data_source
stringclasses 1
value | prompt
stringlengths 271
349
| ability
stringclasses 1
value | reward_model
dict | extra_info
dict |
|---|---|---|---|---|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xae6 * 0x1a13) * (0x8fb9 >> 0x0)) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x9f896a2e02",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xae6 * 0x1a13) * (0x8fb9 >> 0x0)) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 100
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x7fb4 << 0x1) - (0x4ca4 >> 0x3)) + ((0xa42a << 0x0) >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x11ede",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x7fb4 << 0x1) - (0x4ca4 >> 0x3)) + ((0xa42a << 0x0) >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 101
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xaafd + 0x69dc) - (0x7832 - 0xb06f)) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x14d16",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xaafd + 0x69dc) - (0x7832 - 0xb06f)) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 102
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xbcbf * 0xcc4c) + (0x9288 << 0x2)) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4b51436a0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xbcbf * 0xcc4c) + (0x9288 << 0x2)) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 103
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xe6f7 * 0x169c) + (0x37dc + 0xfa83)) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x14672ae3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xe6f7 * 0x169c) + (0x37dc + 0xfa83)) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 104
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x2fca << 0x2) << 0x2) - ((0x5795 * 0xbadf) << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x7fda1cf6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x2fca << 0x2) << 0x2) - ((0x5795 * 0xbadf) << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 105
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x46cf * 0x1c24) << 0x1) + ((0x5757 << 0x2) << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf93ecf0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x46cf * 0x1c24) << 0x1) + ((0x5757 << 0x2) << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 106
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x94f8 - 0xb0f) - (0x4e40 + 0xcf36)) * ((0x17d0 << 0x0) << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x6dcc6c80",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x94f8 - 0xb0f) - (0x4e40 + 0xcf36)) * ((0x17d0 << 0x0) << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 107
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x2ab4 - 0x6c8a) * (0x563e * 0x4900)) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x194c47e5d000",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x2ab4 - 0x6c8a) * (0x563e * 0x4900)) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 108
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x1eb9 >> 0x3) * (0x1c68 << 0x3)) - ((0x1fcc >> 0x1) - (0xbbd9 - 0xdf5e)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3686755",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x1eb9 >> 0x3) * (0x1c68 << 0x3)) - ((0x1fcc >> 0x1) - (0xbbd9 - 0xdf5e)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 109
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xa0ea + 0x56d) << 0x3) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2995c0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xa0ea + 0x56d) << 0x3) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 110
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xcb7c >> 0x2) << 0x2) + ((0xd6f8 - 0xe48f) >> 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc816",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xcb7c >> 0x2) << 0x2) + ((0xd6f8 - 0xe48f) >> 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 111
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xe3b2 + 0x749e) - (0x6e1e << 0x0)) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3a8c8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xe3b2 + 0x749e) - (0x6e1e << 0x0)) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 112
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x8b26 << 0x3) * (0xfc90 >> 0x1)) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2251eb580",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x8b26 << 0x3) * (0xfc90 >> 0x1)) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 113
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xdff6 - 0xec01) - (0x7306 >> 0x2)) - ((0x7108 + 0xf291) + (0x62b4 << 0x0)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1ef19",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xdff6 - 0xec01) - (0x7306 >> 0x2)) - ((0x7108 + 0xf291) + (0x62b4 << 0x0)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 114
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x5251 - 0xd1f2) + (0x3a64 - 0xbd9f)) - ((0x6906 << 0x2) + (0x1b25 >> 0x3)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x2aa58",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x5251 - 0xd1f2) + (0x3a64 - 0xbd9f)) - ((0x6906 << 0x2) + (0x1b25 >> 0x3)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 115
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xc65d >> 0x2) + (0xa4f6 << 0x0)) - ((0xf81 + 0x15dc) + (0x4759 >> 0x1)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x8d84",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xc65d >> 0x2) + (0xa4f6 << 0x0)) - ((0xf81 + 0x15dc) + (0x4759 >> 0x1)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 116
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xc16a + 0xb814) - (0x46f9 + 0xaca0)) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x42f28",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xc16a + 0xb814) - (0x46f9 + 0xaca0)) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 117
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x7f24 >> 0x1) >> 0x2) * ((0x5f78 >> 0x2) + (0xf16a * 0xc04d)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb41ada63b00",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x7f24 >> 0x1) >> 0x2) * ((0x5f78 >> 0x2) + (0xf16a * 0xc04d)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 118
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x7dcf << 0x0) >> 0x0) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xfb9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x7dcf << 0x0) >> 0x0) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 119
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xfad8 >> 0x2) << 0x3) - ((0x563 >> 0x2) >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1f458",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xfad8 >> 0x2) << 0x3) - ((0x563 >> 0x2) >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 120
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x387e * 0x5b38) - (0x2522 - 0x2e64)) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x14212ed2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x387e * 0x5b38) - (0x2522 - 0x2e64)) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 121
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x6366 >> 0x0) * (0xd4fa + 0xde19)) * ((0xa549 * 0x1d42) - (0xf2c7 >> 0x0)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc76762314d0fa46",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x6366 >> 0x0) * (0xd4fa + 0xde19)) * ((0xa549 * 0x1d42) - (0xf2c7 >> 0x0)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 122
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xe5ab << 0x2) - (0x33cc + 0x1221)) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1a85f8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xe5ab << 0x2) - (0x33cc + 0x1221)) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 123
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x7dc1 + 0xbf5c) + (0x4b36 * 0xae5c)) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xccebe21",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x7dc1 + 0xbf5c) + (0x4b36 * 0xae5c)) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 124
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xd10a + 0xbf39) * (0x9de8 << 0x3)) + ((0x18a8 + 0x271f) - (0xf16 << 0x2)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x7b71ea12f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xd10a + 0xbf39) * (0x9de8 << 0x3)) + ((0x18a8 + 0x271f) - (0xf16 << 0x2)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 125
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x33a1 - 0xde08) - (0x9cfb << 0x3)) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x16490",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x33a1 - 0xde08) - (0x9cfb << 0x3)) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 126
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xd5b5 * 0xc158) >> 0x0) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa166eb38",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xd5b5 * 0xc158) >> 0x0) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 127
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x959b * 0x2022) + (0x64c1 + 0xe934)) >> 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4b22322",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x959b * 0x2022) + (0x64c1 + 0xe934)) >> 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 128
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xd472 >> 0x3) << 0x2) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x351c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xd472 >> 0x3) << 0x2) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 129
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x7710 << 0x3) * (0x9393 - 0xbea3)) - ((0x9454 * 0xe22c) + (0x114 << 0x1)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x12344b098",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x7710 << 0x3) * (0x9393 - 0xbea3)) - ((0x9454 * 0xe22c) + (0x114 << 0x1)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 130
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x5a4d + 0xb38d) - 0xbdf2) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x9fd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x5a4d + 0xb38d) - 0xbdf2) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 131
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xdd44 - 0x3eeb) << 0x2) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x27964",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xdd44 - 0x3eeb) << 0x2) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 132
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x9944 * 0xe017) >> 0x0) + ((0xc8d1 >> 0x1) >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x86297750",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x9944 * 0xe017) >> 0x0) + ((0xc8d1 >> 0x1) >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 133
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x7cbf >> 0x0) << 0x2) - ((0x8f61 * 0xa423) * (0xf8f5 << 0x0)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x59664ad60b23",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x7cbf >> 0x0) << 0x2) - ((0x8f61 * 0xa423) * (0xf8f5 << 0x0)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 134
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xc16 << 0x2) - (0xdacb * 0x180d)) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x148df3f7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xc16 << 0x2) - (0xdacb * 0x180d)) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 135
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xec6c * 0xbbdc) - (0x3064 * 0x154a)) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x152efbfd",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xec6c * 0xbbdc) - (0x3064 * 0x154a)) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 136
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x4eea >> 0x0) + (0x395d * 0xda5b)) - ((0xbbd7 << 0x1) * (0x99d1 - 0x9f37)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x38d9fa4d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x4eea >> 0x0) + (0x395d * 0xda5b)) - ((0xbbd7 << 0x1) * (0x99d1 - 0x9f37)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 137
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x4024 << 0x0) + (0xa79f + 0x8b8)) + ((0x8700 << 0x0) + (0xc954 + 0x3ce4)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x27db3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x4024 << 0x0) + (0xa79f + 0x8b8)) + ((0x8700 << 0x0) + (0xc954 + 0x3ce4)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 138
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xc1ea * 0x5608) * (0xc06e << 0x1)) + ((0x5e40 * 0x48e9) + (0x64e8 >> 0x3)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x61f81c7b0d9d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xc1ea * 0x5608) * (0xc06e << 0x1)) + ((0x5e40 * 0x48e9) + (0x64e8 >> 0x3)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 139
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x14cb * 0xc9db) * (0xa1e1 + 0x82be)) - ((0x5f1b - 0xc362) * (0x28fc + 0x9308)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x12bddf6d3613",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x14cb * 0xc9db) * (0xa1e1 + 0x82be)) - ((0x5f1b - 0xc362) * (0x28fc + 0x9308)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 140
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x85f7 + 0xddb1) - (0x138a + 0x6eb9)) + ((0x743a + 0xcf6) - (0xc78 >> 0x3)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x16106",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x85f7 + 0xddb1) - (0x138a + 0x6eb9)) + ((0x743a + 0xcf6) - (0xc78 >> 0x3)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 141
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x8960 >> 0x1) * (0xacdd >> 0x1)) - ((0x1255 - 0xda86) * (0xa694 - 0xc903)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3bcab9f",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x8960 >> 0x1) * (0xacdd >> 0x1)) - ((0x1255 - 0xda86) * (0xa694 - 0xc903)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 142
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x7ae3 << 0x3) * (0xc7bf >> 0x1)) + ((0x7d8 >> 0x1) * (0x4386 << 0x2)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x183a9ec08",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x7ae3 << 0x3) * (0xc7bf >> 0x1)) + ((0x7d8 >> 0x1) * (0x4386 << 0x2)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 143
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xafab << 0x0) << 0x3) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x57d58",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xafab << 0x0) << 0x3) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 144
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xd1c6 + 0x9595) - (0xbd31 << 0x3)) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x1208b4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xd1c6 + 0x9595) - (0xbd31 << 0x3)) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 145
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x654f * 0x4483) + (0x4509 * 0xfc73)) - ((0x7a50 << 0x0) + (0x5121 + 0x67b9)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5f2f7f4e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x654f * 0x4483) + (0x4509 * 0xfc73)) - ((0x7a50 << 0x0) + (0x5121 + 0x67b9)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 146
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xbd0f << 0x0) >> 0x2) * ((0x7595 + 0x892c) + (0x2ac1 << 0x1)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3ed15a89",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xbd0f << 0x0) >> 0x2) * ((0x7595 + 0x892c) + (0x2ac1 << 0x1)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 147
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xf54f << 0x1) - (0xf3d >> 0x0)) * ((0xd600 << 0x2) * (0xdd45 + 0x733b)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x82962f9ac0000",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xf54f << 0x1) - (0xf3d >> 0x0)) * ((0xd600 << 0x2) * (0xdd45 + 0x733b)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 148
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xc4c2 << 0x3) >> 0x3) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc4c2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xc4c2 << 0x3) >> 0x3) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 149
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xe8ef * 0x6e1c) * (0x6017 - 0x30bd)) * ((0x4579 - 0x751f) << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xdcbfd6fa24013c0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xe8ef * 0x6e1c) * (0x6017 - 0x30bd)) * ((0x4579 - 0x751f) << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 150
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x73a - 0x50d8) >> 0x1) - ((0xa952 * 0x53db) << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xddd9e167",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x73a - 0x50d8) >> 0x1) - ((0xa952 * 0x53db) << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 151
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xbe76 * 0xd4a1) * (0x8c9b << 0x3)) + ((0x20db << 0x1) + (0xef7e >> 0x2)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2b716d0b1c325",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xbe76 * 0xd4a1) * (0x8c9b << 0x3)) + ((0x20db << 0x1) + (0xef7e >> 0x2)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 152
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xb72e * 0x9102) - (0xdc3e * 0x5847)) + ((0xc837 << 0x1) >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1bd1a798",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xb72e * 0x9102) - (0xdc3e * 0x5847)) + ((0xc837 << 0x1) >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 153
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xcdcd * 0x152d) - (0x821f - 0x480a)) + ((0x4759 >> 0x2) - (0xf77e + 0xba52)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x110423fa",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xcdcd * 0x152d) - (0x821f - 0x480a)) + ((0x4759 >> 0x2) - (0xf77e + 0xba52)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 154
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x95db + 0x7d0f) - (0xf58c - 0x95d5)) - ((0x2801 - 0x96cb) - (0x7f4f << 0x2)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x31f39",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x95db + 0x7d0f) - (0xf58c - 0x95d5)) - ((0x2801 - 0x96cb) - (0x7f4f << 0x2)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 155
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x4b79 >> 0x3) << 0x3) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x25bc0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x4b79 >> 0x3) << 0x3) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 156
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x5a99 >> 0x1) * (0xc607 * 0x8937)) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x963f1ef65a60",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x5a99 >> 0x1) * (0xc607 * 0x8937)) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 157
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xeb96 * 0x3ef) + (0xb8f8 - 0x527)) - ((0xa6f8 - 0xdb52) << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x3a109ab",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xeb96 * 0x3ef) + (0xb8f8 - 0x527)) - ((0xa6f8 - 0xdb52) << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 158
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x9fe7 << 0x2) * (0x9d2a >> 0x1)) * ((0x380f - 0xe8b9) << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x877d5e76e978",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x9fe7 << 0x2) * (0x9d2a >> 0x1)) * ((0x380f - 0xe8b9) << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 159
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xf923 << 0x3) - (0xa3c << 0x2)) << 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xf4050",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xf923 << 0x3) - (0xa3c << 0x2)) << 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 160
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xfafb >> 0x2) - (0xc769 + 0x4097)) << 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x64a10",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xfafb >> 0x2) - (0xc769 + 0x4097)) << 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 161
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xddae << 0x0) - (0x54ce - 0xf8a1)) + ((0xdd91 >> 0x1) << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x25f11",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xddae << 0x0) - (0x54ce - 0xf8a1)) + ((0xdd91 >> 0x1) << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 162
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xf9a4 - 0xfaca) << 0x1) + ((0xbb6a * 0xf50e) - (0x4d49 >> 0x2)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xb3669c2e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xf9a4 - 0xfaca) << 0x1) + ((0xbb6a * 0xf50e) - (0x4d49 >> 0x2)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 163
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
0x4f1a
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4f1a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "0x4f1a",
"source_dataset": "bitwise_arithmetic",
"source_index": 164
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xad7a + 0xf4cc) - (0xda42 << 0x0)) >> 0x1)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6402",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xad7a + 0xf4cc) - (0xda42 << 0x0)) >> 0x1)",
"source_dataset": "bitwise_arithmetic",
"source_index": 165
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xa052 >> 0x3) >> 0x1) - ((0xecd2 >> 0x3) * (0x9e6a * 0x35a8)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x3d6da74929b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xa052 >> 0x3) >> 0x1) - ((0xecd2 >> 0x3) * (0x9e6a * 0x35a8)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 166
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x14f3 - 0x5e8c) >> 0x2) + ((0xd928 << 0x0) * (0x3b3d - 0x91e5)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x498204a7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x14f3 - 0x5e8c) >> 0x2) + ((0xd928 << 0x0) * (0x3b3d - 0x91e5)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 167
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xb3d - 0xa235) + (0xaead >> 0x0)) << 0x2)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x5ed4",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xb3d - 0xa235) + (0xaead >> 0x0)) << 0x2)",
"source_dataset": "bitwise_arithmetic",
"source_index": 168
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x58c9 >> 0x1) >> 0x2) - ((0x8b21 * 0x3ff3) >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x11608c90",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x58c9 >> 0x1) >> 0x2) - ((0x8b21 * 0x3ff3) >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 169
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x28e0 - 0xee90) + (0xfd9a - 0xc3fb)) + ((0x4ad7 << 0x0) - (0x2a07 + 0x9b6)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x74f7",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x28e0 - 0xee90) + (0xfd9a - 0xc3fb)) + ((0x4ad7 << 0x0) - (0x2a07 + 0x9b6)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 170
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xea97 >> 0x1) - (0xe985 >> 0x2)) - ((0xcf50 - 0x947f) << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xb05a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xea97 >> 0x1) - (0xe985 >> 0x2)) - ((0xcf50 - 0x947f) << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 171
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x69ba - 0xbed) >> 0x1) * ((0xc1d3 + 0xfe4b) >> 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x290bff7a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x69ba - 0xbed) >> 0x1) * ((0xc1d3 + 0xfe4b) >> 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 172
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x8c2e + 0x6141) * (0xd093 + 0x1e5b)) * ((0x8147 + 0xcc6c) - (0x866d << 0x3)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x2820b3f31d85a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x8c2e + 0x6141) * (0xd093 + 0x1e5b)) * ((0x8147 + 0xcc6c) - (0x866d << 0x3)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 173
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x94b5 + 0x760) << 0x3) - ((0x1980 + 0xb45e) * (0x9ce7 + 0x105a)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x8b4e6ab6",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x94b5 + 0x760) << 0x3) - ((0x1980 + 0xb45e) * (0x9ce7 + 0x105a)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 174
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x45cf - 0xc09a) - (0x8dc3 << 0x1)) - ((0x9075 + 0xeba4) * (0xcacc + 0x41e6)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x18ef40bb3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x45cf - 0xc09a) - (0x8dc3 << 0x1)) - ((0x9075 + 0xeba4) * (0xcacc + 0x41e6)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 175
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xdbfd - 0xe9fb) >> 0x3) + ((0xa28b - 0x974b) * (0x7797 << 0x1)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa82c3c0",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xdbfd - 0xe9fb) >> 0x3) + ((0xa28b - 0x974b) * (0x7797 << 0x1)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 176
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xc90f + 0x4a1c) * (0xfb9e * 0x7a03)) * ((0x5e7c << 0x1) + (0xb3a - 0x45af)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x41b73a1ca1bec0da",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xc90f + 0x4a1c) * (0xfb9e * 0x7a03)) * ((0x5e7c << 0x1) + (0xb3a - 0x45af)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 177
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x6b13 << 0x1) << 0x1) - ((0x96a3 + 0xde07) << 0x2))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x4265c",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x6b13 << 0x1) << 0x1) - ((0x96a3 + 0xde07) << 0x2))",
"source_dataset": "bitwise_arithmetic",
"source_index": 178
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xd944 - 0xc459) >> 0x0) + ((0x6bef - 0x7fb9) + (0xed92 - 0xe4fa)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x9b9",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xd944 - 0xc459) >> 0x0) + ((0x6bef - 0x7fb9) + (0xed92 - 0xe4fa)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 179
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x72e9 - 0xbe7e) + (0x1438 << 0x0)) - ((0xac52 << 0x1) << 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0xafc7d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x72e9 - 0xbe7e) + (0x1438 << 0x0)) - ((0xac52 << 0x1) << 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 180
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xc797 + 0xc904) >> 0x2) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x6426",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xc797 + 0xc904) >> 0x2) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 181
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x6e22 + 0xea56) >> 0x2) - ((0xeefe << 0x1) + (0x61b4 * 0x664c)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x270c414e",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x6e22 + 0xea56) >> 0x2) - ((0xeefe << 0x1) + (0x61b4 * 0x664c)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 182
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x5f00 - 0xe2df) >> 0x1) - ((0x3eb7 >> 0x1) >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x45db",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x5f00 - 0xe2df) >> 0x1) - ((0x3eb7 >> 0x1) >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 183
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xf265 * 0xf122) + (0xd330 << 0x2)) >> 0x3)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1c8a9265",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xf265 * 0xf122) + (0xd330 << 0x2)) >> 0x3)",
"source_dataset": "bitwise_arithmetic",
"source_index": 184
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x9be << 0x0) - (0x1348 - 0xd893)) * ((0x5d6a * 0xdac7) + (0xcefe - 0xd6d2)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x408fea68b422",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x9be << 0x0) - (0x1348 - 0xd893)) * ((0x5d6a * 0xdac7) + (0xcefe - 0xd6d2)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 185
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xb359 >> 0x3) - (0xfa20 - 0xcf73)) - ((0xcb2e - 0x4f77) >> 0x3))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x23b8",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xb359 >> 0x3) - (0xfa20 - 0xcf73)) - ((0xcb2e - 0x4f77) >> 0x3))",
"source_dataset": "bitwise_arithmetic",
"source_index": 186
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x9e33 - 0x2cac) << 0x0) - ((0xba06 + 0x51c0) - (0xffbf + 0xf50a)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x15a8a",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x9e33 - 0x2cac) << 0x0) - ((0xba06 + 0x51c0) - (0xffbf + 0xf50a)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 187
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xc512 << 0x3) >> 0x0) * ((0xd147 * 0xebe3) - (0xe8fd << 0x3)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x4a363810aff50",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xc512 << 0x3) >> 0x0) * ((0xd147 * 0xebe3) - (0xe8fd << 0x3)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 188
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x3c3c >> 0x2) * (0xb89d * 0xf323)) - ((0x2053 << 0x0) * (0xdebd - 0xc635)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xa5050f807e1",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x3c3c >> 0x2) * (0xb89d * 0xf323)) - ((0x2053 << 0x0) * (0xdebd - 0xc635)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 189
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xd307 * 0x48dc) + (0x6c20 - 0x2a61)) - ((0x5d91 * 0xa230) + (0x4632 - 0x730a)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xc8736b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xd307 * 0x48dc) + (0x6c20 - 0x2a61)) - ((0x5d91 * 0xa230) + (0x4632 - 0x730a)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 190
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xd642 + 0x1b31) << 0x1) - ((0x7c45 + 0x5355) - (0x7d2d * 0x87b5)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x425c4f1d",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xd642 + 0x1b31) << 0x1) - ((0x7c45 + 0x5355) - (0x7d2d * 0x87b5)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 191
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xdfc6 << 0x1) << 0x0) + ((0x6485 + 0xc843) << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x2ec54",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xdfc6 << 0x1) << 0x0) + ((0x6485 + 0xc843) << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 192
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x4165 + 0xe33d) - (0x10fa + 0xdfc9)) >> 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x33df",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x4165 + 0xe33d) - (0x10fa + 0xdfc9)) >> 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 193
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xc1b7 - 0x96d2) * (0x9883 - 0xb382)) << 0x0)
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x485fc1b",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xc1b7 - 0x96d2) * (0x9883 - 0xb382)) << 0x0)",
"source_dataset": "bitwise_arithmetic",
"source_index": 194
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x82f1 - 0xbcf4) << 0x3) - ((0x801f * 0x4421) >> 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x221a9017",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x82f1 - 0xbcf4) << 0x3) - ((0x801f * 0x4421) >> 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 195
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x1ee3 - 0x89b9) + (0xbd6 >> 0x1)) + ((0x4bc6 << 0x2) << 0x1))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1f945",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x1ee3 - 0x89b9) + (0xbd6 >> 0x1)) + ((0x4bc6 << 0x2) << 0x1))",
"source_dataset": "bitwise_arithmetic",
"source_index": 196
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0x6987 * 0x462) << 0x1) - ((0x1e94 + 0xf3a) + (0x7ae4 * 0x798)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "-0x85dd2",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0x6987 * 0x462) << 0x1) - ((0x1e94 + 0xf3a) + (0x7ae4 * 0x798)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 197
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xf2ca >> 0x2) * (0x40a8 + 0x15f)) + ((0xde6e >> 0x1) << 0x0))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0xfa7fc15",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xf2ca >> 0x2) * (0x40a8 + 0x15f)) + ((0xde6e >> 0x1) << 0x0))",
"source_dataset": "bitwise_arithmetic",
"source_index": 198
}
|
bitwise_arithmetic_L3
|
Please solve this problem. Assume there is arbitrary bit depth and that there are signed integers. If the answer is negative, reply as a negative value (ex., -0x3), not the two's-compliment form.
(((0xda52 >> 0x2) + (0xb9bc * 0x246e)) + ((0x3ced >> 0x1) + (0xcb0c - 0xeeb)))
Let's think step by step and output the final answer within \boxed{}.
|
bitwise_arithmetic
|
{
"ground_truth": "0x1a6f4ff3",
"style": "rule"
}
|
{
"difficulty": {
"difficulty": 3
},
"problem": "(((0xda52 >> 0x2) + (0xb9bc * 0x246e)) + ((0x3ced >> 0x1) + (0xcb0c - 0xeeb)))",
"source_dataset": "bitwise_arithmetic",
"source_index": 199
}
|
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