data_source
stringclasses 1
value | prompt
stringlengths 271
305
| ability
stringclasses 1
value | reward_model
dict | extra_info
dict |
|---|---|---|---|---|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7d52 >> 0x1) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7d52",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7d52 >> 0x1) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 200
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7465 + 0x9126) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1058b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7465 + 0x9126) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 201
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7870 >> 0x2) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7870",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7870 >> 0x2) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 202
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd04b * 0xbe4a) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x26b4f7eb8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd04b * 0xbe4a) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 203
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x11cf * 0xbc19) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x345704d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x11cf * 0xbc19) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 204
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdfdc << 0x0) + (0x6d2d - 0x32e))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x149db",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdfdc << 0x0) + (0x6d2d - 0x32e))",
"source_dataset": "bitwise_arithmetic",
"source_index": 205
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb023 << 0x2) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb0230",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb023 << 0x2) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 206
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdd97 >> 0x3) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x376",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdd97 >> 0x3) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 207
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb504 + 0xb04) - (0xee43 - 0x60d0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3295",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb504 + 0xb04) - (0xee43 - 0x60d0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 208
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x75fe >> 0x3) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x75f8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x75fe >> 0x3) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 209
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8b65 * 0x2651) + (0x48b8 * 0x75a3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x36477e1d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8b65 * 0x2651) + (0x48b8 * 0x75a3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 210
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa804 - 0xa8e9) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x728",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa804 - 0xa8e9) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 211
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x38a3 * 0x1e8) * (0xbc8a * 0x7cea))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x26cc519ecbc1e0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x38a3 * 0x1e8) * (0xbc8a * 0x7cea))",
"source_dataset": "bitwise_arithmetic",
"source_index": 212
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9d53 * 0xc17f) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1dba67cb",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9d53 * 0xc17f) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 213
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x760b + 0xc698) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4f28c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x760b + 0xc698) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 214
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x870b >> 0x0) + (0xd517 + 0xbad8))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x216fa",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x870b >> 0x0) + (0xd517 + 0xbad8))",
"source_dataset": "bitwise_arithmetic",
"source_index": 215
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6f3b >> 0x1) + (0x125 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x37e6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6f3b >> 0x1) + (0x125 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 216
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xeb99 >> 0x1) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x75cc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xeb99 >> 0x1) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 217
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3720 << 0x0) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3720",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3720 << 0x0) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 218
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8ccb + 0xd457) + (0xcc72 * 0x3091))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x26ca8db4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8ccb + 0xd457) + (0xcc72 * 0x3091))",
"source_dataset": "bitwise_arithmetic",
"source_index": 219
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5dbe * 0xda3f) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x27f56ee1",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5dbe * 0xda3f) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 220
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xba82 << 0x1) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5d410",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xba82 << 0x1) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 221
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2ba6 >> 0x1) * (0xece9 + 0xd2bd))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x262993d2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2ba6 >> 0x1) * (0xece9 + 0xd2bd))",
"source_dataset": "bitwise_arithmetic",
"source_index": 222
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x86df << 0x2) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x436f8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x86df << 0x2) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 223
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7319 + 0xbde3) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x130fc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7319 + 0xbde3) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 224
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3ac + 0x8efd) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x92a9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3ac + 0x8efd) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 225
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc904 + 0x6c9a) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4d67",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc904 + 0x6c9a) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 226
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x509a >> 0x1) + (0xd9de >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x953c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x509a >> 0x1) + (0xd9de >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 227
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc94d >> 0x0) * (0xbd2 - 0xd986))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xa1c03324",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc94d >> 0x0) * (0xbd2 - 0xd986))",
"source_dataset": "bitwise_arithmetic",
"source_index": 228
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6069 - 0x87df) * (0xd683 << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x2110d562",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6069 - 0x87df) * (0xd683 << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 229
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x580b << 0x2) * (0xf0d1 - 0x8355))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x969d5150",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x580b << 0x2) * (0xf0d1 - 0x8355))",
"source_dataset": "bitwise_arithmetic",
"source_index": 230
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x95d8 >> 0x1) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4aec",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x95d8 >> 0x1) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 231
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7a7 - 0xaa04) * (0xc6d6 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3f0dd3df",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7a7 - 0xaa04) * (0xc6d6 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 232
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8fac * 0x4cb0) + (0xca35 * 0xa16d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xaa8b43d1",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8fac * 0x4cb0) + (0xca35 * 0xa16d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 233
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x46bd * 0x4869) - 0x6288)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1401c8fd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x46bd * 0x4869) - 0x6288)",
"source_dataset": "bitwise_arithmetic",
"source_index": 234
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2ce6 + 0x7a6b) - (0x9ff3 - 0x7967))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x80c5",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2ce6 + 0x7a6b) - (0x9ff3 - 0x7967))",
"source_dataset": "bitwise_arithmetic",
"source_index": 235
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa365 << 0x3) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x146ca0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa365 << 0x3) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 236
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x584b - 0x1749) + (0x374c - 0x7fba))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x76c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x584b - 0x1749) + (0x374c - 0x7fba))",
"source_dataset": "bitwise_arithmetic",
"source_index": 237
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x74b3 * 0x8d7f) + (0x7ea0 + 0xad07))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4081a774",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x74b3 * 0x8d7f) + (0x7ea0 + 0xad07))",
"source_dataset": "bitwise_arithmetic",
"source_index": 238
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf4ab << 0x1) * (0xcc19 + 0x9087))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x29a62bdc0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf4ab << 0x1) * (0xcc19 + 0x9087))",
"source_dataset": "bitwise_arithmetic",
"source_index": 239
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xfa47 << 0x1) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7d238",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xfa47 << 0x1) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 240
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf8f4 * 0xd905) - (0x7018 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd30ad094",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf8f4 * 0xd905) - (0x7018 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 241
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4d63 << 0x1) * (0x1306 - 0x54f4))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x27dc2a14",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4d63 << 0x1) * (0x1306 - 0x54f4))",
"source_dataset": "bitwise_arithmetic",
"source_index": 242
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x18ec << 0x2) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc760",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x18ec << 0x2) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 243
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb674 + 0x6a18) * (0x8963 - 0xac07))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x270b71b0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb674 + 0x6a18) * (0x8963 - 0xac07))",
"source_dataset": "bitwise_arithmetic",
"source_index": 244
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6bc5 - 0x9f23) * (0x79f - 0x267c))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6315c26",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6bc5 - 0x9f23) * (0x79f - 0x267c))",
"source_dataset": "bitwise_arithmetic",
"source_index": 245
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x797b << 0x3) * (0x7618 + 0x9fe8))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x41f5c9000",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x797b << 0x3) * (0x7618 + 0x9fe8))",
"source_dataset": "bitwise_arithmetic",
"source_index": 246
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x160d - 0x7263) * 0x736)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x299d424",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x160d - 0x7263) * 0x736)",
"source_dataset": "bitwise_arithmetic",
"source_index": 247
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x284 >> 0x1) * (0x1e60 << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2634c0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x284 >> 0x1) * (0x1e60 << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 248
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa265 << 0x3) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x144ca",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa265 << 0x3) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 249
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3229 * 0xefbe) * (0x53d4 >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7b0e5caec8c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3229 * 0xefbe) * (0x53d4 >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 250
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6a35 >> 0x3) + (0x1abd - 0xcecb))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xa6c8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6a35 >> 0x3) + (0x1abd - 0xcecb))",
"source_dataset": "bitwise_arithmetic",
"source_index": 251
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7075 + 0xb7c9) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4a0f8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7075 + 0xb7c9) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 252
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x525f << 0x3) * (0x3e13 * 0xba72))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x745f2bfa2e50",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x525f << 0x3) * (0x3e13 * 0xba72))",
"source_dataset": "bitwise_arithmetic",
"source_index": 253
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa2cb + 0xdb91) * (0xe38f << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x153e12964",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa2cb + 0xdb91) * (0xe38f << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 254
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd8f8 * 0x1d5e) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc71e1880",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd8f8 * 0x1d5e) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 255
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x523b - 0xbd22) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x6ae7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x523b - 0xbd22) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 256
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc754 >> 0x2) - (0xb48c >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x82b7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc754 >> 0x2) - (0xb48c >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 257
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x59b0 << 0x3) * (0x2a65 - 0x203a))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1c7f8480",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x59b0 << 0x3) * (0x2a65 - 0x203a))",
"source_dataset": "bitwise_arithmetic",
"source_index": 258
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf414 - 0xac19) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8ff6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf414 - 0xac19) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 259
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7a8f << 0x1) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3d47",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7a8f << 0x1) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 260
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf35d >> 0x2) - (0x295f << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x10e21",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf35d >> 0x2) - (0x295f << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 261
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xf38 << 0x2) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3ce0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xf38 << 0x2) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 262
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8603 * 0x2d58) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5ef2602",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8603 * 0x2d58) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 263
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc477 * 0xa0bf) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7b5cf4c9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc477 * 0xa0bf) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 264
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x863d * 0x7c18) * (0xaf7d + 0x6444))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x461788e413b8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x863d * 0x7c18) * (0xaf7d + 0x6444))",
"source_dataset": "bitwise_arithmetic",
"source_index": 265
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x458d >> 0x3) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x22c4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x458d >> 0x3) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 266
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3519 - 0x3c15) + (0x10dd << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3c78",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3519 - 0x3c15) + (0x10dd << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 267
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4a6c - 0xf24e) - (0xd9ef >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xde5d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4a6c - 0xf24e) - (0xd9ef >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 268
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x7a78 << 0x1) * (0x8972 + 0x6e6b))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xed270330",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x7a78 << 0x1) * (0x8972 + 0x6e6b))",
"source_dataset": "bitwise_arithmetic",
"source_index": 269
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x54b5 - 0xf992) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xa4dd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x54b5 - 0xf992) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 270
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x325c + 0xd780) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x213b8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x325c + 0xd780) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 271
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x3cf6 * 0x67bb) + (0xe466 >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x18b46618",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x3cf6 * 0x67bb) + (0xe466 >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 272
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x9688 * 0xa596) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc2bbb760",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x9688 * 0xa596) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 273
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd15a + 0xd9c9) + (0xc495 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7cfcb",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd15a + 0xd9c9) + (0xc495 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 274
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8f8e - 0x736a) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7090",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8f8e - 0x736a) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 275
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2b49 << 0x2) + (0x5c95 << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1664e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2b49 << 0x2) + (0x5c95 << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 276
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc8f8 >> 0x3) + (0xc724 - 0xbefc))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2147",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc8f8 >> 0x3) + (0xc724 - 0xbefc))",
"source_dataset": "bitwise_arithmetic",
"source_index": 277
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1b24 * 0x6c31) + (0xb648 >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb788f76",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1b24 * 0x6c31) + (0xb648 >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 278
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x5853 << 0x1) - (0x6da9 << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x2bca2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x5853 << 0x1) - (0x6da9 << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 279
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x4965 - 0x52b4) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x129e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x4965 - 0x52b4) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 280
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xe80 * 0x8c0d) + (0xf7ef << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7f29c3c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xe80 * 0x8c0d) + (0xf7ef << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 281
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd54c << 0x0) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1aa98",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd54c << 0x0) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 282
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x2cb0 + 0x5c01) - (0x3e81 - 0xaf0d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf93d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x2cb0 + 0x5c01) - (0x3e81 - 0xaf0d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 283
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x68d8 << 0x0) * (0x82b3 * 0x93b7))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1ee2c7f1e6b8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x68d8 << 0x0) * (0x82b3 * 0x93b7))",
"source_dataset": "bitwise_arithmetic",
"source_index": 284
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x26b3 - 0x3896) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x8f2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x26b3 - 0x3896) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 285
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc091 + 0x7d97) * (0x317b << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf5fa14e0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc091 + 0x7d97) * (0x317b << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 286
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6513 - 0x473d) * (0x7c46 + 0x519))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf13e86a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6513 - 0x473d) * (0x7c46 + 0x519))",
"source_dataset": "bitwise_arithmetic",
"source_index": 287
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x67e7 + 0x9087) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf86e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x67e7 + 0x9087) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 288
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xdfc9 - 0xd803) * (0x78be << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xeaa53d0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xdfc9 - 0xd803) * (0x78be << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 289
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xb473 << 0x3) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2d1cc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xb473 << 0x3) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 290
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1602 << 0x2) * (0xf695 - 0xcd4d))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xe320a40",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1602 << 0x2) * (0xf695 - 0xcd4d))",
"source_dataset": "bitwise_arithmetic",
"source_index": 291
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x6c91 << 0x2) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xd922",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x6c91 << 0x2) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 292
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xc2ea + 0xdc8b) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xcfba8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xc2ea + 0xdc8b) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 293
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
0xc0ff
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc0ff",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "0xc0ff",
"source_dataset": "bitwise_arithmetic",
"source_index": 294
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x8466 + 0x8878) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x10cde",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x8466 + 0x8878) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 295
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xd5b1 - 0xb4e1) * (0xb5f1 * 0x78bb))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xaff732698f0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xd5b1 - 0xb4e1) * (0xb5f1 * 0x78bb))",
"source_dataset": "bitwise_arithmetic",
"source_index": 296
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa25c >> 0x0) - (0x7987 * 0xd88e))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x66ccae86",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa25c >> 0x0) - (0x7987 * 0xd88e))",
"source_dataset": "bitwise_arithmetic",
"source_index": 297
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0x1f68 >> 0x2) + (0xb434 - 0x8652))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x35bc",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0x1f68 >> 0x2) + (0xb434 - 0x8652))",
"source_dataset": "bitwise_arithmetic",
"source_index": 298
}
|
bitwise_arithmetic_L2
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
((0xa16 + 0xda1e) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1c86",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 2
},
"problem": "((0xa16 + 0xda1e) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 299
}
|
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