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Provide tags and a correct Python 3 solution for this coding contest problem.
This is an interactive problem.
Homer likes arrays a lot and he wants to play a game with you.
Homer has hidden from you a permutation a_1, a_2, ..., a_n of integers 1 to n. You are asked to find any index k (1 β€ k β€ n) which is a local minimum.
For an array a_1, a_2, ..., a_n, an index i (1 β€ i β€ n) is said to be a local minimum if a_i < min\\{a_{i-1},a_{i+1}\}, where a_0 = a_{n+1} = +β. An array is said to be a permutation of integers 1 to n, if it contains all integers from 1 to n exactly once.
Initially, you are only given the value of n without any other information about this permutation.
At each interactive step, you are allowed to choose any i (1 β€ i β€ n) and make a query with it. As a response, you will be given the value of a_i.
You are asked to find any index k which is a local minimum after at most 100 queries.
Interaction
You begin the interaction by reading an integer n (1β€ n β€ 10^5) on a separate line.
To make a query on index i (1 β€ i β€ n), you should output "? i" in a separate line. Then read the value of a_i in a separate line. The number of the "?" queries is limited within 100.
When you find an index k (1 β€ k β€ n) which is a local minimum, output "! k" in a separate line and terminate your program.
In case your query format is invalid, or you have made more than 100 "?" queries, you will receive Wrong Answer verdict.
After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
Hack Format
The first line of the hack should contain a single integer n (1 β€ n β€ 10^5).
The second line should contain n distinct integers a_1, a_2, ..., a_n (1 β€ a_i β€ n).
Example
Input
5
3
2
1
4
5
Output
? 1
? 2
? 3
? 4
? 5
! 3
Note
In the example, the first line contains an integer 5 indicating that the length of the array is n = 5.
The example makes five "?" queries, after which we conclude that the array is a = [3,2,1,4,5] and k = 3 is local minimum.
Tags: binary search, interactive, ternary search
Correct Solution:
```
from collections import deque
from typing import List
from sys import stdout
class ContestParser:
"""Helper module to read/write
Commonly in programming competition input for a problem is given with space separated numbers and strings.
Standard python input() functionality is clunky when dealing with such input. This parser can tokenize inputs and convert them to proper types.
"""
def __init__(self):
self.buffer = deque()
def next_token(self) -> str:
if len(self.buffer) == 0:
self.buffer.extend(input().split())
return self.buffer.popleft()
def next_int(self) -> int:
return int(self.next_token())
parser = ContestParser()
def ask(v: int) -> int:
print("? {}".format(v))
stdout.flush()
return parser.next_int()
def answer(v: int) -> int:
print("! {}".format(v))
if __name__ == '__main__':
n = parser.next_int()
left = 1
right = n
while left < right:
mid = (left + right) // 2
b_1 = ask(mid)
b_2 = ask(mid + 1)
if b_1 < b_2:
right = mid
else:
left = mid + 1
answer(left)
```
| 200
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
Homer likes arrays a lot and he wants to play a game with you.
Homer has hidden from you a permutation a_1, a_2, ..., a_n of integers 1 to n. You are asked to find any index k (1 β€ k β€ n) which is a local minimum.
For an array a_1, a_2, ..., a_n, an index i (1 β€ i β€ n) is said to be a local minimum if a_i < min\\{a_{i-1},a_{i+1}\}, where a_0 = a_{n+1} = +β. An array is said to be a permutation of integers 1 to n, if it contains all integers from 1 to n exactly once.
Initially, you are only given the value of n without any other information about this permutation.
At each interactive step, you are allowed to choose any i (1 β€ i β€ n) and make a query with it. As a response, you will be given the value of a_i.
You are asked to find any index k which is a local minimum after at most 100 queries.
Interaction
You begin the interaction by reading an integer n (1β€ n β€ 10^5) on a separate line.
To make a query on index i (1 β€ i β€ n), you should output "? i" in a separate line. Then read the value of a_i in a separate line. The number of the "?" queries is limited within 100.
When you find an index k (1 β€ k β€ n) which is a local minimum, output "! k" in a separate line and terminate your program.
In case your query format is invalid, or you have made more than 100 "?" queries, you will receive Wrong Answer verdict.
After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
Hack Format
The first line of the hack should contain a single integer n (1 β€ n β€ 10^5).
The second line should contain n distinct integers a_1, a_2, ..., a_n (1 β€ a_i β€ n).
Example
Input
5
3
2
1
4
5
Output
? 1
? 2
? 3
? 4
? 5
! 3
Note
In the example, the first line contains an integer 5 indicating that the length of the array is n = 5.
The example makes five "?" queries, after which we conclude that the array is a = [3,2,1,4,5] and k = 3 is local minimum.
Submitted Solution:
```
# https://codeforces.com/contest/1479/problem/A
def main():
n = int(input())
l = 1
r = n
prev = None
while l <= r:
m = l + (r - l) // 2
print(f'? {m}')
curr = int(input())
if prev is None or curr < prev:
l = m + 1
else:
r = m - 1
prev = curr
ans = l - 1
print(f'! {ans}')
if __name__ == '__main__':
main()
```
No
| 201
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
Homer likes arrays a lot and he wants to play a game with you.
Homer has hidden from you a permutation a_1, a_2, ..., a_n of integers 1 to n. You are asked to find any index k (1 β€ k β€ n) which is a local minimum.
For an array a_1, a_2, ..., a_n, an index i (1 β€ i β€ n) is said to be a local minimum if a_i < min\\{a_{i-1},a_{i+1}\}, where a_0 = a_{n+1} = +β. An array is said to be a permutation of integers 1 to n, if it contains all integers from 1 to n exactly once.
Initially, you are only given the value of n without any other information about this permutation.
At each interactive step, you are allowed to choose any i (1 β€ i β€ n) and make a query with it. As a response, you will be given the value of a_i.
You are asked to find any index k which is a local minimum after at most 100 queries.
Interaction
You begin the interaction by reading an integer n (1β€ n β€ 10^5) on a separate line.
To make a query on index i (1 β€ i β€ n), you should output "? i" in a separate line. Then read the value of a_i in a separate line. The number of the "?" queries is limited within 100.
When you find an index k (1 β€ k β€ n) which is a local minimum, output "! k" in a separate line and terminate your program.
In case your query format is invalid, or you have made more than 100 "?" queries, you will receive Wrong Answer verdict.
After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
Hack Format
The first line of the hack should contain a single integer n (1 β€ n β€ 10^5).
The second line should contain n distinct integers a_1, a_2, ..., a_n (1 β€ a_i β€ n).
Example
Input
5
3
2
1
4
5
Output
? 1
? 2
? 3
? 4
? 5
! 3
Note
In the example, the first line contains an integer 5 indicating that the length of the array is n = 5.
The example makes five "?" queries, after which we conclude that the array is a = [3,2,1,4,5] and k = 3 is local minimum.
Submitted Solution:
```
# from __future__ import print_function,division
# range = xrange
import sys
input = sys.stdin.readline
# sys.setrecursionlimit(10**9)
from sys import stdin, stdout
from collections import defaultdict, Counter
M = 10 ** 9 + 7
n = int(input())
i = 1
j = n
l = [-1] * (n + 2)
l[0] = -10 ** 9
l[n + 1] = 10 ** 9
while i <= j:
mid = (i + j) // 2
if l[mid] == -1:
print("?", mid)
stdout.flush()
a = int(input())
l[mid] = a
if l[mid + 1] == -1:
print("?", mid + 1)
stdout.flush()
a = int(input())
l[mid + 1] = a
if l[mid - 1] == -1:
print("?", mid - 1)
stdout.flush()
a = int(input())
l[mid - 1] = a
if l[mid] < l[mid - 1] and l[mid] < l[mid + 1]:
print("!", mid)
break
elif l[mid - 1] < l[mid]:
j = mid - 1
else:
i = mid + 1
```
No
| 202
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
Homer likes arrays a lot and he wants to play a game with you.
Homer has hidden from you a permutation a_1, a_2, ..., a_n of integers 1 to n. You are asked to find any index k (1 β€ k β€ n) which is a local minimum.
For an array a_1, a_2, ..., a_n, an index i (1 β€ i β€ n) is said to be a local minimum if a_i < min\\{a_{i-1},a_{i+1}\}, where a_0 = a_{n+1} = +β. An array is said to be a permutation of integers 1 to n, if it contains all integers from 1 to n exactly once.
Initially, you are only given the value of n without any other information about this permutation.
At each interactive step, you are allowed to choose any i (1 β€ i β€ n) and make a query with it. As a response, you will be given the value of a_i.
You are asked to find any index k which is a local minimum after at most 100 queries.
Interaction
You begin the interaction by reading an integer n (1β€ n β€ 10^5) on a separate line.
To make a query on index i (1 β€ i β€ n), you should output "? i" in a separate line. Then read the value of a_i in a separate line. The number of the "?" queries is limited within 100.
When you find an index k (1 β€ k β€ n) which is a local minimum, output "! k" in a separate line and terminate your program.
In case your query format is invalid, or you have made more than 100 "?" queries, you will receive Wrong Answer verdict.
After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
Hack Format
The first line of the hack should contain a single integer n (1 β€ n β€ 10^5).
The second line should contain n distinct integers a_1, a_2, ..., a_n (1 β€ a_i β€ n).
Example
Input
5
3
2
1
4
5
Output
? 1
? 2
? 3
? 4
? 5
! 3
Note
In the example, the first line contains an integer 5 indicating that the length of the array is n = 5.
The example makes five "?" queries, after which we conclude that the array is a = [3,2,1,4,5] and k = 3 is local minimum.
Submitted Solution:
```
from sys import stdout
n = int(input())
def ask (v):
val = (int( input ("? " + str(v) + "\n") ))
if (val == 1 ):
print ("! {}".format(v))
exit()
else:
return (int( input ("? " + str(v) + "\n") ))
def calc(right):
stdout.flush()
left = 1
while ( right - left > 1 ):
if ( ask( ( right + left ) // 2 ) < ask ( ( right + left ) // 2 + 1 ) ):
right = ( right + left ) // 2
minlocal = right - 1
else:
left = ( right + left ) // 2 + 1
minlocal = left
print ("! {}".format(minlocal))
calc(n)
```
No
| 203
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem.
Homer likes arrays a lot and he wants to play a game with you.
Homer has hidden from you a permutation a_1, a_2, ..., a_n of integers 1 to n. You are asked to find any index k (1 β€ k β€ n) which is a local minimum.
For an array a_1, a_2, ..., a_n, an index i (1 β€ i β€ n) is said to be a local minimum if a_i < min\\{a_{i-1},a_{i+1}\}, where a_0 = a_{n+1} = +β. An array is said to be a permutation of integers 1 to n, if it contains all integers from 1 to n exactly once.
Initially, you are only given the value of n without any other information about this permutation.
At each interactive step, you are allowed to choose any i (1 β€ i β€ n) and make a query with it. As a response, you will be given the value of a_i.
You are asked to find any index k which is a local minimum after at most 100 queries.
Interaction
You begin the interaction by reading an integer n (1β€ n β€ 10^5) on a separate line.
To make a query on index i (1 β€ i β€ n), you should output "? i" in a separate line. Then read the value of a_i in a separate line. The number of the "?" queries is limited within 100.
When you find an index k (1 β€ k β€ n) which is a local minimum, output "! k" in a separate line and terminate your program.
In case your query format is invalid, or you have made more than 100 "?" queries, you will receive Wrong Answer verdict.
After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
Hack Format
The first line of the hack should contain a single integer n (1 β€ n β€ 10^5).
The second line should contain n distinct integers a_1, a_2, ..., a_n (1 β€ a_i β€ n).
Example
Input
5
3
2
1
4
5
Output
? 1
? 2
? 3
? 4
? 5
! 3
Note
In the example, the first line contains an integer 5 indicating that the length of the array is n = 5.
The example makes five "?" queries, after which we conclude that the array is a = [3,2,1,4,5] and k = 3 is local minimum.
Submitted Solution:
```
import sys
from sys import stdin
import random
mode = 0
count = 0
def q(i):
if a[i] == None:
print ("?",i,flush=True)
if mode == 0:
cat = int(stdin.readline())
else:
global count
cat = c[i]
print (c[i] , count)
count += 1
a[i] = cat
return cat
return a[i]
def ans(i):
if a[i] < min(a[i-1],a[i+1]):
print ("!",i,flush=True)
sys.exit()
n = int(stdin.readline())
a = [None] * (n+2)
if mode == 1:
n = random.randint(1,10**5)
a = [None] * (n+2)
tmp = [i+1 for i in range(n)]
random.shuffle(tmp)
c = [float("inf")] + tmp + [float("inf")]
a[0] = float("inf")
a[-1] = float("inf")
if n <= 4:
for i in range(1,n+1):
q(i)
for i in range(1,n+1):
ans(i)
sys.exit()
q(1)
q(2)
q(n)
q(n-1)
ans(1)
ans(n)
l = 1
r = n
while r-l != 1:
m = (l+r)//2
q(m)
q(m-1)
q(m+1)
ans(m)
if abs(a[l] - a[m]) == abs(l-m):
l = m
else:
r = m
```
No
| 204
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Tags: *special, implementation
Correct Solution:
```
a = ['10010', '11020', '20011', '21012', '11011', '21021', '22022', '12021', '00000', '12012', '10120', '11130', '20121', '21122', '11121', '21131', '22132', '12131', '11111', '12122', '10221', '11231', '12113', '20222', '21223', '11222']
n = int(input())
for i in range(n) :
f = input().replace(' ','')
print (chr (97 + a.index(f)), end='')
```
| 205
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Tags: *special, implementation
Correct Solution:
```
table = {
(1, 0, 0, 1, 0): 'a',
(1, 1, 0, 2, 0): 'b',
(2, 0, 0, 1, 1): 'c',
(2, 1, 0, 1, 2): 'd',
(1, 1, 0, 1, 1): 'e',
(2, 1, 0, 2, 1): 'f',
(2, 2, 0, 2, 2): 'g',
(1, 2, 0, 2, 1): 'h',
# (1, 1, 0, 1, 1): 'i',
(1, 2, 0, 1, 2): 'j',
(1, 0, 1, 2, 0): 'k',
(1, 1, 1, 3, 0): 'l',
(2, 0, 1, 2, 1): 'm',
(2, 1, 1, 2, 2): 'n',
(1, 1, 1, 2, 1): 'o',
(2, 1, 1, 3, 1): 'p',
(2, 2, 1, 3, 2): 'q',
(1, 2, 1, 3, 1): 'r',
# (1, 1, 1, 2, 1): 's',
(1, 2, 1, 2, 2): 't',
(1, 0, 2, 2, 1): 'u',
(1, 1, 2, 3, 1): 'v',
(1, 2, 1, 1, 3): 'w',
(2, 0, 2, 2, 2): 'x',
(2, 1, 2, 2, 3): 'y',
(1, 1, 2, 2, 2): 'z',
}
for item in table:
if item[0] + item[1] + item[2] !=item[3] + item[4]:
print(table[item])
exit(1)
ans = []
for _ in range(int(input())):
a = tuple(map(int, input().split()))
ans.append(table[a])
print(''.join(ans))
```
| 206
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Tags: *special, implementation
Correct Solution:
```
Y='1 11 1001 11001 10001 1011 11011 10011 1010 11010 101 111 1101 11101 10101 1111 11111 10111 1110 11110 100101 100111 111010 101101 111101 110101'
X=list(map(lambda x:int(x,2),Y.split()))
N=int(input())
ANS=[]
for i in range(N):
a,b,c,d,e=map(int,input().split())
A=[a,b,c]
B=[d,e]
for j in range(26):
C,D=[0,0,0],[0,0]
for k in range(6):
C[k%3]+=(X[j]>>k)&1
D[k//3]+=(X[j]>>k)&1
if A==C and B==D:
ANS.append(chr(ord('a')+j))
break
print(''.join(ANS))
```
| 207
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Tags: *special, implementation
Correct Solution:
```
q={
"1 0 0 1 0" : 'a',
"1 1 0 2 0" : 'b',
"2 0 0 1 1" : 'c',
"2 1 0 1 2" : 'd',
"1 1 0 1 1" : 'e',
"2 1 0 2 1" : 'f',
"2 2 0 2 2" : 'g',
"1 2 0 2 1" : 'h',
#"1 1 0 1 1" : 'i',
"1 2 0 1 2" : 'j',
"1 0 1 2 0" : 'k',
"1 1 1 3 0" : 'l',
"2 0 1 2 1" : 'm',
"2 1 1 2 2" : 'n',
"1 1 1 2 1" : 'o',
"2 1 1 3 1" : 'p',
"2 2 1 3 2" : 'q',
"1 2 1 3 1" : 'r',
#"1 1 1 2 1" : 's',
"1 2 1 2 2" : 't',
"1 0 2 2 1" : 'u',
"1 1 2 3 1" : 'v',
"2 0 2 2 2" : 'x',
"2 1 2 2 3" : 'y',
"1 1 2 2 2" : 'z',
"1 2 1 1 3" : 'w'
}
print(''.join([q[input()] for i in range(int(input()))]))
```
| 208
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Tags: *special, implementation
Correct Solution:
```
dic = {}
dic['1 0 0 1 0'] = 'a'
dic['1 1 0 2 0'] = 'b'
dic['2 0 0 1 1'] = 'c'
dic['2 1 0 1 2'] = 'd'
dic['1 1 0 1 1'] = 'e'
dic['2 1 0 2 1'] = 'f'
dic['2 2 0 2 2'] = 'g'
dic['1 2 0 2 1'] = 'h'
# dic['1 1 0 1 1'] = 'i'
dic['1 2 0 1 2'] = 'j'
dic['1 0 1 2 0'] = 'k'
dic['1 1 1 3 0'] = 'l'
dic['2 0 1 2 1'] = 'm'
dic['2 1 1 2 2'] = 'n'
dic['1 1 1 2 1'] = 'o'
dic['2 1 1 3 1'] = 'p'
dic['2 2 1 3 2'] = 'q'
dic['1 2 1 3 1'] = 'r'
# dic['1 1 1 2 1'] = 's'
dic['1 2 1 2 2'] = 't'
dic['1 0 2 2 1'] = 'u'
dic['1 1 2 3 1'] = 'v'
dic['1 2 1 1 3'] = 'w'
dic['2 0 2 2 2'] = 'x'
dic['2 1 2 2 3'] = 'y'
dic['1 1 2 2 2'] = 'z'
ans = ''
for _ in range(int(input())):
s = input()
ans += dic[s]
print(ans)
```
| 209
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Tags: *special, implementation
Correct Solution:
```
n = int(input())
d = dict()
d[10010] = "a"
d[11020] = "b"
d[20011] = "c"
d[21012] = "d"
d[11011] = "e"
d[21021] = "f"
d[22022] = "g"
d[12021] = "h"
#d[11011] = "i"
d[12012] = "j"
d[10120] = "k"
d[11130] = "l"
d[20121] = "m"
d[21122] = "n"
d[11121] = "o"
d[21131] = "p"
d[22132] = "q"
d[12131] = "r"
#d[11121] = "s"
d[12122] = "t"
d[10221] = "u"
d[11231] = "v"
d[12113] = "w"
d[20222] = "x"
d[21223] = "y"
d[11222] = "z"
ans = ""
for _ in range(n):
ans += d[int("".join(list(input().split())))]
print(ans)
```
| 210
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Tags: *special, implementation
Correct Solution:
```
a = ['10010','11020','20011','21012','11011','21021','22022','12021','00000','12012','10120','11130','20121','21122','11121','21131','22132','12131','11111','12122','10221','11231','12113','20222','21223','11222']
from string import ascii_lowercase as l
n = int(input())
r = ''
for i in range(n):
*b, = map(int, input().split())
s = ''.join(map(str, b))
r += l[a.index(s)]
print(r)
```
| 211
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Tags: *special, implementation
Correct Solution:
```
braille = [["a", "1"],
["b", "12"],
["c", "14"],
["d", "145"],
["e", "15"],
["f", "124"],
["g", "1245"],
["h", "125"],
["i", "24"],
["j", "245"],
["k", "13"],
["l", "123"],
["m", "134"],
["n", "1345"],
["o", "135"],
["p", "1234"],
["q", "12345"],
["r", "1235"],
["s", "234"],
["t", "2345"],
["u", "136"],
["v", "1236"],
["w", "2456"],
["x", "1346"],
["y", "13456"],
["z", "1356"]]
decoded = {}
for ch, enc in braille:
final = [0] * 5
for idx in enc:
idx = ord(idx) - ord('1')
r = idx % 3
c = idx //3
final[r] += 1
final[c+3] += 1
if tuple(final) not in decoded:
decoded[tuple(final)] = ch
n = int(input())
ans = ""
for i in range(n):
a, b, c, d, e = map(int, input().split())
ans += decoded[a,b,c,d,e]
print(ans)
```
| 212
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Submitted Solution:
```
def translateinput(i):
return bitbraichar[input().replace(' ','')]
bitbraichar = {
'10010':'a',
'11020':'b',
'20011':'c',
'21012':'d',
'11011':'e',
'21021':'f',
'22022':'g',
'12021':'h',
'12012':'j',
'10120':'k',
'11130':'l',
'20121':'m',
'21122':'n',
'11121':'o',
'21131':'p',
'22132':'q',
'12131':'r',
'12122':'t',
'10221':'u',
'11231':'v',
'12113':'w',
'20222':'x',
'21223':'y',
'11222':'z'
}
n = int(input())
for i in map(translateinput,range(n)):
print(i,end='')
```
Yes
| 213
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Submitted Solution:
```
for s in[*open(0)][1:]:print(chr(97+['10010','11020','20011','21012','11011','21021','22022','12021','00000','12012','10120','11130','20121','21122','11121','21131','22132','12131','11111','12122','10221','11231','12113','20222','21223','11222'].index(s[:-1].replace(' ',''))),end='')
```
Yes
| 214
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Submitted Solution:
```
# coding: utf-8
n = int(input())
d = dict()
d['10010'] = 'a'
d['11020'] = 'b'
d['20011'] = 'c'
d['21012'] = 'd'
d['11011'] = 'e'
d['21021'] = 'f'
d['22022'] = 'g'
d['12021'] = 'h'
d['12012'] = 'j'
d['10120'] = 'k'
d['11130'] = 'l'
d['20121'] = 'm'
d['21122'] = 'n'
d['11121'] = 'o'
d['21131'] = 'p'
d['22132'] = 'q'
d['12131'] = 'r'
d['12122'] = 't'
d['10221'] = 'u'
d['11231'] = 'v'
d['12113'] = 'w'
d['20222'] = 'x'
d['21223'] = 'y'
d['11222'] = 'z'
result = ''
for i in range(n):
result += d[input().replace(' ', '')]
print(result)
```
Yes
| 215
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Submitted Solution:
```
n = int(input())
D = {
'12113': 'w',
'11222': 'z',
'21223': 'y',
'20222': 'x',
'11231': 'v',
'10221': 'u',
'12122': 't',
'11121': 's',
'12131': 'r',
'22132': 'q',
'21131': 'p',
'11121': 'o',
'21122': 'n',
'20121': 'm',
'11130': 'l',
'10120': 'k',
'12012': 'j',
'11011': 'i',
'12021': 'h',
'22022': 'g',
'21021': 'f',
'11011': 'e',
'21012': 'd',
'20011': 'c',
'11020': 'b',
'10010': 'a',
}
print(''.join(D[input().replace(' ', '')] for _ in range(n)))
```
Yes
| 216
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Submitted Solution:
```
for i in range(int(input())):
input()
print('lol')
```
No
| 217
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Submitted Solution:
```
s=int(input())
print((2-s) if s==1 else 0)
```
No
| 218
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Submitted Solution:
```
n = int(input())
out = ""
for i in range (0,n):
input()
out+='a'
if (n==1):
print('a')
else:
print('codeforcez')
```
No
| 219
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Input
The first line of the input contains a single integer N (1 β€ N β€ 24). The next N lines contain 5 space-separated integers each. The first three integers will be between 0 and 2, inclusive. The last two integers will be between 0 and 3, inclusive. The sum of the first three integers will be equal to the sum of the last two integers.
Output
Output the result β a string of lowercase English letters.
Examples
Input
1
1 0 0 1 0
Output
a
Input
10
2 0 0 1 1
1 1 1 2 1
2 1 0 1 2
1 1 0 1 1
2 1 0 2 1
1 1 1 2 1
1 2 1 3 1
2 0 0 1 1
1 1 0 1 1
1 1 2 2 2
Output
codeforcez
Submitted Solution:
```
for i in range(int(input())):
a, b, c, d, e = map(int, input().split())
if c==0:
print(chr(a+b+d+e+95), end="")
else:
print(chr(a+b+c*10+d+e+96),end="")
```
No
| 220
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Tags: constructive algorithms, greedy, math
Correct Solution:
```
t = int(input().strip())
for case in range(t):
n = int(input().strip())
nums = list(map(int, input().split()))
count = nums.count(min(nums))
print(len(nums) - count)
```
| 221
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Tags: constructive algorithms, greedy, math
Correct Solution:
```
import sys
read=sys.stdin.buffer.read;readline=sys.stdin.buffer.readline;input=lambda:sys.stdin.readline().rstrip()
import bisect,string,math,time,functools,random,fractions
from bisect import*
from heapq import heappush,heappop,heapify
from collections import deque,defaultdict,Counter
from itertools import permutations,combinations,groupby
rep=range;R=range
def I():return int(input())
def LI():return [int(i) for i in input().split()]
def LI_():return [int(i)-1 for i in input().split()]
def AI():return map(int,open(0).read().split())
def S_():return input()
def IS():return input().split()
def LS():return [i for i in input().split()]
def NI(n):return [int(input()) for i in range(n)]
def NI_(n):return [int(input())-1 for i in range(n)]
def NLI(n):return [[int(i) for i in input().split()] for i in range(n)]
def NLI_(n):return [[int(i)-1 for i in input().split()] for i in range(n)]
def StoLI():return [ord(i)-97 for i in input()]
def ItoS(n):return chr(n+97)
def LtoS(ls):return ''.join([chr(i+97) for i in ls])
def RLI(n=8,a=1,b=10):return [random.randint(a,b)for i in range(n)]
def RI(a=1,b=10):return random.randint(a,b)
def INP():
N=10
n=random.randint(1,N)
a=RLI(n,0,n-1)
return n,a
def Rtest(T):
case,err=0,0
for i in range(T):
inp=INP()
a1=naive(*inp)
a2=solve(*inp)
if a1!=a2:
print(inp)
print('naive',a1)
print('solve',a2)
err+=1
case+=1
print('Tested',case,'case with',err,'errors')
def GI(V,E,ls=None,Directed=False,index=1):
org_inp=[];g=[[] for i in range(V)]
FromStdin=True if ls==None else False
for i in range(E):
if FromStdin:
inp=LI()
org_inp.append(inp)
else:
inp=ls[i]
if len(inp)==2:a,b=inp;c=1
else:a,b,c=inp
if index==1:a-=1;b-=1
aa=(a,c);bb=(b,c);g[a].append(bb)
if not Directed:g[b].append(aa)
return g,org_inp
def GGI(h,w,search=None,replacement_of_found='.',mp_def={'#':1,'.':0},boundary=1):
#h,w,g,sg=GGI(h,w,search=['S','G'],replacement_of_found='.',mp_def={'#':1,'.':0},boundary=1) # sample usage
mp=[boundary]*(w+2);found={}
for i in R(h):
s=input()
for char in search:
if char in s:
found[char]=((i+1)*(w+2)+s.index(char)+1)
mp_def[char]=mp_def[replacement_of_found]
mp+=[boundary]+[mp_def[j] for j in s]+[boundary]
mp+=[boundary]*(w+2)
return h+2,w+2,mp,found
def TI(n):return GI(n,n-1)
def accum(ls):
rt=[0]
for i in ls:rt+=[rt[-1]+i]
return rt
def bit_combination(n,base=2):
rt=[]
for tb in R(base**n):s=[tb//(base**bt)%base for bt in R(n)];rt+=[s]
return rt
def gcd(x,y):
if y==0:return x
if x%y==0:return y
while x%y!=0:x,y=y,x%y
return y
def YN(x):print(['NO','YES'][x])
def Yn(x):print(['No','Yes'][x])
def show(*inp,end='\n'):
if show_flg:print(*inp,end=end)
mo=10**9+7
#mo=998244353
inf=float('inf')
FourNb=[(-1,0),(1,0),(0,1),(0,-1)];EightNb=[(-1,0),(1,0),(0,1),(0,-1),(1,1),(-1,-1),(1,-1),(-1,1)];compas=dict(zip('WENS',FourNb));cursol=dict(zip('LRUD',FourNb))
alp=[chr(ord('a')+i)for i in range(26)]
#sys.setrecursionlimit(10**7)
def gcj(c,x):
print("Case #{0}:".format(c+1),x)
show_flg=False
show_flg=True
ans=0
for _ in range(I()):
ans=0
n=I()
a=LI()
m=min(a)
ans=n-a.count(m)
print(ans)
```
| 222
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Tags: constructive algorithms, greedy, math
Correct Solution:
```
for _ in range(int(input())):
n=int(input())
arr=list(map(int,input().split()))
arr.sort()
print(n-arr.count(arr[0]))
```
| 223
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Tags: constructive algorithms, greedy, math
Correct Solution:
```
for i in range(int(input())):
n=int(input())
a=list(map(int,input().split()))
print(n-a.count(min(a)))
```
| 224
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Tags: constructive algorithms, greedy, math
Correct Solution:
```
a=int(input())
while a:
a=a-1
n=int(input())
x=list(map(int,input().split()))
p=list(set(x))
p.sort()
print(n-x.count(p[0]))
```
| 225
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Tags: constructive algorithms, greedy, math
Correct Solution:
```
for _ in range(int(input())):
n = int(input())
a = list(map(int, input().split()))
mn = min(a)
print(n - a.count(mn))
```
| 226
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Tags: constructive algorithms, greedy, math
Correct Solution:
```
from itertools import combinations, permutations, combinations_with_replacement, product
import itertools
from timeit import timeit
import timeit
import time
from time import time
from random import *
import random
import collections
import bisect
import os
import math
from collections import defaultdict, OrderedDict, Counter
from sys import stdin, stdout
from bisect import bisect_left, bisect_right
# import numpy as np
from queue import Queue, PriorityQueue
from heapq import *
from statistics import *
from math import sqrt, log10, log2, log, gcd, ceil, floor
import fractions
import copy
from copy import deepcopy
import sys
import io
sys.setrecursionlimit(10000)
mod = int(pow(10, 9)) + 7
def ncr(n, r, p=mod):
num = den = 1
for i in range(r):
num = (num * (n - i)) % p
den = (den * (i + 1)) % p
return (num * pow(den,
p - 2, p)) % p
def normalncr(n, r):
r = min(r, n - r)
count = 1
for i in range(n - r, n + 1):
count *= i
for i in range(1, r + 1):
count //= i
return count
inf = float("inf")
adj = defaultdict(set)
visited = defaultdict(int)
def addedge(a, b):
adj[a].add(b)
adj[b].add(a)
def bfs(v):
q = Queue()
q.put(v)
visited[v] = 1
while q.qsize() > 0:
s = q.get_nowait()
print(s)
for i in adj[s]:
if visited[i] == 0:
q.put(i)
visited[i] = 1
def dfs(v, visited):
if visited[v] == 1:
return
visited[v] = 1
print(v)
for i in adj[v]:
dfs(i, visited)
# a9=pow(10,5)+100
# prime = [True for i in range(a9 + 1)]
# def SieveOfEratosthenes(n):
# p = 2
# while (p * p <= n):
# if (prime[p] == True):
# for i in range(p * p, n + 1, p):
# prime[i] = False
# p += 1
# SieveOfEratosthenes(a9)
# prime_number=[]
# for i in range(2,a9):
# if prime[i]:
# prime_number.append(i)
def reverse_bisect_right(a, x, lo=0, hi=None):
if lo < 0:
raise ValueError('lo must be non-negative')
if hi is None:
hi = len(a)
while lo < hi:
mid = (lo + hi) // 2
if x > a[mid]:
hi = mid
else:
lo = mid + 1
return lo
def reverse_bisect_left(a, x, lo=0, hi=None):
if lo < 0:
raise ValueError('lo must be non-negative')
if hi is None:
hi = len(a)
while lo < hi:
mid = (lo + hi) // 2
if x >= a[mid]:
hi = mid
else:
lo = mid + 1
return lo
def get_list():
return list(map(int, input().split()))
def make_list(m):
m += list(map(int, input().split()))
def get_str_list_in_int():
return [int(i) for i in list(input())]
def get_str_list():
return list(input())
def get_map():
return map(int, input().split())
def input_int():
return int(input())
def matrix(a, b):
return [[0 for i in range(b)] for j in range(a)]
def swap(a, b):
return b, a
def find_gcd(l):
a = l[0]
for i in range(len(l)):
a = gcd(a, l[i])
return a
def is_prime(n):
sqrta = int(sqrt(n))
for i in range(2, sqrta + 1):
if n % i == 0:
return 0
return 1
def prime_factors(n):
l = []
while n % 2 == 0:
l.append(2)
n //= 2
sqrta = int(sqrt(n))
for i in range(3, sqrta + 1, 2):
while n % i == 0:
n //= i
l.append(i)
if n > 2:
l.append(n)
return l
def p(a):
if type(a) == str:
print(a + "\n")
else:
print(str(a) + "\n")
def ps(a):
if type(a) == str:
print(a)
else:
print(str(a))
def kth_no_not_div_by_n(n, k):
return k + (k - 1) // (n - 1)
def forward_array(l):
"""
returns the forward index where the elemetn is just greater than that element
[100,200] gives [1,2]
because element at index 1 is greater than 100 and nearest
similarly if it is largest then it outputs n
:param l:
:return:
"""
n = len(l)
stack = []
forward = [0] * n
for i in range(len(l) - 1, -1, -1):
while len(stack) and l[stack[-1]] < l[i]:
stack.pop()
if len(stack) == 0:
forward[i] = len(l)
else:
forward[i] = stack[-1]
stack.append(i)
return forward
def forward_array_notequal(l):
n = len(l)
stack = []
forward = [n]*n
for i in range(len(l) - 1, -1, -1):
while len(stack) and l[stack[-1]] <= l[i]:
stack.pop()
if len(stack) == 0:
forward[i] = len(l)
else:
forward[i] = stack[-1]
stack.append(i)
return forward
def backward_array(l):
n = len(l)
stack = []
backward = [0] * n
for i in range(len(l)):
while len(stack) and l[stack[-1]] < l[i]:
stack.pop()
if len(stack) == 0:
backward[i] = -1
else:
backward[i] = stack[-1]
stack.append(i)
return backward
def char(a):
return chr(a + 97)
def get_length(a):
return 1 + int(log10(a))
def issq(n):
sqrta = int(n ** 0.5)
return sqrta ** 2 == n
def ceil(a, b):
return int((a+b-1)/b)
def equal_sum_partition(arr, n):
sum = 0
for i in range(n):
sum += arr[i]
if sum % 2 != 0:
return False
part = [[True for i in range(n + 1)]
for j in range(sum // 2 + 1)]
for i in range(0, n + 1):
part[0][i] = True
for i in range(1, sum // 2 + 1):
part[i][0] = False
for i in range(1, sum // 2 + 1):
for j in range(1, n + 1):
part[i][j] = part[i][j - 1]
if i >= arr[j - 1]:
part[i][j] = (part[i][j] or
part[i - arr[j - 1]][j - 1])
return part[sum // 2][n]
def bin_sum_array(arr, n):
for i in range(n):
if arr[i] % 2 == 1:
return i+1
binarray = [list(reversed(bin(i)[2:])) for i in arr]
new_array = [0 for i in range(32)]
for i in binarray:
for j in range(len(i)):
if i[j] == '1':
new_array[j] += 1
return new_array
def ispalindrome(s):
return s == s[::-1]
def get_prefix(l):
if l == []:
return []
prefix = [l[0]]
for i in range(1, len(l)):
prefix.append(prefix[-1]+l[i])
return prefix
def get_suffix(l):
if l == []:
return []
suffix = [l[-1]]*len(l)
for i in range(len(l)-2, -1, -1):
suffix[i] = suffix[i+1]+l[i]
return suffix
nc = "NO"
yc = "YES"
ns = "No"
ys = "Yes"
def yesno(a):
print(yc if a else nc)
def reduce(dict, a):
dict[a] -= 1
if dict[a] == 0:
dict.pop(a)
# import math as mt
# MAXN=10**7
# spf = [0 for i in range(MAXN)]
# def sieve():
# spf[1] = 1
# for i in range(2, MAXN):
# # marking smallest prime factor
# # for every number to be itself.
# spf[i] = i
#
# # separately marking spf for
# # every even number as 2
# for i in range(4, MAXN, 2):
# spf[i] = 2
#
# for i in range(3, mt.ceil(mt.sqrt(MAXN))):
#
# # checking if i is prime
# if (spf[i] == i):
#
# # marking SPF for all numbers
# # divisible by i
# for j in range(i * i, MAXN, i):
#
# # marking spf[j] if it is
# # not previously marked
# if (spf[j] == j):
# spf[j] = i
# def getFactorization(x):
# ret = list()
# while (x != 1):
# ret.append(spf[x])
# x = x // spf[x]
#
# return ret
# sieve()
# if(os.path.exists('input.txt')):
# sys.stdin = open("input.txt","r") ; sys.stdout = open("output.txt","w")
import sys
import io
from sys import stdin, stdout
# input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
input=sys.stdin.readline
# print=sys.stdout.write
t = 1
import time
time.sleep(0.1)
t=int(input())
for i in range(t):
n=int(input())
l=get_list()
mina=min(l)
print(n-l.count(min(l)))
```
| 227
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Tags: constructive algorithms, greedy, math
Correct Solution:
```
def solve():
n = int(input())
arr = list(map(int, input().split()))
m = min(arr)
k = arr.count(m)
print(n - k)
t = int(input())
for _ in range(t):
solve()
```
| 228
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Submitted Solution:
```
for _ in range(int(input())):
n = int(input())
a = list(map(int,input().split()))
c = min(a)
ans = 0
for i in range(len(a)):
if a[i] != c:
ans += 1
print(ans)
```
Yes
| 229
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Submitted Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
arr = list(map(int, input().split()))
c = arr.count(min(arr))
print(n - c)
```
Yes
| 230
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Submitted Solution:
```
n = int(input())
for i in range(n):
b=int(input())
arr = [int(c) for c in input().split()]
arr = sorted(arr)
x = [a for a in arr if a!=arr[0]]
print(len(x))
```
Yes
| 231
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Submitted Solution:
```
import sys,os.path
if __name__ == '__main__':
if(os.path.exists('input.txt')):
sys.stdin = open("input.txt","r")
sys.stdout = open("output.txt","w")
for _ in range(int(input())):
n = int(input())
a = list(map(int,input().split()))
k = min(a)
c = 0
for i in range(n):
if a[i]==k:
c+=1
print(n-c)
```
Yes
| 232
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Submitted Solution:
```
for i in range(int(input())):
import math
n=int(input())
a=list(map(int,input().strip().split()))
d=sum(a)//n
a.sort()
c=0
if(len(set(a))==1):
print(0)
else:
for i in range(len(a)):
if(a[i]<=d):
c+=1
print(c)
```
No
| 233
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Submitted Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
a = sorted(map(int, input().split(' ')))
print((n - sum([k for k in a if k == a[0]])) if a[0] != a[-1] else 0)
```
No
| 234
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Submitted Solution:
```
from sys import *
import sys
# from math import *
# from collections import *
import string
# import re
# from bisect import *
t=stdin.readline
R=range
p=stdout.write
mod = int(1e9)+7
MAX = 9223372036854775808
def S(): return t().strip()
def I(): return int(t())
def GI(): return map(int, input().strip().split())
def GS(): return map(str, t().strip().split())
def IL(): return list(map(int, t().strip().split()))
def SL(): return list(map(str, t().strip().split()))
def mat(n): return [IL() for i in range(n)]
# def isPerfectSquare(x): return (ceil(float(sqrt(x))) == floor(float(sqrt(x))))
#alpha = string.ascii_lowercase
for _ in range(I()):
n,a=I(),[]
ans,mn =0,MAX
for i in GI():
a.append(i)
if i<=0: ans +=1
else: mn = min(mn,i)
a.sort()
f = (mn<MAX)
for i in range(1,n):
if a[i]<=0:
f &= (a[i]-a[i-1] >=mn)
print(ans+1 if f else ans)
```
No
| 235
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Eshag has an array a consisting of n integers.
Eshag can perform the following operation any number of times: choose some subsequence of a and delete every element from it which is strictly larger than AVG, where AVG is the average of the numbers in the chosen subsequence.
For example, if a = [1 , 4 , 3 , 2 , 4] and Eshag applies the operation to the subsequence containing a_1, a_2, a_4 and a_5, then he will delete those of these 4 elements which are larger than (a_1+a_2+a_4+a_5)/(4) = 11/4, so after the operation, the array a will become a = [1 , 3 , 2].
Your task is to find the maximum number of elements Eshag can delete from the array a by applying the operation described above some number (maybe, zero) times.
A sequence b is a subsequence of an array c if b can be obtained from c by deletion of several (possibly, zero or all) elements.
Input
The first line contains an integer t (1β€ tβ€ 100) β the number of test cases. The description of the test cases follows.
The first line of each test case contains an integer n (1β€ nβ€ 100) β the length of the array a.
The second line of each test case contains n integers a_1, a_2, β¦, a_n (1β€ a_i β€ 100) β the elements of the array a.
Output
For each test case print a single integer β the maximum number of elements Eshag can delete from the array a.
Example
Input
3
6
1 1 1 2 2 3
6
9 9 9 9 9 9
6
6 4 1 1 4 1
Output
3
0
3
Note
Consider the first test case.
Initially a = [1, 1, 1, 2, 2, 3].
In the first operation, Eshag can choose the subsequence containing a_1, a_5 and a_6, their average is equal to (a_1 + a_5 + a_6)/(3) = 6/3 = 2. So a_6 will be deleted.
After this a = [1, 1, 1, 2, 2].
In the second operation, Eshag can choose the subsequence containing the whole array a, the average of all its elements is equal to 7/5. So a_4 and a_5 will be deleted.
After this a = [1, 1, 1].
In the second test case, Eshag can't delete any element.
Submitted Solution:
```
t = int(input())
for i in range (t):
n=int(input())
a=list(input().split())
print(len(a)-a.count(min(a)))
```
No
| 236
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Tags: greedy, sortings
Correct Solution:
```
length = int(input())
coin = [int(x) for x in input().split()]
b = sorted(coin,reverse=True)
sum = 0
for x in coin:
sum += x
crit = sum /2
take = 0
for i in range(length):
take += b[i]
if take > crit:
print(i+1)
break
```
| 237
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Tags: greedy, sortings
Correct Solution:
```
x = int(input())
y = input()
y = y.split()
l = []
for i in y:
i = int(i)
l.append(i)
l.sort()
l = l[::-1]
c= 1
s1 = l[0]
s = 0
for i in range(len(l)):
for j in range(i+1,len(l)):
s = s + l[j]
if s1 <= s:
s1 = s1 + l[i+1]
c+=1
s = 0
print(c)
```
| 238
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Tags: greedy, sortings
Correct Solution:
```
n = int(input())
coins = list(map(int, input().split()))
coins.sort(reverse = True)
total = sum(coins)
taken = []
for i in range(0, n):
if sum(taken) + coins[i] <= total - sum(taken) - coins[i]:
taken.append(coins[i])
else:
print(len(taken) + 1)
break
```
| 239
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Tags: greedy, sortings
Correct Solution:
```
n = int(input())
s = input().split()
i = 0
for u in range(0,len(s)):
s[u]=int(s[u])
maxsum = 0
while(True):
maxsum += max(s)
del(s[s.index(max(s))])
i += 1
if (sum(s) < maxsum):
break
print(i)
```
| 240
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Tags: greedy, sortings
Correct Solution:
```
n=int(input())
s=list(map(int,input().split()))
s.sort(reverse=True)
x=sum(s)
x=(x//2)+1
su=0
c=0
for j in s:
su=su+j
c+=1
if su>=x:
break
print(c)
```
| 241
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Tags: greedy, sortings
Correct Solution:
```
n=int(input())
a=[]
c=list(map(int,input().split()))
a.extend(c)
a.sort(reverse=True)
v=sum(c)
count=0
ctr=0
for i in range(n):
if count<=v/2:
count=count+a[i]
ctr+=1
print(ctr)
```
| 242
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Tags: greedy, sortings
Correct Solution:
```
n=int(input())
li=list(map(int, input().split()))
li.sort(reverse=True)
sum=sum(li)
j=0
sum2=0
while sum2<=(sum//2):
sum2=sum2+li[j]
j=j+1
print(j)
exit()
```
| 243
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Tags: greedy, sortings
Correct Solution:
```
import sys
file = sys.stdin.readlines()
line = file[1]
numbers = line.split(" ")
numbers[-1] = numbers[-1].strip()
i = 0
while i < len(numbers):
numbers[i] = int(numbers[i])
i += 1
numbers.sort(reverse = True)
total = sum(numbers)
coins = []
for coin in numbers:
coins.append(coin)
if sum(coins) > total - sum(coins):
print(len(coins))
break
```
| 244
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Submitted Solution:
```
n = int(input())
coins = [int(i) for i in input().split()]
coins.sort(reverse = True)
take = 0
total = 0
count = 0
total = sum(coins)
for i in range(n):
take += coins[i]
count += 1
if take> total-take:
break
print(count)
```
Yes
| 245
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Submitted Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
#from bisect import bisect_left as bl #c++ lowerbound bl(array,element)
#from bisect import bisect_right as br #c++ upperbound br(array,element)
def main():
n=int(input())
a=list(map(int,input().split(" ")))
a.sort(reverse=True)
for x in range(1,n+1):
# print(sum(a[:x]),sum(a[x:]),a[x:],a[:x])
if sum(a[:x])>sum(a[x:]):
print(x)
return
#-----------------------------BOSS-------------------------------------!
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
main()
```
Yes
| 246
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Submitted Solution:
```
n=int(input())
coin=[int(x)for x in input().split()]
coin.sort(reverse=True)
ave=sum(coin)/2
m=0
for i in range(n):
m+=coin[i]
if m>ave:
print(i+1)
break
```
Yes
| 247
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Submitted Solution:
```
n=int(input())
L=[int(x) for x in input().split()]
L.sort()
i=n-1
test=False
while (i>=0) and (test==False):
test=sum(L[:i])<sum(L[i:])
i-=1
print(len(L[i+1:]))
```
Yes
| 248
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Submitted Solution:
```
#160A Twins
n=input()
x=input()
y=x.split()
sum=0
for i in range(len(y)):
sum+=int(y[i])
y.sort(reverse=True)
sum1,i=0,0
while(i<len(y)):
sum1+=int(y[i])
if sum1>(sum//2):
break
i+=1
print(i+1)
```
No
| 249
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Submitted Solution:
```
n=int(input())
lst = list(map(int,input().split()))
lst.sort()
s=0
def sumRange(L,a,b):
sum = 0
for i in range(a,b):
sum += L[i]
return sum
for i in range(n):
s=s+lst[i]
ss=sumRange(lst,i+1,n)
if s>ss:
break
print(i+1)
```
No
| 250
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Submitted Solution:
```
a=int(input())
b=[int(s) for s in input().split()]
for k in range(1, len(b)+1):
if sum(b[(len(b)-k):])>sum(b[:(len(b)-k)]):
print(k)
break
```
No
| 251
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Imagine that you have a twin brother or sister. Having another person that looks exactly like you seems very unusual. It's hard to say if having something of an alter ego is good or bad. And if you do have a twin, then you very well know what it's like.
Now let's imagine a typical morning in your family. You haven't woken up yet, and Mom is already going to work. She has been so hasty that she has nearly forgotten to leave the two of her darling children some money to buy lunches in the school cafeteria. She fished in the purse and found some number of coins, or to be exact, n coins of arbitrary values a1, a2, ..., an. But as Mom was running out of time, she didn't split the coins for you two. So she scribbled a note asking you to split the money equally.
As you woke up, you found Mom's coins and read her note. "But why split the money equally?" β you thought. After all, your twin is sleeping and he won't know anything. So you decided to act like that: pick for yourself some subset of coins so that the sum of values of your coins is strictly larger than the sum of values of the remaining coins that your twin will have. However, you correctly thought that if you take too many coins, the twin will suspect the deception. So, you've decided to stick to the following strategy to avoid suspicions: you take the minimum number of coins, whose sum of values is strictly more than the sum of values of the remaining coins. On this basis, determine what minimum number of coins you need to take to divide them in the described manner.
Input
The first line contains integer n (1 β€ n β€ 100) β the number of coins. The second line contains a sequence of n integers a1, a2, ..., an (1 β€ ai β€ 100) β the coins' values. All numbers are separated with spaces.
Output
In the single line print the single number β the minimum needed number of coins.
Examples
Input
2
3 3
Output
2
Input
3
2 1 2
Output
2
Note
In the first sample you will have to take 2 coins (you and your twin have sums equal to 6, 0 correspondingly). If you take 1 coin, you get sums 3, 3. If you take 0 coins, you get sums 0, 6. Those variants do not satisfy you as your sum should be strictly more that your twins' sum.
In the second sample one coin isn't enough for us, too. You can pick coins with values 1, 2 or 2, 2. In any case, the minimum number of coins equals 2.
Submitted Solution:
```
def sub(list1):
sublist = []
for i in range(len(list1) + 1):
for j in range(i + 1, len(list1) + 1):
sub = tuple(list1[i:j])
sublist.append(sub)
return sublist
def add(A,s):
add={}
for i in A:
a=sum(i)
if a>s/2:
add[i]=a
return add
n=int(input())
val=list(map(int,input().split()))
s=sum(val)
sub=sub(val)
main=add(sub,s)
#print(main)
e=n+1
for i in main:
#print(i)
if len(i)<e:
e=len(i)
print(e)
```
No
| 252
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Nick likes strings very much, he likes to rotate them, sort them, rearrange characters within a string... Once he wrote a random string of characters a, b, c on a piece of paper and began to perform the following operations:
* to take two adjacent characters and replace the second character with the first one,
* to take two adjacent characters and replace the first character with the second one
To understand these actions better, let's take a look at a string Β«abcΒ». All of the following strings can be obtained by performing one of the described operations on Β«abcΒ»: Β«bbcΒ», Β«abbΒ», Β«accΒ». Let's denote the frequency of a character for each of the characters a, b and c as the number of occurrences of this character in the string. For example, for string Β«abcΒ»: |a| = 1, |b| = 1, |c| = 1, and for string Β«bbcΒ»: |a| = 0, |b| = 2, |c| = 1.
While performing the described operations, Nick sometimes got balanced strings. Let's say that a string is balanced, if the frequencies of each character differ by at most 1. That is - 1 β€ |a| - |b| β€ 1, - 1 β€ |a| - |c| β€ 1 ΠΈ - 1 β€ |b| - |c| β€ 1.
Would you help Nick find the number of different balanced strings that can be obtained by performing the operations described above, perhaps multiple times, on the given string s. This number should be calculated modulo 51123987.
Input
The first line contains integer n (1 β€ n β€ 150) β the length of the given string s. Next line contains the given string s. The initial string can be balanced as well, in this case it should be counted too. The given string s consists only of characters a, b and c.
Output
Output the only number β the number of different balanced strings that can be obtained by performing the described operations, perhaps multiple times, on the given string s, modulo 51123987.
Examples
Input
4
abca
Output
7
Input
4
abbc
Output
3
Input
2
ab
Output
1
Note
In the first sample it is possible to get 51 different strings through the described operations, but only 7 of them are balanced: Β«abcaΒ», Β«bbcaΒ», Β«bccaΒ», Β«bcaaΒ», Β«abccΒ», Β«abbcΒ», Β«aabcΒ». In the second sample: Β«abbcΒ», Β«aabcΒ», Β«abccΒ». In the third sample there is only one balanced string β Β«abΒ» itself.
Submitted Solution:
```
def solve():
n = int(input())
s = input().strip()
temp = []
temp.append(s[0])
for c in s:
if c != temp[-1]:
temp.append(c)
s_prime = ''.join(temp)
m = len(s_prime)
next_index = [[m] * 3 for _i in range(m)]
next_index[m-1][ord(s_prime[m-1])-97] = m - 1
for i in range(m-2, -1, -1):
next_index[i][0] = next_index[i+1][0]
next_index[i][1] = next_index[i+1][1]
next_index[i][2] = next_index[i+1][2]
next_index[i][ord(s_prime[i])-97] = i
mf = (n + 2) // 3
mod = 51123987
dp = [[[[0] * (mf + 2) for _i in range(mf+2)] for _j in range(mf+2)] for _k in range(m+1)]
dp[next_index[0][0]][1][0][0] = 1
dp[next_index[0][1]][0][1][0] = 1
dp[next_index[0][2]][0][0][1] = 1
for i in range(m):
for j in range(mf+1):
for k in range(mf+1):
for l in range(mf+1):
dp[next_index[i][0]][j+1][k][l] += dp[i][j][k][l]
if dp[next_index[i][0]][j+1][k][l] >= mod:
dp[next_index[i][0]][j+1][k][l] -= mod
dp[next_index[i][1]][j][k+1][l] += dp[i][j][k][l]
if dp[next_index[i][1]][j][k+1][l] >= mod:
dp[next_index[i][1]][j][k+1][l] -= mod
dp[next_index[i][2]][j][k][l+1] += dp[i][j][k][l]
if dp[next_index[i][2]][j][k][l+1] >= mod:
dp[next_index[i][2]][j][k][l+1] -= mod
ans = 0
for i in range(m):
if n % 3 == 0:
ans = (ans + dp[i][mf][mf][mf]) % mod
elif n % 3 == 1:
ans = (ans + dp[i][mf-1][mf-1][mf] + dp[i][mf-1][mf][mf-1] + dp[i][mf][mf-1][mf-1]) % mod
else:
ans = (ans + dp[i][mf-1][mf][mf] + dp[i][mf][mf-1][mf] + dp[i][mf][mf][mf-1]) % mod
print(ans)
```
No
| 253
|
Provide tags and a correct Python 3 solution for this coding contest problem.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Tags: math
Correct Solution:
```
n, m = map(int, input().split())
print(( pow(3,n,m) - 1 + m) % m)
```
| 254
|
Provide tags and a correct Python 3 solution for this coding contest problem.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Tags: math
Correct Solution:
```
a = list(map(int, input().split()))
aliens = a[0]
modulo = a[1]
print((pow(3, aliens, modulo)-1) % modulo)
```
| 255
|
Provide tags and a correct Python 3 solution for this coding contest problem.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Tags: math
Correct Solution:
```
n,m=map(int,input().split())
print((3*pow(3,n-1,m)-1)%m)
```
| 256
|
Provide tags and a correct Python 3 solution for this coding contest problem.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Tags: math
Correct Solution:
```
import sys
import string
import math
import heapq
from collections import defaultdict
from functools import lru_cache
from collections import Counter
from fractions import Fraction
def mi(s):
return map(int, s.strip().split())
def lmi(s):
return list(mi(s))
def tmi(s):
return tuple(mi(s))
def mf(f, s):
return map(f, s)
def lmf(f, s):
return list(mf(f, s))
def js(lst):
return " ".join(str(d) for d in lst)
def jsns(lst):
return "".join(str(d) for d in lst)
def line():
return sys.stdin.readline().strip()
def linesp():
return line().split()
def iline():
return int(line())
def mat(n):
matr = []
for _ in range(n):
matr.append(linesp())
return matr
def matns(n):
mat = []
for _ in range(n):
mat.append([c for c in line()])
return mat
def mati(n):
mat = []
for _ in range(n):
mat.append(lmi(line()))
return mat
def pmat(mat):
for row in mat:
print(js(row))
def fast_exp(x, n, m):
if n == 0:
return 1
elif n % 2 == 1:
return (x * fast_exp(x, (n - 1) // 2, m)**2) % m
else:
return (fast_exp(x, n // 2, m)**2) % m
def main():
n, m = mi(line())
print((fast_exp(3, n, m) - 1) % m)
main()
```
| 257
|
Provide tags and a correct Python 3 solution for this coding contest problem.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Tags: math
Correct Solution:
```
n, m = map(int, input().strip().split())
print((pow(3, n, m) - 1) % m)
```
| 258
|
Provide tags and a correct Python 3 solution for this coding contest problem.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Tags: math
Correct Solution:
```
n, m = map(int, input().split())
def fast_pow(a, b):
res, ret = a, 1
while b > 0:
if b % 2 == 1:
ret = (ret * res) % m
res = (res * res) % m
b //= 2
return ret % m
print((fast_pow(3, n) - 1) % m)
```
| 259
|
Provide tags and a correct Python 3 solution for this coding contest problem.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Tags: math
Correct Solution:
```
n,m=map(int,input().split())
x=pow(3,n-1,m)
ans=(x*2+x-1)%m
print(ans)
```
| 260
|
Provide tags and a correct Python 3 solution for this coding contest problem.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Tags: math
Correct Solution:
```
def pow(a, b, m):
res = 1
while(b):
if b & 1:
res = res*a % m
b = b>>1
a = a*a%m
return res
n, m = map(int, input().split())
print((pow(3, n, m)-1)%m)
```
| 261
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Submitted Solution:
```
def binpow(a,n):
res = 1
while(n>0):
if(n&1):
res = (res*a)%m
a = (a*a)%m
n>>=1
return res
n,m = map(int,input().split())
ans = binpow(3,n)-1
if(ans%m ==0 and ans != 0):
print(m-1)
else:
print(ans%m)
```
Yes
| 262
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Submitted Solution:
```
import sys
from functools import lru_cache, cmp_to_key
from heapq import merge, heapify, heappop, heappush
# from math import *
from collections import defaultdict as dd, deque, Counter as C
from itertools import combinations as comb, permutations as perm
from bisect import bisect_left as bl, bisect_right as br, bisect
from time import perf_counter
from fractions import Fraction
import copy
import time
starttime = time.time()
mod = int(pow(10, 9) + 7)
mod2 = 998244353
# from sys import stdin
# input = stdin.readline
def data(): return sys.stdin.readline().strip()
def out(*var, end="\n"): sys.stdout.write(' '.join(map(str, var))+end)
def L(): return list(sp())
def sl(): return list(ssp())
def sp(): return map(int, data().split())
def ssp(): return map(str, data().split())
def l1d(n, val=0): return [val for i in range(n)]
def l2d(n, m, val=0): return [l1d(n, val) for j in range(m)]
try:
# sys.setrecursionlimit(int(pow(10,6)))
sys.stdin = open("input.txt", "r")
# sys.stdout = open("../output.txt", "w")
except:
pass
def pmat(A):
for ele in A:
print(ele,end="\n")
n,m=L()
print((pow(3,n,m)-1)%m)
endtime = time.time()
# print(f"Runtime of the program is {endtime - starttime}")
```
Yes
| 263
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Submitted Solution:
```
def modpow(a, b, n):
if b == 0:
return 1
if b == 1:
return a % n
tmp = modpow(a, b // 2, n) % n
tmp = (tmp * tmp) % n
if b % 2 == 1:
return (tmp * a) % n
else:
return tmp
def main():
n, m = map(int, input().split())
ans = (modpow(3, n, m) - 1) % m
print(ans)
if __name__ == "__main__":
main()
```
Yes
| 264
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Submitted Solution:
```
def main(a,b):
return (pow(3,a,b)-1 )%b
a,b=list(map(int,input().split()))
print(main(a,b))
```
Yes
| 265
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Submitted Solution:
```
n, m = map(int, input().split())
def mod_exp(a, b, n):
x = a
y = 1
while b > 0:
if b%2:
y = (y*x)%n
x = (x*x)%n
b = b >> 1
return y
print(mod_exp(3, n, m)-1)
```
No
| 266
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Submitted Solution:
```
#!/usr/bin/env python3
# -*- coding: utf-8 -*-
"""
Created on Sat Aug 1 18:48:05 2020
@author: shailesh
"""
n,m = [int(i) for i in input().split()]
ans = pow(3,n,m) - 1
if ans == -1:
ans = m-1
print(m)
```
No
| 267
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Submitted Solution:
```
n, m = map(int, input().split())
ans = pow(3, n, m)
if n % 2 == 1:
ans -= 1
else:
ans += 1
print(ans % m)
```
No
| 268
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
An expedition group flew from planet ACM-1 to Earth in order to study the bipedal species (its representatives don't even have antennas on their heads!).
The flying saucer, on which the brave pioneers set off, consists of three sections. These sections are connected by a chain: the 1-st section is adjacent only to the 2-nd one, the 2-nd one β to the 1-st and the 3-rd ones, the 3-rd one β only to the 2-nd one. The transitions are possible only between the adjacent sections.
The spacecraft team consists of n aliens. Each of them is given a rank β an integer from 1 to n. The ranks of all astronauts are distinct. The rules established on the Saucer, state that an alien may move from section a to section b only if it is senior in rank to all aliens who are in the segments a and b (besides, the segments a and b are of course required to be adjacent). Any alien requires exactly 1 minute to make a move. Besides, safety regulations require that no more than one alien moved at the same minute along the ship.
Alien A is senior in rank to alien B, if the number indicating rank A, is more than the corresponding number for B.
At the moment the whole saucer team is in the 3-rd segment. They all need to move to the 1-st segment. One member of the crew, the alien with the identification number CFR-140, decided to calculate the minimum time (in minutes) they will need to perform this task.
Help CFR-140, figure out the minimum time (in minutes) that all the astronauts will need to move from the 3-rd segment to the 1-st one. Since this number can be rather large, count it modulo m.
Input
The first line contains two space-separated integers: n and m (1 β€ n, m β€ 109) β the number of aliens on the saucer and the number, modulo which you should print the answer, correspondingly.
Output
Print a single number β the answer to the problem modulo m.
Examples
Input
1 10
Output
2
Input
3 8
Output
2
Note
In the first sample the only crew member moves from segment 3 to segment 2, and then from segment 2 to segment 1 without any problems. Thus, the whole moving will take two minutes.
To briefly describe the movements in the second sample we will use value <image>, which would correspond to an alien with rank i moving from the segment in which it is at the moment, to the segment number j. Using these values, we will describe the movements between the segments in the second sample: <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>, <image>; In total: the aliens need 26 moves. The remainder after dividing 26 by 8 equals 2, so the answer to this test is 2.
Submitted Solution:
```
n, m = map(int, input().split())
print(pow(3, n, m) - 1)
```
No
| 269
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Tags: binary search, combinatorics, two pointers
Correct Solution:
```
######### ## ## ## #### ##### ## # ## # ##
# # # # # # # # # # # # # # # # # # #
# # # # ### # # # # # # # # # # # #
# ##### # # # # ### # # # # # # # # #####
# # # # # # # # # # # # # # # # # #
######### # # # # ##### # ##### # ## # ## # #
"""
PPPPPPP RRRRRRR OOOO VV VV EEEEEEEEEE
PPPPPPPP RRRRRRRR OOOOOO VV VV EE
PPPPPPPPP RRRRRRRRR OOOOOOOO VV VV EE
PPPPPPPP RRRRRRRR OOOOOOOO VV VV EEEEEE
PPPPPPP RRRRRRR OOOOOOOO VV VV EEEEEEE
PP RRRR OOOOOOOO VV VV EEEEEE
PP RR RR OOOOOOOO VV VV EE
PP RR RR OOOOOO VV VV EE
PP RR RR OOOO VVVV EEEEEEEEEE
"""
"""
Perfection is achieved not when there is nothing more to add, but rather when there is nothing more to take away.
"""
import sys
input = sys.stdin.readline
read = lambda: map(int, input().split())
read_float = lambda: map(float, input().split())
# from bisect import bisect_left as lower_bound;
# from bisect import bisect_right as upper_bound;
# from math import ceil, factorial;
def ceil(x):
if x != int(x):
x = int(x) + 1
return x
def factorial(x, m):
val = 1
while x>0:
val = (val * x) % m
x -= 1
return val
def fact(x):
val = 1
while x > 0:
val *= x
x -= 1
return val
# swap_array function
def swaparr(arr, a,b):
temp = arr[a];
arr[a] = arr[b];
arr[b] = temp;
## gcd function
def gcd(a,b):
if b == 0:
return a;
return gcd(b, a % b);
## lcm function
def lcm(a, b):
return (a * b) // math.gcd(a, b)
## nCr function efficient using Binomial Cofficient
def nCr(n, k):
if k > n:
return 0
if(k > n - k):
k = n - k
res = 1
for i in range(k):
res = res * (n - i)
res = res / (i + 1)
return int(res)
## upper bound function code -- such that e in a[:i] e < x;
## prime factorization
def primefs(n):
## if n == 1 ## calculating primes
primes = {}
while(n%2 == 0 and n > 0):
primes[2] = primes.get(2, 0) + 1
n = n//2
for i in range(3, int(n**0.5)+2, 2):
while(n%i == 0 and n > 0):
primes[i] = primes.get(i, 0) + 1
n = n//i
if n > 2:
primes[n] = primes.get(n, 0) + 1
## prime factoriazation of n is stored in dictionary
## primes and can be accesed. O(sqrt n)
return primes
## MODULAR EXPONENTIATION FUNCTION
def power(x, y, p):
res = 1
x = x % p
if (x == 0) :
return 0
while (y > 0) :
if ((y & 1) == 1) :
res = (res * x) % p
y = y >> 1
x = (x * x) % p
return res
## DISJOINT SET UNINON FUNCTIONS
def swap(a,b):
temp = a
a = b
b = temp
return a,b;
# find function with path compression included (recursive)
# def find(x, link):
# if link[x] == x:
# return x
# link[x] = find(link[x], link);
# return link[x];
# find function with path compression (ITERATIVE)
def find(x, link):
p = x;
while( p != link[p]):
p = link[p];
while( x != p):
nex = link[x];
link[x] = p;
x = nex;
return p;
# the union function which makes union(x,y)
# of two nodes x and y
def union(x, y, link, size):
x = find(x, link)
y = find(y, link)
if size[x] < size[y]:
x,y = swap(x,y)
if x != y:
size[x] += size[y]
link[y] = x
## returns an array of boolean if primes or not USING SIEVE OF ERATOSTHANES
def sieve(n):
prime = [True for i in range(n+1)]
prime[0], prime[1] = False, False
p = 2
while (p * p <= n):
if (prime[p] == True):
for i in range(p * p, n+1, p):
prime[i] = False
p += 1
return prime
# Euler's Toitent Function phi
def phi(n) :
result = n
p = 2
while(p * p<= n) :
if (n % p == 0) :
while (n % p == 0) :
n = n // p
result = result * (1.0 - (1.0 / (float) (p)))
p = p + 1
if (n > 1) :
result = result * (1.0 - (1.0 / (float)(n)))
return (int)(result)
def is_prime(n):
if n == 0:
return False
if n == 1:
return True
for i in range(2, int(n ** (1 / 2)) + 1):
if not n % i:
return False
return True
#### PRIME FACTORIZATION IN O(log n) using Sieve ####
MAXN = int(1e5 + 5)
def spf_sieve():
spf[1] = 1;
for i in range(2, MAXN):
spf[i] = i;
for i in range(4, MAXN, 2):
spf[i] = 2;
for i in range(3, ceil(MAXN ** 0.5), 2):
if spf[i] == i:
for j in range(i*i, MAXN, i):
if spf[j] == j:
spf[j] = i;
## function for storing smallest prime factors (spf) in the array
################## un-comment below 2 lines when using factorization #################
spf = [0 for i in range(MAXN)]
# spf_sieve();
def factoriazation(x):
res = []
for i in range(2, int(x ** 0.5) + 1):
while x % i == 0:
res.append(i)
x //= i
if x != 1:
res.append(x)
return res
## this function is useful for multiple queries only, o/w use
## primefs function above. complexity O(log n)
def factors(n):
res = []
for i in range(1, int(n ** 0.5) + 1):
if n % i == 0:
res.append(i)
res.append(n // i)
return list(set(res))
## taking integer array input
def int_array():
return list(map(int, input().strip().split()));
def float_array():
return list(map(float, input().strip().split()));
## taking string array input
def str_array():
return input().strip().split();
def binary_search(low, high, w, h, n):
while low < high:
mid = low + (high - low) // 2
# print(low, mid, high)
if check(mid, w, h, n):
low = mid + 1
else:
high = mid
return low
## for checking any conditions
def check(councils, a, k):
summ = 0
for x in a:
summ += min(x, councils)
return summ // councils >= k
#defining a couple constants
MOD = int(1e9)+7;
CMOD = 998244353;
INF = float('inf'); NINF = -float('inf');
################### ---------------- TEMPLATE ENDS HERE ---------------- ###################
from itertools import permutations
import math
import bisect as bis
import random
import sys
def solve():
n, d = read()
coordinates = list(read())
m = {}
s = 0
for i in range(n - 2):
a = bis.bisect_right(coordinates, coordinates[i] + d) - i - 2
s += a * (a + 1) // 2
print(s)
if __name__ == '__main__':
for _ in range(1):
solve()
# fin_time = datetime.now()
# print("Execution time (for loop): ", (fin_time-init_time))
```
| 270
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Tags: binary search, combinatorics, two pointers
Correct Solution:
```
nd=input().split()
n=int(nd[0])
d=int(nd[1])
x=input().split()
for i in range(n):
x[i]=int(x[i])
s=0
j=0
for i in range(n):
while j < n and x[j]-x[i] <= d:
j+=1
k=j-i-1
s+=(k*(k-1))//2
print(s)
```
| 271
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Tags: binary search, combinatorics, two pointers
Correct Solution:
```
def main():
n, d = map(int, input().split())
X = [int(x) for x in input().split()]
cnt = 0
for i in range(n):
l = i
r = n - 1
j = -1
while(l <= r):
m = l + (r - l) // 2
if X[m] - X[i] <= d:
l = m + 1
j = max(j, m)
else:
r = m - 1
if j != -1:
cnt += (j - i - 1) * (j - i) // 2
print(cnt)
if __name__ == "__main__":
main()
```
| 272
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Tags: binary search, combinatorics, two pointers
Correct Solution:
```
from collections import deque
from math import factorial
nd = input()
nd = nd.split()
n = int(nd[0])
d = int(nd[1])
xcorr = list(map(int, input().split()))
dq = deque()
g = 0
for x in xcorr:
dq.append(x)
while (x - dq[0]) > d:
if len(dq) >= 4:
g += (len(dq)-2)*(len(dq)-2-1)/2
#factorial(len(dq)-2)/(factorial(len(dq)-2-2)*2)
dq.popleft()
if len(dq) >= 3:
g += len(dq)*(len(dq)-1)*(len(dq)-2)/2/3
#factorial(len(dq))/(factorial(len(dq)-3)*2*3)
print(int(g))
```
| 273
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Tags: binary search, combinatorics, two pointers
Correct Solution:
```
n, k = list(map(int, input().split()))
lis = list(map(int, input().split()))
def find(s, lis, a, k):
l = s
r = len(lis) - 1
while (r - l) > 1:
mid = (l + r) // 2
if lis[mid] < a + k:
l = mid
else:
r = mid
if lis[r] <= a + k:
return r
return l
nat = 0
def entekhab(y):
return int(y * (y - 1) / 2)
s = 0
for i in range(n):
now = lis[i]
loc = find(i, lis, now, k)
if now + k >= lis[loc]:
nat += entekhab(loc - i)
print(int(nat))
```
| 274
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Tags: binary search, combinatorics, two pointers
Correct Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Mon May 16 17:14:14 2016
@author: Hangell
"""
from collections import deque
str1=input()
str2=input()
n=int(str1.split()[0])
d=int(str1.split()[1])
numlist=str2.split()
newdeque=deque()
Sum=0
cha=0
way=0
for i in range(n):
numlist[i]=int(numlist[i])
for i in range(n-1):
cha=numlist[i+1]-numlist[i]
newdeque.append(cha)
Sum+=cha
while Sum>d and len(newdeque)!=0:
Sum-=newdeque.popleft()
if len(newdeque)>1:
way+=(len(newdeque)-1)*len(newdeque)/2
print(int(way))
```
| 275
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Tags: binary search, combinatorics, two pointers
Correct Solution:
```
from sys import *
from math import *
n,k=map(int,stdin.readline().split())
a=list(map(int,stdin.readline().split()))
ans=0
for i in range(n-2):
x=a[i]+k
l=i+2
h=n-1
j=0
f=0
while l<=h:
m=(l+h)//2
if a[m]>x:
h=m-1
elif a[m]<=x:
j=m
l=m+1
f=1
if f==1:
y=j-i-2
ans+=(y+1)*(y+2)//2
print(ans)
```
| 276
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Tags: binary search, combinatorics, two pointers
Correct Solution:
```
from sys import stdin,stdout,stderr
def binary(lo,hi,value):
global a
ans=lo
while lo<=hi:
mid=(lo+hi)//2
if a[mid]<=value:
ans=mid
lo=mid+1
else:hi=mid-1
return ans
n,d=map(int,input().split())
a=[int(x)for x in input().split()]
ans=0
for i in range(n):
lo=binary(i+1,n-1,a[i]+d)
lo=(lo-i)
ans=ans+lo*(lo-1)/2
print(int(ans))
```
| 277
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Submitted Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
def main():
pass
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
main()
n,m = map(int,input().split())
l = list(map(int,input().split()))
l.sort()
# 1 2 3 6 7
ans=0
i=0
for j in range(n):
while l[j]-l[i]>m:
i+=1
if l[j]-l[i]<=m:
ans+=((j-i)*(j-i-1))//2
print(ans)
```
Yes
| 278
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Submitted Solution:
```
# n=int(input())
# n,k=map(int,input().split())
'''l=0
r=10**13
while l+1<r:
mid=(l+r)//2
val=(max(0,b_b*mid-b)*rb+max(0,b_s*mid-s)*rs+max(0,b_c*mid-b)*rc)
if val>money:
r=mid
if val<=money:
l=mid'''
# arr=list(map(int,input().split()))
# n=int(input())
# n,k=map(int,input().split())
# arr=list(map(int,input().split()))
n,d=map(int,input().split())
arr=list(map(int,input().split()))
i=0
ans=0
for j in range(n):
while j-i>=3 and arr[j]-arr[i]>d:
i+=1
if arr[j]-arr[i]<=d:
ans+=(j-i)*(j-i-1)//2
print(ans)
```
Yes
| 279
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Submitted Solution:
```
import bisect
n,d = [int(x) for x in input().split()]
a = [int(x) for x in input().split()]
ans =0
for i in range(0,n):
x = bisect.bisect_right(a,a[i]+d)
ans+=(x-i-1)*(x-i-2)//2
print(ans)
```
Yes
| 280
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Submitted Solution:
```
from bisect import bisect_left
def sol(a,n,d):
ans = 0
for i in range(n-2):
x = a[i]+d
pos = bisect_left(a,x)
if pos < n and a[pos] == x:
pos+=1
x = pos - (i+2)
ans+=((x*(x+1))//2)
return ans
n,d = map(int,input().split())
a = [int(i) for i in input().split()]
print(sol(a,n,d))
```
Yes
| 281
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Submitted Solution:
```
n, d = list(map(int, input().split()))
x = list(map(int, input().split()))
i = 0
j = i + 2
count = 0
in_betn = 1
while(j-i-1 >= 1 and j<n):
# print(x[j] - x[i])
while(j<n and x[j] - x[i] <= d):
count += (in_betn * (in_betn+1) / 2)
j += 1
in_betn += 1
# print("here")
in_betn -= 1
i += 1
print(int(count))
```
No
| 282
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Submitted Solution:
```
n, d = map(int, input().split())
x = list(map(int, input().split()))
k = 0
j = 1
for i in range(n):
p = 0
while (j < n and x[j] - x[i] <= d):
k += (max(0, (j - i - 1)))
j += 1
p += 1
if (p == 0):
k += (max(0, j - i - 2))
print(k)
```
No
| 283
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Submitted Solution:
```
def cnk(n):
return 0 if 3 > n else n * (n - 1) * (n - 2) // 6
n, d = input().split()
n, d = int(n), float(d)
dots = list(map(int, input().split()))
l, r, res = 0, 0, 0
while l < n:
while r < n and dots[r] - dots[l] <= d:
r += 1
res += cnk(r - l)
if r == n:
break
while l < r and dots[r] - dots[l] > d:
l += 1
print(res)
```
No
| 284
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little Petya likes points a lot. Recently his mom has presented him n points lying on the line OX. Now Petya is wondering in how many ways he can choose three distinct points so that the distance between the two farthest of them doesn't exceed d.
Note that the order of the points inside the group of three chosen points doesn't matter.
Input
The first line contains two integers: n and d (1 β€ n β€ 105; 1 β€ d β€ 109). The next line contains n integers x1, x2, ..., xn, their absolute value doesn't exceed 109 β the x-coordinates of the points that Petya has got.
It is guaranteed that the coordinates of the points in the input strictly increase.
Output
Print a single integer β the number of groups of three points, where the distance between two farthest points doesn't exceed d.
Please do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier.
Examples
Input
4 3
1 2 3 4
Output
4
Input
4 2
-3 -2 -1 0
Output
2
Input
5 19
1 10 20 30 50
Output
1
Note
In the first sample any group of three points meets our conditions.
In the seconds sample only 2 groups of three points meet our conditions: {-3, -2, -1} and {-2, -1, 0}.
In the third sample only one group does: {1, 10, 20}.
Submitted Solution:
```
def busquedaBinaria(arr,n,item):
aux2=0
i=0
k=item
while(i!=len(arr)):
val = arr[i] + k
#print(val)
encontrado = False
primero = 0
ultimo = len(arr) - 1
#print("entro en while1")
while primero <= ultimo:
#print("entro en while2")
puntoMedio = (primero + ultimo) // 2
if arr[puntoMedio] == val:
#print("lo encontro")
encontrado = True
break
else:
if item < arr[puntoMedio]:
ultimo = puntoMedio - 1
else:
primero = puntoMedio + 1
if (encontrado==True and (i+2)!=(k)):
encontrado=False
posicion =abs(puntoMedio - i - 1)
#print(puntoMedio)
#print(posicion)
aux2 += posicion*(posicion + 1) // 2
#print(aux2)
#print("")
i += 1
k = item
elif((encontrado== False) and (i+2)!=(k)):
k-=1
else:
k=item
i+=1
return aux2
arr=[]
n,k = list(map(int,input().strip().split()))
arr = list(map(int,input().strip().split()))
print(busquedaBinaria(arr,n,k))
```
No
| 285
|
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Tags: games, greedy
Correct Solution:
```
from collections import Counter
s=input()
dic=Counter(s)
count=0
for val in dic.values():
if val%2!=0:
count+=1
if count==0:
print("First")
elif count%2==0:
print("Second")
else:
print("First")
```
| 286
|
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Tags: games, greedy
Correct Solution:
```
from collections import Counter
def iswin(c):
if c == c[::-1]:
return True, None
else:
co = Counter(c)
ae = 0
k1 = c[0]
for k, v in co.items():
if v%2==0:
ae += 1
k1 = k
if ae == len(co) or len(co)%2==1 and ae == len(co)-1:
return True, None
else:
return False, k1
s = input()
p = True
res = ''
while s:
# print(s)
r, k = iswin(s)
if not r:
i = s.index(k)
s = s[:i] + s[min(i+1, len(s)-1):]
else:
if p:
res = 'First'
else:
res = 'Second'
break
p = not p
print(res)
```
| 287
|
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Tags: games, greedy
Correct Solution:
```
if __name__ == '__main__':
s = input()
c = [s.count(x) for x in set(s)]
total = 0
for x in c:
if x % 2 != 0:
total += 1
if total % 2 == 0 and total != 0:
print("Second")
else:
print("First")
```
| 288
|
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Tags: games, greedy
Correct Solution:
```
# Description of the problem can be found at http://codeforces.com/problemset/problem/276/B
s = input()
d_e = {}
n_o = 0
for c in s:
if c not in d_e:
d_e[c] = 0
d_e[c] += 1
if (d_e[c] % 2 == 1):
n_o += 1
else:
n_o -= 1
if n_o == 0:
print("First")
elif n_o % 2 == 1:
print("First")
else:
print("Second")
```
| 289
|
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Tags: games, greedy
Correct Solution:
```
import sys
arr = ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
def check(d):
w = 0
for i in d:
if(d[i]%2!=0):
w = w+1
return w
def deeznuts(n):
b = []
for i in n :
b.append(n.count(i))
d = dict(zip(n,b))
w = check(d)
if len(n)%2 == 0 and w == 0:
print('First')
if len(n)%2 == 0 and w!= 0:
print('Second')
if len(n)%2 !=0 and (w%2)!=0:
print('First')
if len(n)%2 !=0 and (w%2)==0:
print('Second')
if __name__ == '__main__':
input = sys.stdin.read()
data = list(map(str, input.split()))
n = list(data[0])
deeznuts(n)
```
| 290
|
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Tags: games, greedy
Correct Solution:
```
s=list(input())
for n in s:
if n==' ':
s.remove(n)
def normalisation(s):
c=[]
b=set()
for letter in s:
if letter in b:
continue
if s.count(letter)%2==1:
c.append(letter)
b.add(letter)
return c
s=normalisation(s)
def check(s,odds,b):
c=len(s)
if c==1 or c==0:
return True
elif c>1 and odds==c and b==c:
return False
letter=s[b]
count=s.count(letter)
if count%2==0:
while count!=0:
s.remove(letter)
count-=1
return check(s,odds,b)
else:
while count!=1:
s.remove(letter)
count-=1
odds+=1
b+=1
return check(s,odds,b)
count=2
while True:
if count%2==0:
player='First'
else:
player='Second'
if check(s,0,0):
print(player)
break
s.pop(0)
count+=1
```
| 291
|
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Tags: games, greedy
Correct Solution:
```
s = input()
dict = {}
l = list(s)
total = -1
for i in l:
if i in dict:
continue
else:
c = l.count(i)
dict[i] = c
if c%2:
total += 1
if total == -1:
print("First")
elif total%2:
print("Second")
else:
print("First")
```
| 292
|
Provide tags and a correct Python 3 solution for this coding contest problem.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Tags: games, greedy
Correct Solution:
```
word = input()
count = 0
for char in set(word):
if word.count(char) & 1:
count += 1
if count == 0 or count&1:
print("First")
else:
print("Second")
```
| 293
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Submitted Solution:
```
s=input()
n=len(s)
a=[0]*30
for i in range(n):
a[ord(s[i])-97]+=1
odd=0
for i in range(26):
if(a[i]&1):
odd+=1
if(odd==0 or odd&1):
print("First")
else:
print("Second")
```
Yes
| 294
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Submitted Solution:
```
word = input()
lets = [0] * 26
for c in word:
lets[ord(c) - 97] += 1
c = 0
for e in lets:
if e % 2 == 1:
c += 1
if c == 0 or c % 2 == 1:
print('First')
else:
print('Second')
```
Yes
| 295
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Submitted Solution:
```
s = input()
counts = {}
for i in s:
if (i not in counts):
counts[i] = 0
counts[i] += 1
dist = 0
for i in counts:
dist += int(counts[i] % 2 == 1)
if (dist == 0) or (dist % 2 == 1):
print ('First')
else:
print ('Second')
```
Yes
| 296
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Submitted Solution:
```
def GirlAndTheGame(str):
game = list(str)
odd = [item for item in game if game.count(item)%2!=0]
oddOneOut = len(set(odd))
if oddOneOut == 0 or oddOneOut%2==1:
print('First')
else:
print('Second')
GirlAndTheGame(input())
```
Yes
| 297
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Submitted Solution:
```
from collections import Counter
s = list(input())
cnt = Counter(s)
check = 0
for ch in cnt:
if cnt[ch]%2 == 1:
check += 1
if check % 2 == 0:
print("Second")
else:
print("First")
```
No
| 298
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Little Girl loves problems on games very much. Here's one of them.
Two players have got a string s, consisting of lowercase English letters. They play a game that is described by the following rules:
* The players move in turns; In one move the player can remove an arbitrary letter from string s.
* If the player before his turn can reorder the letters in string s so as to get a palindrome, this player wins. A palindrome is a string that reads the same both ways (from left to right, and vice versa). For example, string "abba" is a palindrome and string "abc" isn't.
Determine which player will win, provided that both sides play optimally well β the one who moves first or the one who moves second.
Input
The input contains a single line, containing string s (1 β€ |s| β€ 103). String s consists of lowercase English letters.
Output
In a single line print word "First" if the first player wins (provided that both players play optimally well). Otherwise, print word "Second". Print the words without the quotes.
Examples
Input
aba
Output
First
Input
abca
Output
Second
Submitted Solution:
```
x=list(input())
c=0
i=0
while i<(len(x)):
if x[i]==x[len(x)-i-1]:
i+=1
continue
elif x[len(x)-i-1]==x[i]:
x.pop(i)
else:
x.pop(len(x)-i-1)
c+=1
if c%2==0:
print("First")
else:
print("Second")
```
No
| 299
|
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