetic",
"source_index": 471
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa69c << 0x3) - (0x51b0 * 0xd3ef))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x439b1e70",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa69c << 0x3) - (0x51b0 * 0xd3ef))",
"source_dataset": "bitwise_arithmetic",
"source_index": 472
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xcf38 + 0xefc7) * (0x81c7 * 0xcc54))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb4dd0b868ab4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xcf38 + 0xefc7) * (0x81c7 * 0xcc54))",
"source_dataset": "bitwise_arithmetic",
"source_index": 473
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xebbb >> 0x0) - (0x47b8 + 0x6c0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x9d43",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xebbb >> 0x0) - (0x47b8 + 0x6c0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 474
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xccdb << 0x3) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x666d8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xccdb << 0x3) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 475
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9369 * 0x42bf) * (0xbabe << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe049b0e8e490",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9369 * 0x42bf) * (0xbabe << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 476
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x221f - 0x4cb8) + (0x3a00 >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf67",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x221f - 0x4cb8) + (0x3a00 >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 477
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6820 << 0x1) + (0xe3c3 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x297c6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6820 << 0x1) + (0xe3c3 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 478
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd058 - 0x5c0d) * (0xd3e1 + 0xa7bf))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xac73b7e0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd058 - 0x5c0d) * (0xd3e1 + 0xa7bf))",
"source_dataset": "bitwise_arithmetic",
"source_index": 479
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc47a >> 0x1) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc47a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc47a >> 0x1) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 480
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2944 << 0x1) * (0xa08e >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x33c2c770",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2944 << 0x1) * (0xa08e >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 481
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5737 << 0x2) + (0x9406 + 0xca52))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2bb34",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5737 << 0x2) + (0x9406 + 0xca52))",
"source_dataset": "bitwise_arithmetic",
"source_index": 482
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xaed1 - 0x3073) + (0x9d1e - 0x4842))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd33a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xaed1 - 0x3073) + (0x9d1e - 0x4842))",
"source_dataset": "bitwise_arithmetic",
"source_index": 483
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6373 * 0xc4ac) - (0xf0ee >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4c65ec56",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6373 * 0xc4ac) - (0xf0ee >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 484
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x51cb - 0xc6df) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xea28",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x51cb - 0xc6df) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 485
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7e13 << 0x1) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1f84",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7e13 << 0x1) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 486
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf987 - 0xba05) - (0x6e25 - 0x3a8e))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xbeb",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf987 - 0xba05) - (0x6e25 - 0x3a8e))",
"source_dataset": "bitwise_arithmetic",
"source_index": 487
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd6a4 >> 0x3) + (0x64ac << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7f80",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd6a4 >> 0x3) + (0x64ac << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 488
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x96a7 << 0x3) - (0xd0d + 0x773c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x430ef",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x96a7 << 0x3) - (0xd0d + 0x773c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 489
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x57ad << 0x0) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x15eb",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x57ad << 0x0) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 490
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xacff << 0x3) * (0xd8b7 - 0x62bc))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x27dd14828",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xacff << 0x3) * (0xd8b7 - 0x62bc))",
"source_dataset": "bitwise_arithmetic",
"source_index": 491
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x28b6 >> 0x2) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x516",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x28b6 >> 0x2) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 492
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xad6e >> 0x1) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xad6e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xad6e >> 0x1) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 493
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8ef8 + 0xcf19) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2bc2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8ef8 + 0xcf19) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 494
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x85b0 << 0x3) - (0x48ac >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3e4d4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x85b0 << 0x3) - (0x48ac >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 495
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2b03 + 0x41d0) + (0xe291 + 0x2e21))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x17d85",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2b03 + 0x41d0) + (0xe291 + 0x2e21))",
"source_dataset": "bitwise_arithmetic",
"source_index": 496
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd976 + 0x25c6) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xff3c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd976 + 0x25c6) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 497
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9b6e * 0x750f) * (0x444a + 0x6492))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2ee123be8df8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9b6e * 0x750f) * (0x444a + 0x6492))",
"source_dataset": "bitwise_arithmetic",
"source_index": 498
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8be2 - 0x59a6) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6478",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8be2 - 0x59a6) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 499
}
|
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.