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int64 450
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int64 900
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Princess Twilight went to Celestia and Luna's old castle to research the chest from the Elements of Harmony.
<image>
A sequence of positive integers bi is harmony if and only if for every two elements of the sequence their greatest common divisor equals 1. According to an ancient book, the key of the chest is a harmony sequence bi which minimizes the following expression:
<image>
You are given sequence ai, help Princess Twilight to find the key.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of elements of the sequences a and b. The next line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 30).
Output
Output the key — sequence bi that minimizes the sum described above. If there are multiple optimal sequences, you can output any of them.
Examples
Input
5
1 1 1 1 1
Output
1 1 1 1 1
Input
5
1 6 4 2 8
Output
1 5 3 1 8
Submitted Solution:
```
import sys
readline = sys.stdin.readline
def gcd(a, b):
while b:
a, b = b, a%b
return a
limit = 45
C = set([tuple()])
for i in range(2, limit+1):
for k in C.copy():
if all(gcd(ki, i) == 1 for ki in k):
kn = tuple(list(k) + [i])
C.add(kn)
INF = 10**9+7
N = int(readline())
A = list(map(int, readline().split()))
Ao = A[:]
A.sort()
ans = INF
Ans = None
for ci in C:
tc = [1]*(N-len(ci)) + list(ci)
res = 0
for a, t in zip(A, tc):
res += abs(a-t)
if ans > res:
ans = res
Ans = tc
buc = [[] for _ in range(limit+1)]
for a, an in zip(A, Ans):
buc[a].append(an)
AA = []
for ao in Ao:
AA.append(buc[ao].pop())
#print(ans)
print(*AA)
```
|
instruction
| 0
| 107,337
| 2
| 214,674
|
No
|
output
| 1
| 107,337
| 2
| 214,675
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Princess Twilight went to Celestia and Luna's old castle to research the chest from the Elements of Harmony.
<image>
A sequence of positive integers bi is harmony if and only if for every two elements of the sequence their greatest common divisor equals 1. According to an ancient book, the key of the chest is a harmony sequence bi which minimizes the following expression:
<image>
You are given sequence ai, help Princess Twilight to find the key.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of elements of the sequences a and b. The next line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 30).
Output
Output the key — sequence bi that minimizes the sum described above. If there are multiple optimal sequences, you can output any of them.
Examples
Input
5
1 1 1 1 1
Output
1 1 1 1 1
Input
5
1 6 4 2 8
Output
1 5 3 1 8
Submitted Solution:
```
import sys
readline = sys.stdin.readline
def gcd(a, b):
while b:
a, b = b, a%b
return a
limit = 30
C = set([tuple()])
for i in range(2, limit+1):
for k in C.copy():
if all(gcd(ki, i) == 1 for ki in k):
kn = tuple(list(k) + [i])
C.add(kn)
INF = 10**9+7
N = int(readline())
A = list(map(int, readline().split()))
Ao = A[:]
A.sort()
ans = INF
Ans = None
for ci in C:
tc = [1]*(N-len(ci)) + list(ci)
res = 0
for a, t in zip(A, tc):
res += abs(a-t)
if ans > res:
ans = res
Ans = tc
buc = [[] for _ in range(limit+1)]
for a, an in zip(A, Ans):
buc[a].append(an)
AA = []
for ao in Ao:
AA.append(buc[ao].pop())
#print(ans)
print(*AA)
```
|
instruction
| 0
| 107,338
| 2
| 214,676
|
No
|
output
| 1
| 107,338
| 2
| 214,677
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Princess Twilight went to Celestia and Luna's old castle to research the chest from the Elements of Harmony.
<image>
A sequence of positive integers bi is harmony if and only if for every two elements of the sequence their greatest common divisor equals 1. According to an ancient book, the key of the chest is a harmony sequence bi which minimizes the following expression:
<image>
You are given sequence ai, help Princess Twilight to find the key.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of elements of the sequences a and b. The next line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 30).
Output
Output the key — sequence bi that minimizes the sum described above. If there are multiple optimal sequences, you can output any of them.
Examples
Input
5
1 1 1 1 1
Output
1 1 1 1 1
Input
5
1 6 4 2 8
Output
1 5 3 1 8
Submitted Solution:
```
import sys
readline = sys.stdin.readline
def gcd(a, b):
while b:
a, b = b, a%b
return a
def prsh(N):
prime = [2]
for L in range(3,N):
for p in prime:
if not L % p:
break
if p > L**(1/2):
prime.append(L)
break
return prime
limit = 59
prime = prsh(limit+1)
C = set([tuple()])
Cp = []
for i in range(2, limit+1):
if i >= 30 and i in prime:
Cp.append(i)
continue
for k in C.copy():
if all(gcd(ki, i) == 1 for ki in k):
kn = tuple(list(k) + [i])
C.add(kn)
INF = 10**9+7
N = int(readline())
A = list(map(int, readline().split()))
Ao = A[:]
A.sort()
ans = INF
Ans = None
for ci in C:
tc = [1]*(N-len(ci)) + list(ci) + Cp
for j in range(8):
res = 0
for a, t in zip(A, tc[j:]):
res += abs(a-t)
if ans > res:
ans = res
Ans = tc
buc = [[] for _ in range(limit+1)]
for a, an in zip(A, Ans):
buc[a].append(an)
AA = []
for ao in Ao:
AA.append(buc[ao].pop())
#print(ans)
print(*AA)
```
|
instruction
| 0
| 107,339
| 2
| 214,678
|
No
|
output
| 1
| 107,339
| 2
| 214,679
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
|
instruction
| 0
| 107,531
| 2
| 215,062
|
Tags: math
Correct Solution:
```
from sys import stdin, stdout
from math import factorial
n = int(stdin.readline())
values = list(map(int, stdin.readline().split()))
ans = 0
cnt = 1
for i in range(1, n):
if values[i] != values[i - 1]:
ans += cnt * (cnt + 1) // 2
cnt = 1
else:
cnt += 1
ans += cnt * (cnt + 1) // 2
stdout.write(str(ans))
```
|
output
| 1
| 107,531
| 2
| 215,063
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
|
instruction
| 0
| 107,532
| 2
| 215,064
|
Tags: math
Correct Solution:
```
import math
def choose(n, k):
return n - k + 1
class CodeforcesTask84BSolution:
def __init__(self):
self.result = ''
self.n = 0
self.array = []
def read_input(self):
self.n = int(input())
self.array = [int(x) for x in input().split(" ")]
def process_task(self):
magic_arrays = 0
cr = 10 ** 10
cn = 0
for a in self.array:
if a == cr:
cn += 1
else:
if cn:
for x in range(1, cn + 1):
magic_arrays += choose(cn, x)
cr = a
cn = 1
for x in range(1, cn + 1):
magic_arrays += choose(cn, x)
self.result = str(int(magic_arrays))
def get_result(self):
return self.result
if __name__ == "__main__":
Solution = CodeforcesTask84BSolution()
Solution.read_input()
Solution.process_task()
print(Solution.get_result())
```
|
output
| 1
| 107,532
| 2
| 215,065
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
|
instruction
| 0
| 107,533
| 2
| 215,066
|
Tags: math
Correct Solution:
```
#------------------------template--------------------------#
import os
import sys
from math import *
from collections import *
from fractions import *
from bisect import *
from heapq import*
from io import BytesIO, IOBase
def vsInput():
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
ALPHA='abcdefghijklmnopqrstuvwxyz'
MOD=1000000007
def value():return tuple(map(int,input().split()))
def array():return [int(i) for i in input().split()]
def Int():return int(input())
def Str():return input()
def arrayS():return [i for i in input().split()]
#-------------------------code---------------------------#
# vsInput()
n=Int()
a=array()
i=0
ans=0
while(i<n):
l=1
i+=1
while(i<n and a[i]==a[i-1]):
l+=1
i+=1
ans+=l*(l+1)//2
print(ans)
```
|
output
| 1
| 107,533
| 2
| 215,067
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
|
instruction
| 0
| 107,534
| 2
| 215,068
|
Tags: math
Correct Solution:
```
input()
c=a=r=0
for i in input().split():c=(a==i)*c+1;a=i;r+=c
print(r)
# Made By Mostafa_Khaled
```
|
output
| 1
| 107,534
| 2
| 215,069
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
|
instruction
| 0
| 107,535
| 2
| 215,070
|
Tags: math
Correct Solution:
```
n = int(input())
arr = list(map(int,input().split()))
ans = 0
cnt = 1
for i in range(n-1):
if arr[i] == arr[i+1]:
cnt += 1
continue
ans += (cnt*(cnt+1))//2
cnt = 1
ans += (cnt*(cnt+1))//2
print(ans)
```
|
output
| 1
| 107,535
| 2
| 215,071
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
|
instruction
| 0
| 107,536
| 2
| 215,072
|
Tags: math
Correct Solution:
```
n = int(input())
A = list(map(int, input().split()))
j = 0
ans = 0
for i in range(n):
while j < n:
if A[i] == A[j]:
j += 1
else:
break
ans += j-i
if i == j:
j += 1
print(ans)
```
|
output
| 1
| 107,536
| 2
| 215,073
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
|
instruction
| 0
| 107,537
| 2
| 215,074
|
Tags: math
Correct Solution:
```
n=int(input())
arr = [int(x) for x in input().strip().split()]
arr1=arr[0]
c=1
s=0
for ele in arr[1:]:
if arr1==ele:
c+=1
else :
s+=(c*(c-1))//2
c=1
arr1=ele
s+=(c*(c-1))//2
print(n+s)
```
|
output
| 1
| 107,537
| 2
| 215,075
|
Provide tags and a correct Python 3 solution for this coding contest problem.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
|
instruction
| 0
| 107,538
| 2
| 215,076
|
Tags: math
Correct Solution:
```
input()
L,ans='',0
for x in input().split():
if x==L:
z+=1
else:
if L!='':
ans+=z*(z+1)//2
z,L=1,x
ans+=z*(z+1)//2
print(ans)
```
|
output
| 1
| 107,538
| 2
| 215,077
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
n = int(input())
a = list(map(int, input().split()))
cur = 0
ans = 0
for i in range(n):
if i and a[i] != a[i-1]:
cur = 0
cur += 1
ans += cur
print(ans)
```
|
instruction
| 0
| 107,539
| 2
| 215,078
|
Yes
|
output
| 1
| 107,539
| 2
| 215,079
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
import sys
import math
from collections import defaultdict
import itertools
MAXNUM = math.inf
MINNUM = -1 * math.inf
def getInt():
return int(sys.stdin.readline().rstrip())
def getInts():
return map(int, sys.stdin.readline().rstrip().split(" "))
def getString():
return sys.stdin.readline().rstrip()
def printOutput(ans):
sys.stdout.write(str(ans) + "\n")
def solve(arr):
# min = max iff all elements in subarray are the same
# amount of subarrays increases by len of consec elemnts
total = 0
curEle = None
ln = 1
for ele in arr:
if ele == curEle:
ln += 1
else:
ln = 1
curEle = ele
total += ln
return total
def readinput():
arrLen = getInt()
arr = list(getInts())
printOutput(solve(arr))
readinput()
```
|
instruction
| 0
| 107,540
| 2
| 215,080
|
Yes
|
output
| 1
| 107,540
| 2
| 215,081
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
import sys
from functools import lru_cache, cmp_to_key
from heapq import merge, heapify, heappop, heappush
from math import *
from collections import defaultdict as dd, deque, Counter as C
from itertools import combinations as comb, permutations as perm
from bisect import bisect_left as bl, bisect_right as br, bisect
from time import perf_counter
from fractions import Fraction
import copy
import time
starttime = time.time()
mod = int(pow(10, 9) + 7)
mod2 = 998244353
# from sys import stdin
# input = stdin.readline
def data(): return sys.stdin.readline().strip()
def out(*var, end="\n"): sys.stdout.write(' '.join(map(str, var))+end)
def L(): return list(sp())
def sl(): return list(ssp())
def sp(): return map(int, data().split())
def ssp(): return map(str, data().split())
def l1d(n, val=0): return [val for i in range(n)]
def l2d(n, m, val=0): return [l1d(n, val) for j in range(m)]
try:
# sys.setrecursionlimit(int(pow(10,6)))
sys.stdin = open("input.txt", "r")
# sys.stdout = open("../output.txt", "w")
except:
pass
def pmat(A):
for ele in A:
print(ele,end="\n")
n=L()[0]
A=L()
ans=0
i=0
while(i<n):
j=i
while(j<n and A[i]==A[j]):
j+=1
ans+=(j-i)*(j-i+1)//2
i=j
print(ans)
endtime = time.time()
# print(f"Runtime of the program is {endtime - starttime}")
```
|
instruction
| 0
| 107,541
| 2
| 215,082
|
Yes
|
output
| 1
| 107,541
| 2
| 215,083
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
input()
c=a=r=0
for i in input().split():c=(a==i)*c+1;a=i;r+=c
print(r)
```
|
instruction
| 0
| 107,542
| 2
| 215,084
|
Yes
|
output
| 1
| 107,542
| 2
| 215,085
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
n=int(input())
arr=[int(x) for x in input().split()]
arr=sorted(arr)
sub_st_array=[]
cnt=0
for i in range(len(arr)):
temp=[]
for j in range(i,len(arr)):
temp=arr[i:j+1]
sub_st_array.append(temp)
for i in range(len(sub_st_array)):
if sub_st_array[i][0]==sub_st_array[i][-1]:
cnt+=1
print(cnt)
```
|
instruction
| 0
| 107,543
| 2
| 215,086
|
No
|
output
| 1
| 107,543
| 2
| 215,087
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
n=int(input())
arr = sorted([int(x) for x in input().strip().split()])
arr1=arr[0]
c=1
s=0
for ele in arr[1:]:
if arr1==ele:
c+=1
else :
s+=(c*(c-1))//2
c=1
arr1=ele
print(n+s)
```
|
instruction
| 0
| 107,544
| 2
| 215,088
|
No
|
output
| 1
| 107,544
| 2
| 215,089
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Valery is very interested in magic. Magic attracts him so much that he sees it everywhere. He explains any strange and weird phenomenon through intervention of supernatural forces. But who would have thought that even in a regular array of numbers Valera manages to see something beautiful and magical.
Valera absolutely accidentally got a piece of ancient parchment on which an array of numbers was written. He immediately thought that the numbers in this array were not random. As a result of extensive research Valera worked out a wonderful property that a magical array should have: an array is defined as magic if its minimum and maximum coincide.
He decided to share this outstanding discovery with you, but he asks you for help in return. Despite the tremendous intelligence and wit, Valera counts very badly and so you will have to complete his work. All you have to do is count the number of magical subarrays of the original array of numbers, written on the parchment. Subarray is defined as non-empty sequence of consecutive elements.
Input
The first line of the input data contains an integer n (1 ≤ n ≤ 105). The second line contains an array of original integers a1, a2, ..., an ( - 109 ≤ ai ≤ 109).
Output
Print on the single line the answer to the problem: the amount of subarrays, which are magical.
Please do not use the %lld specificator to read or write 64-bit numbers in C++. It is recommended to use cin, cout streams (you can also use the %I64d specificator).
Examples
Input
4
2 1 1 4
Output
5
Input
5
-2 -2 -2 0 1
Output
8
Note
Notes to sample tests:
Magical subarrays are shown with pairs of indices [a;b] of the beginning and the end.
In the first sample: [1;1], [2;2], [3;3], [4;4], [2;3].
In the second sample: [1;1], [2;2], [3;3], [4;4], [5;5], [1;2], [2;3], [1;3].
Submitted Solution:
```
input()
c=a=ans=0
for i in input().split():
if(a!=i): ans+=c*(c+1)/2; c=1;
else: c+=1; ans+=1;
a=i;
print(int(ans))
```
|
instruction
| 0
| 107,545
| 2
| 215,090
|
No
|
output
| 1
| 107,545
| 2
| 215,091
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are in a fantasy monster-ridden world. You are a slayer fighting against the monsters with magic spells.
The monsters have hit points for each, which represent their vitality. You can decrease their hit points by your magic spells: each spell gives certain points of damage, by which monsters lose their hit points, to either one monster or all monsters in front of you (depending on the spell). Monsters are defeated when their hit points decrease to less than or equal to zero. On the other hand, each spell may consume a certain amount of your magic power. Since your magic power is limited, you want to defeat monsters using the power as little as possible.
Write a program for this purpose.
Input
The input consists of multiple datasets. Each dataset has the following format:
N
HP1
HP2
...
HPN
M
Name1 MP1 Target1 Damage1
Name2 MP2 Target2 Damage2
...
NameM MPM TargetM DamageM
N is the number of monsters in front of you (1 ≤ N ≤ 100); HPi is the hit points of the i-th monster (1 ≤ HPi ≤ 100000); M is the number of available magic spells (1 ≤ M ≤ 100); Namej is the name of the j-th spell, consisting of up to 16 uppercase and lowercase letters; MPj is the amount of magic power consumed by the j-th spell (0 ≤ MPj ≤ 99); Targetj is either "Single" or "All", where these indicate the j-th magic gives damage just to a single monster or to all monsters respectively; Damagej is the amount of damage (per monster in case of "All") made by the j-th magic (0 ≤ Damagej ≤ 999999).
All the numbers in the input are integers. There is at least one spell that gives non-zero damage to monsters.
The last dataset is followed by a line containing one zero. This line is not a part of any dataset and should not be processed.
Output
For each dataset, Print in a line the minimum amount of magic power consumed to defeat all the monsters in the input.
Example
Input
3
8000 15000 30000
3
Flare 45 Single 8000
Meteor 62 All 6000
Ultimate 80 All 9999
0
Output
232
Submitted Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**13
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
def f(n):
h = LI()
hm = max(h)
m = I()
ms = []
ma = []
for _ in range(m):
nama,mp,target,damege = LS()
mp = int(mp)
damege = int(damege)
if damege == 0:
continue
if mp == 0:
return 0
if target == 'All':
ma.append((mp,damege))
else:
ms.append((mp,damege))
ds = [inf] * (hm+1)
ds[0] = 0
for mp, dm in ms:
for i in range(dm,hm+1):
if ds[i] > mp + ds[i-dm]:
ds[i] = mp + ds[i-dm]
t = min(ds[-dm+1:])
if ds[-1] > t + dm:
ds[-1] = t + dm
da = [inf] * (hm+1)
da[0] = 0
for mp, dm in ma:
for i in range(dm,hm+1):
if da[i] > mp + da[i-dm]:
da[i] = mp + da[i-dm]
t = min(da[-dm+1:])
if da[-1] > t + dm:
da[-1] = t + dm
for i in range(hm-1,-1,-1):
if ds[i] > ds[i+1]:
ds[i] = ds[i+1]
if da[i] > da[i+1]:
da[i] = da[i+1]
mm = r = inf
for i in range(hm,-1,-1):
if mm <= da[i]:
continue
mm = tp = da[i]
for hi in h:
if hi > i:
tp += ds[hi-i]
if r > tp:
r = tp
return r
while True:
n = I()
if n == 0:
break
rr.append(f(n))
return '\n'.join(map(str,rr))
print(main())
```
|
instruction
| 0
| 108,595
| 2
| 217,190
|
No
|
output
| 1
| 108,595
| 2
| 217,191
|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are in a fantasy monster-ridden world. You are a slayer fighting against the monsters with magic spells.
The monsters have hit points for each, which represent their vitality. You can decrease their hit points by your magic spells: each spell gives certain points of damage, by which monsters lose their hit points, to either one monster or all monsters in front of you (depending on the spell). Monsters are defeated when their hit points decrease to less than or equal to zero. On the other hand, each spell may consume a certain amount of your magic power. Since your magic power is limited, you want to defeat monsters using the power as little as possible.
Write a program for this purpose.
Input
The input consists of multiple datasets. Each dataset has the following format:
N
HP1
HP2
...
HPN
M
Name1 MP1 Target1 Damage1
Name2 MP2 Target2 Damage2
...
NameM MPM TargetM DamageM
N is the number of monsters in front of you (1 ≤ N ≤ 100); HPi is the hit points of the i-th monster (1 ≤ HPi ≤ 100000); M is the number of available magic spells (1 ≤ M ≤ 100); Namej is the name of the j-th spell, consisting of up to 16 uppercase and lowercase letters; MPj is the amount of magic power consumed by the j-th spell (0 ≤ MPj ≤ 99); Targetj is either "Single" or "All", where these indicate the j-th magic gives damage just to a single monster or to all monsters respectively; Damagej is the amount of damage (per monster in case of "All") made by the j-th magic (0 ≤ Damagej ≤ 999999).
All the numbers in the input are integers. There is at least one spell that gives non-zero damage to monsters.
The last dataset is followed by a line containing one zero. This line is not a part of any dataset and should not be processed.
Output
For each dataset, Print in a line the minimum amount of magic power consumed to defeat all the monsters in the input.
Example
Input
3
8000 15000 30000
3
Flare 45 Single 8000
Meteor 62 All 6000
Ultimate 80 All 9999
0
Output
232
Submitted Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**13
mod = 10**9+7
dd = [(-1,0),(0,1),(1,0),(0,-1)]
ddn = [(-1,0),(-1,1),(0,1),(1,1),(1,0),(1,-1),(0,-1),(-1,-1)]
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
def f(n):
h = [I() for _ in range(n)]
hm = max(h)
m = I()
ms = []
ma = []
zf = False
for _ in range(m):
nama,mp,target,damege = LS()
mp = int(mp)
damege = int(damege)
if damege == 0:
continue
if mp == 0:
zf = True
continue
if target == 'All':
ma.append((mp,damege))
else:
ms.append((mp,damege))
if zf:
return 0
ds = [inf] * (hm+1)
ds[0] = 0
for mp, dm in ms:
for i in range(dm,hm+1):
if ds[i] > mp + ds[i-dm]:
ds[i] = mp + ds[i-dm]
t = min(ds[-dm+1:])
if ds[-1] > t + dm:
ds[-1] = t + dm
da = [inf] * (hm+1)
da[0] = 0
for mp, dm in ma:
for i in range(dm,hm+1):
if da[i] > mp + da[i-dm]:
da[i] = mp + da[i-dm]
t = min(da[-dm+1:])
if da[-1] > t + dm:
da[-1] = t + dm
for i in range(hm-1,-1,-1):
if ds[i] > ds[i+1]:
ds[i] = ds[i+1]
if da[i] > da[i+1]:
da[i] = da[i+1]
mm = r = inf
for i in range(hm,-1,-1):
if mm <= da[i]:
continue
mm = tp = da[i]
for hi in h:
if hi > i:
tp += ds[hi-i]
if r > tp:
r = tp
return r
while True:
n = I()
if n == 0:
break
rr.append(f(n))
return '\n'.join(map(str,rr))
print(main())
```
|
instruction
| 0
| 108,596
| 2
| 217,192
|
No
|
output
| 1
| 108,596
| 2
| 217,193
|
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