data_source
stringclasses 1
value | prompt
stringlengths 271
305
| ability
stringclasses 1
value | reward_model
dict | extra_info
dict |
|---|---|---|---|---|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7c8c + 0xf034) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5b30",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7c8c + 0xf034) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 300
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf345 + 0x865a) - (0x4115 + 0x4e84))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xea06",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf345 + 0x865a) - (0x4115 + 0x4e84))",
"source_dataset": "bitwise_arithmetic",
"source_index": 301
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xed53 >> 0x2) + (0xabc5 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2ea68",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xed53 >> 0x2) + (0xabc5 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 302
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1b10 << 0x2) + (0xfca4 - 0x4906))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x11fde",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1b10 << 0x2) + (0xfca4 - 0x4906))",
"source_dataset": "bitwise_arithmetic",
"source_index": 303
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1efe >> 0x2) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7bf",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1efe >> 0x2) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 304
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7fbc * 0x3188) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc5b6bf00",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7fbc * 0x3188) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 305
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd9d6 << 0x0) - (0xee89 - 0x6c95))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x57e2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd9d6 << 0x0) - (0xee89 - 0x6c95))",
"source_dataset": "bitwise_arithmetic",
"source_index": 306
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9172 << 0x2) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x245c8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9172 << 0x2) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 307
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa7c2 * 0x5bdd) - (0xea9e - 0x9801))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3c3275dd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa7c2 * 0x5bdd) - (0xea9e - 0x9801))",
"source_dataset": "bitwise_arithmetic",
"source_index": 308
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x52b0 * 0xbaf4) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x78c55f8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x52b0 * 0xbaf4) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 309
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2496 * 0x9810) - (0x1313 << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x15bb0d14",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2496 * 0x9810) - (0x1313 << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 310
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9911 + 0x8069) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8cbd0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9911 + 0x8069) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 311
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x178 - 0x1c12) + (0xa105 - 0xa987))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x231c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x178 - 0x1c12) + (0xa105 - 0xa987))",
"source_dataset": "bitwise_arithmetic",
"source_index": 312
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x26ce + 0x8fb2) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5b40",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x26ce + 0x8fb2) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 313
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x70af << 0x3) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1c2bc0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x70af << 0x3) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 314
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4622 - 0x2579) + (0xcc88 - 0x68dc))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8455",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4622 - 0x2579) + (0xcc88 - 0x68dc))",
"source_dataset": "bitwise_arithmetic",
"source_index": 315
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe4fd * 0x3141) - (0x2601 + 0xaf0c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2c0dbc30",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe4fd * 0x3141) - (0x2601 + 0xaf0c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 316
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdede << 0x2) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x37b78",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdede << 0x2) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 317
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf7d3 + 0x3608) * (0xe89c >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x112466974",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf7d3 + 0x3608) * (0xe89c >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 318
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6707 << 0x0) - (0x9f34 - 0x2b76))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xcb7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6707 << 0x0) - (0x9f34 - 0x2b76))",
"source_dataset": "bitwise_arithmetic",
"source_index": 319
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xedad * 0x3f69) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xeb7c3bd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xedad * 0x3f69) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 320
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1272 * 0x1642) + (0x132e << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x19b26d4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1272 * 0x1642) + (0x132e << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 321
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe41b + 0x7fc) + (0x2871 - 0x8811))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8c77",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe41b + 0x7fc) + (0x2871 - 0x8811))",
"source_dataset": "bitwise_arithmetic",
"source_index": 322
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x830f - 0x6436) - (0x2ec1 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x779",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x830f - 0x6436) - (0x2ec1 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 323
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb02a << 0x2) + (0x2823 + 0x675b))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x35026",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb02a << 0x2) + (0x2823 + 0x675b))",
"source_dataset": "bitwise_arithmetic",
"source_index": 324
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x693 << 0x2) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x349",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x693 << 0x2) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 325
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xefc9 - 0xc24b) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x16bf",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xefc9 - 0xc24b) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 326
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9e19 - 0x926) * (0x871c - 0x1d42))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3d9681ee",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9e19 - 0x926) * (0x871c - 0x1d42))",
"source_dataset": "bitwise_arithmetic",
"source_index": 327
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xab3e * 0xeb9c) * (0x9cb7 >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x607aaa9453f8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xab3e * 0xeb9c) * (0x9cb7 >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 328
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfb8c + 0x3e80) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x27418",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfb8c + 0x3e80) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 329
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x366c >> 0x3) * (0xc065 >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa3899c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x366c >> 0x3) * (0xc065 >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 330
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9dce - 0x9bbe) + (0x70e9 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x38958",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9dce - 0x9bbe) + (0x70e9 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 331
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2571 - 0xe076) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x2ec2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2571 - 0xe076) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 332
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc7e6 - 0xf7c4) - (0x510e >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x5865",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc7e6 - 0xf7c4) - (0x510e >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 333
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xab12 - 0x866d) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x12528",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xab12 - 0x866d) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 334
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1585 - 0xcaaa) + (0x7bbf + 0x3fb1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x64b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1585 - 0xcaaa) + (0x7bbf + 0x3fb1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 335
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xed05 - 0xb9b7) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x669c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xed05 - 0xb9b7) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 336
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xaf31 * 0x976a) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x19e79c52",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xaf31 * 0x976a) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 337
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8d2f << 0x3) * (0xce52 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe38fe160",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8d2f << 0x3) * (0xce52 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 338
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x49a1 + 0xa8a0) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7920",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x49a1 + 0xa8a0) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 339
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc472 >> 0x2) - (0xcb0f << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x16502",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc472 >> 0x2) - (0xcb0f << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 340
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7bdc - 0x1cf2) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2f75",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7bdc - 0x1cf2) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 341
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbeb2 >> 0x0) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x17d64",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbeb2 >> 0x0) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 342
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x50e * 0xed94) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x961c430",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x50e * 0xed94) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 343
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd81 << 0x0) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3604",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd81 << 0x0) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 344
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xcc5e - 0x37c5) + (0x82d9 * 0xd8bc))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6ec7c3f5",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xcc5e - 0x37c5) + (0x82d9 * 0xd8bc))",
"source_dataset": "bitwise_arithmetic",
"source_index": 345
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xae63 - 0x1626) * (0x5f16 - 0x3ddf))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x13c0921b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xae63 - 0x1626) * (0x5f16 - 0x3ddf))",
"source_dataset": "bitwise_arithmetic",
"source_index": 346
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8c32 << 0x1) * (0x2309 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4cbf0f08",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8c32 << 0x1) * (0x2309 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 347
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf31d >> 0x3) + (0xa338 * 0x473b))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2d6a444b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf31d >> 0x3) + (0xa338 * 0x473b))",
"source_dataset": "bitwise_arithmetic",
"source_index": 348
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2ab5 - 0xec72) - (0xe645 << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1a802",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2ab5 - 0xec72) - (0xe645 << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 349
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7e17 - 0x3730) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8dce",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7e17 - 0x3730) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 350
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7662 << 0x1) - (0xd787 - 0xf58d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x10aca",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7662 << 0x1) - (0xd787 - 0xf58d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 351
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x801c - 0x1495) - (0x2f29 - 0xa4b2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe110",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x801c - 0x1495) - (0x2f29 - 0xa4b2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 352
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfe12 >> 0x0) + (0xe7f6 * 0x1d51))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1a9140e8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfe12 >> 0x0) + (0xe7f6 * 0x1d51))",
"source_dataset": "bitwise_arithmetic",
"source_index": 353
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5947 - 0x6c8b) * (0x4872 >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xae71b8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5947 - 0x6c8b) * (0x4872 >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 354
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb2e3 + 0x47c5) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7d540",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb2e3 + 0x47c5) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 355
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x603c << 0x1) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x301e0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x603c << 0x1) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 356
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x195a - 0x2911) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1f7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x195a - 0x2911) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 357
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x91e1 + 0x7e33) * (0x6a4a << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x387b76e40",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x91e1 + 0x7e33) * (0x6a4a << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 358
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xcc71 * 0x9305) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xead1c26a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xcc71 * 0x9305) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 359
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x68d7 << 0x3) + (0xa252 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x48b5c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x68d7 << 0x3) + (0xa252 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 360
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe6e3 - 0x458f) * (0x2750 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc631b200",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe6e3 - 0x458f) * (0x2750 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 361
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x18ec >> 0x0) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc760",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x18ec >> 0x0) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 362
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9335 >> 0x0) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x24cd4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9335 >> 0x0) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 363
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4e5d >> 0x0) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x13974",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4e5d >> 0x0) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 364
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8bcf * 0x68c8) + (0xaf6d << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x393ecd20",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8bcf * 0x68c8) + (0xaf6d << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 365
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3d8a >> 0x0) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1ec50",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3d8a >> 0x0) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 366
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xea2d >> 0x0) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1d45",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xea2d >> 0x0) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 367
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1858 * 0xfe2b) * (0x360e << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa34f41b9de0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1858 * 0xfe2b) * (0x360e << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 368
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3ceb - 0xe77e) * (0xfee9 << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xa9d919cb",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3ceb - 0xe77e) * (0xfee9 << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 369
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1e44 - 0x4d40) + (0x78fe - 0x7b25))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3123",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1e44 - 0x4d40) + (0x78fe - 0x7b25))",
"source_dataset": "bitwise_arithmetic",
"source_index": 370
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb5ff >> 0x2) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb5fc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb5ff >> 0x2) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 371
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbf2c >> 0x1) * (0x11f0 * 0xfd30))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x69fbc639e00",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbf2c >> 0x1) * (0x11f0 * 0xfd30))",
"source_dataset": "bitwise_arithmetic",
"source_index": 372
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3888 - 0xea69) - (0x1157 - 0xf1ba))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2e82",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3888 - 0xea69) - (0x1157 - 0xf1ba))",
"source_dataset": "bitwise_arithmetic",
"source_index": 373
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xaace >> 0x2) + (0xe490 << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x10f43",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xaace >> 0x2) + (0xe490 << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 374
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4a34 << 0x0) + (0x115 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x52dc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4a34 << 0x0) + (0x115 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 375
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xaf8a * 0x83e7) + (0x2a40 + 0x6159))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5a728f1f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xaf8a * 0x83e7) + (0x2a40 + 0x6159))",
"source_dataset": "bitwise_arithmetic",
"source_index": 376
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5d9f * 0xb86d) - (0xab4e + 0xc975))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4370aff0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5d9f * 0xb86d) - (0xab4e + 0xc975))",
"source_dataset": "bitwise_arithmetic",
"source_index": 377
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc491 + 0xaae7) * (0x8bc + 0x8699))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xcdbe0ad8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc491 + 0xaae7) * (0x8bc + 0x8699))",
"source_dataset": "bitwise_arithmetic",
"source_index": 378
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xab57 << 0x2) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x55ab",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xab57 << 0x2) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 379
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9b80 >> 0x1) + (0x7792 + 0xebbc))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1b10e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9b80 >> 0x1) + (0x7792 + 0xebbc))",
"source_dataset": "bitwise_arithmetic",
"source_index": 380
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xef95 >> 0x3) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x77c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xef95 >> 0x3) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 381
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x12b3 << 0x1) - (0xc05a - 0x647f))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3675",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x12b3 << 0x1) - (0xc05a - 0x647f))",
"source_dataset": "bitwise_arithmetic",
"source_index": 382
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbe11 >> 0x1) - (0x9afe - 0xad03))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x710d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbe11 >> 0x1) - (0x9afe - 0xad03))",
"source_dataset": "bitwise_arithmetic",
"source_index": 383
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4f2d + 0x78df) * (0xfcdc >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3165ee94",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4f2d + 0x78df) * (0xfcdc >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 384
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2b95 + 0x4c0f) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3bd20",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2b95 + 0x4c0f) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 385
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe3e1 + 0x9aa7) + (0x8c0c * 0x1974))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xdee1ff8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe3e1 + 0x9aa7) + (0x8c0c * 0x1974))",
"source_dataset": "bitwise_arithmetic",
"source_index": 386
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x64a * 0x3ae1) + (0x6ef - 0xdb4a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x17176af",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x64a * 0x3ae1) + (0x6ef - 0xdb4a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 387
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x75a9 - 0x52e6) - (0x315a * 0x1352))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3b95a11",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x75a9 - 0x52e6) - (0x315a * 0x1352))",
"source_dataset": "bitwise_arithmetic",
"source_index": 388
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x16e + 0xad55) + (0x38ea - 0x889d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5f10",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x16e + 0xad55) + (0x38ea - 0x889d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 389
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7a65 << 0x1) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf4ca",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7a65 << 0x1) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 390
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9f58 << 0x2) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4fac0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9f58 << 0x2) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 391
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd191 >> 0x0) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd191",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd191 >> 0x0) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 392
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe51 * 0x9192) - (0x530a << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x823651e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe51 * 0x9192) - (0x530a << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 393
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3edb * 0x8e9a) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x230349be",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3edb * 0x8e9a) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 394
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x433 - 0x9880) + (0xa14f << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4762b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x433 - 0x9880) + (0xa14f << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 395
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xbe8f + 0xe908) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd3cb",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xbe8f + 0xe908) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 396
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdbaf >> 0x2) * (0xebcd << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xca56ccbc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdbaf >> 0x2) * (0xebcd << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 397
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3ce6 * 0x3605) + (0x8e32 * 0xa2bc))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x673dc536",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3ce6 * 0x3605) + (0x8e32 * 0xa2bc))",
"source_dataset": "bitwise_arithmetic",
"source_index": 398
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2816 >> 0x1) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x140b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2816 >> 0x1) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 399
}
|
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